factorizacion de polinomios
DESCRIPTION
algebraTRANSCRIPT
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FACTORIZACIN DE POLINOMIOS
Solucin (1):
Solucin (2):
Solucin (3):
Solucin (4):
Solucin (5):
Solucin (6):
factor( (xK 1) $ (xK 2) $ (xK 3) K (xK 1) $ (2K x )C 1Kx );
(x K 3 ) (x K 1 )2
factor (x4 K 5 $ x3 K 2 $ x2 C 5 $ x C 1 ) ;
(x K 1 ) (x C 1 ) (x2 K 5 x K 1 )
factor ( (x C y )3
C 3xy $ (1KxKy )K1);
(K1 C x C y ) (x2 C 2 x yC x K 3 xy C y2 C yC 1 )
factor (a2 K a $ c2 K b $ c2 C 2 $ b2
C 3 $ a $ b ) ;
(aC b ) (aC 2 bK c2 )
factor (a6 K a4 C 2 $ a3K 4 $ a2 C 1 ) ;
(a3 C a2 K 2 aK 1) (a3 K a2 C 2 aK 1)
factor (2 $ a2b2 C 2$ a2c2
C 2$ b2c2K a4K b4K c4 ) ;
K (cC aC b ) (aC cK b ) (KbK cC a ) (aC bK c )
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Solucin (7):
Solucin (8):
Solucin (9):
Solucin (10):
Solucin (11):
Solucin (12):
factor (64 $ x12y3 K 68 $ x8y7
C 4$ x4y11 ) ;
4 x4 y3 (KyC x ) (KyC 2 x ) (yC 2 x ) (yC x ) (y2
C 4 x2 ) (y2 C x2 )
factor 04 $ a2b2 K (a2 C b2 K c2 )21;
K (cC aC b ) (aC cK b ) (KbK cC a ) (aC bK c )
factor (x4 K7 $ x2 y2 C y4 ) ;
(y2 C 3 x yC x2 ) (y2 K 3 x yC x2 )
factor (x5 C xK 1 ) ;
(x2 K x C 1 ) (x3 C x2 K 1 )
factor 0 (x2C xC1)2C3x2C3xK 151 ;
(x C 2 ) (x K 1 ) (x2 C x C 7 )
factor (x4 C 6x3 C 7x2 K 6x C 1 ) ;
(x2C3 xK1)2
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Solucin (13):
Solucin (14):
Solucin (15):
Solucin (16):
Solucin (17):
Solucin (18):
Solucin (19):
factor (a $ (b2 C c2 K a2 ) C b $ (c2
C a2K b2 ) ) ;
K (aC b ) (KcC aK b ) (cC aK b )
factor (6 $ x4 K 4 $ x3 K 3 $ x2
C 15$ xK 5);
(3 x2 K 5 x C 5 ) (2 x2 C 2 x K 1 )
factor (4 $ x5 C 8 $ x4 K 25 $ x3 K 20 $ x2
C 51 $ xK 18);
(x K 1) (2 x K 1) (2 x K 3) (x C 3) (x C 2)
factor (x5 C 2x3 C xK 1 ) ;
(x2 C x C 1 ) (x3 K x2 C 2 x K 1 )
factor (x6 C 2$x5 C 3 $ x4 C 4 $ x3 C 3$x2 C 2 $ x C 1 ) ;
(xC1)2 (x2C1)2
factor (x3 C x2 K x K 1 ) ;
(x K 1 ) (x C 1 )2
factor( (xK 3) $ (xK 2) $ (xK 1) C (xK 2) $ (xK 1)C 1 K x ) ;
(x K 3 ) (x K 1 )2
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Solucin (20):
Solucin (21):
Solucin (22):
Solucin (23):
Solucin (24):
Solucin (25):
Solucin (26):
factor (a2 C 2 $ aC a$ bC bC 1);
(aC 1) (aC 1C b )
factor ((xC 1)2K (yK 2)2
);
(x K 1C y ) (x C 3K y )
factor ( (xyC 1 )2K (xC y)2 );
K (x C xy C yC 1) (x K 1K xy C y )
factor (x10 C x8 C x6 C x4 C x2 C 1 ) ;
(x2 C 1 ) (x4 K x2 C 1 ) (x2 K x C 1 ) (x2 C x C 1 )
factor (x4 K 12 $ x3 C 49 $ x2 K 78 $ x C 40 ) ;
(x K 5) (x K 1) (x K 2) (x K 4)
factor (4 $ x4 K 13 $ x2 C 9 ) ;
(x K 1) (2 x C 3) (2 x K 3) (x C 1)
factor (2$ x4K 3$ x3K 1);
(x2 K x K 1 ) (2 x2 K x C 1 )
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Solucin (28):
Solucin (29):
Solucin (30):
Solucin (31):
factor( (xK 2) $ (xC 3) $ (xC 2) $ (xK 1)C 3);
(x2 C x K 3 ) (x2 C x K 5 )
factor (2x3 K x2 K xK 3 ) ;
(2 x K 3 ) (x2 C x C 1 )
factor (x4
C 2 $ x3 K 2 $ x K 1);
(x K 1 ) (x C 1 )3
factor (22$ yC 10$ x$yC 15C 3 $ x2 C 8 $ y2 C 14$x ) ;
(x C 2 yC 3) (3 x C 4 yC 5)