dinÁmica mecanismo manivela corredera

8/19/2019 DINÁMICA MECANISMO MANIVELA CORREDERA

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UNIVERSIDAD NACIONAL AUTONOMA DE MEXICO FACULTAD DE ESTUDIOS SUPERIORES CUAUTITLAN

INGENIERIA MECÁNICA ELECTRICA

“MECANISMO DE MANIVELACORREDERA ACOPLADA COMO

HERRAMIENTA DE CORTE”

DINÁMICA DE MAQUINARIAIng. PEDRO LEYVA JIMENEZ.

PROYECTO FINAL

PRESENTAN

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DINAMICA DE MAQUINARIAMECANISMO MANIVELA CORREDERA

INDICE

- Introducción1

- Planteaiento del !ro"lea#

- O"$eti%o& '

- Dia(nó&tico

)

- De&cri!ción de la etodolo(*a+

- Pro!ue&ta de &olución1,

- Anli&i& Cinetico . Dinico1+

- Art*culo& de con&ulta#/

- Siulacione&0)

- Eleento& con&tituti%o& del ecani&o''

2a"ricación del ecani&o ')

- Conclu&ione& ),

- 3i"lio(ra4*a)0


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INTRODUCCION

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Pro!ue&ta de &olución

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aG 2! =2∗40∗(−sen (35.26 )+ cos (35.26 ) )=160∠125.26

aG2=1250∠35.26+160∠125.26=1260.19∠42.55 cm/ s2

aG 3 N =r 3∗ω32 (cosθ3+ sen θ3 )

aG3 N =6cm∗(−6.8rads )2

(cos (186.35 )+ sen (186.35 ))=81.6∠6.35

aG2! =r 3∗α 3 (−senθ3+ cosθ3 )

aG 3! =6∗115.20∗(−sen (186.35 )+ cos (186.35 ) )=1380∠−83.65

aG3=81.6∠6.35+1380∠−83.65=1382.41∠−80.26 cm/s2

aG4 N =−a α 2senθ2−aω22 cosθ2+bα 3 senθ3+bω32 cosθ3

aG 4 N =−4∗40∗sen (35.26 )−4∗252cos (35.26 )+12∗115.20∗sen (186.35 )+12∗−6.82∗cos (186.35 )

aG4 N =−1734.87∠0

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DINAMICA

Cu#&n4 #&% 86n$n0$% 4$ #&% 1$&88"n$% $n #% $%#&/n$% $n 8.

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$32=2cm∠35.26 $32 x=2cos35.26=1.63 $32 y=2 sen35.26=1.15

$23=6 cm∠186.35 $23 x=6cos186.35=−5.96 $ 23 y=6sen186.35=−.66

$43=6cm∠186.35 $43 x=6cos186.35=5.96 $ 43 y=6 sen186.35=.66

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aG2=1260.19∠42.55aG2 x=928.36aG 2 y=852.18

aG3=1382.41∠−80.26aG2 x=233.87aG 2 y=−1362.48

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" 43 x=1122.4 kg

" 43 y=1966.4 kg

" 14 y=1966.4 kg

! 12=−24.076 kg&m

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CINEMATICA

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aG 2! =r 2∗α 2 (−senθ2+ cos θ2 )

aG2! =2∗40∗(−sen (43.22 )+ cos (43.22 ) )=80∠133.22

aG2=1250∠43.22+80∠133.22=1252.55∠46.88 cm/ s2

aG3 N =r 3∗ω32 (cosθ3+ senθ3 )

aG3 N =6cm∗(−6.67 rads )2

(cos (155.51 )+ sen (155.51 ) )=40.02∠−24.49

aG 2! =r 3∗α 3 (−senθ3+ cosθ3 )

aG3! =6∗166.35∗(−sen (155.51 )+ cos (155.51 ) )=998.1∠−114.49

aG3=40.02∠−24.49+998.1∠−114.49=998.90∠−112.19cm / s2

aG4 N =−a α 2senθ2−aω22 cosθ2+bα 3 senθ3+bω32 cosθ3

aG 4 N =−4∗40∗sen (43.22 )−4∗252cos (43.22 )+12∗166.35∗sen (155.51 )+12∗−6.672∗cos (155.51

aG4 N =−618.06∠0

"a= #d∗m∗g+ma

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DINAMICA

$12=2cm∠43.22 $12 x=−1.45 $12 y=−1.36

$32=2cm∠ 43.22 $32 x=1.45 $32 y=1.36

$23=6∠155.51 $23 x=−5.46 $ 23 y=2.48

$43=6∠155.51 $43 x=5.46 $43 y=−2.48

aG2=1252.55∠46.88aG2 x=856.15aG2 y=914.26

aG3=998.90∠−112.19aG 3 x=−377.26aG3 y=−924.91

aG4=−618.06∠0aG 4 x=−618.06aG 4 y=0

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" 32 y=23.26 kg

" 43 x=13.54 kg

" 43 y=22.47 kg

" 14 y=22.47kg

! 12=−23.24 kg&m

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“Se debe localizar el Centro de Gravedad de todos los cuerpos móvilesdentro del diseño, porque la componente de la aceleración lineal decada cuerpo se calcula si actúa en ese punto. A menudo conviene modelar una forma complicada en varias formassimples interconectadas, cuyas eometr!as individuales permitancalcular con facilidad sus masas y las ubicaciones de sus CG locales.Se puede encontrar entonces el CG lobal con la suma de los primerosmomentos de estas formas simples e iualar a cero" #n modelo simple, puede ser descompuesto en partes eom$tricasf%ciles de analizar y de obtener centros de masa y CG. &

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“An%lisis cinem%tico del mecanismo. 'recuentemente, el an%lisis din%mico de cualquier maquina inicia con elan%lisis cinem%tico del, o de los, mecanismo(s) que constituyen lam%quina. *ste caso, no es la e+cepción, de manera que en esta secciónse analiza con relativa profundidad el an%lisis cinem%tico de unmecanismo de manivela biela

Corredera. ara tal -n, se obtendr%n las ecuaciones correspondientes alan%lisis de posición, velocidad y aceleración del mecanismo."

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4ectores Adicionales ara la 1ocalización de los Centros de asas de los*slabones de unecanismo de anivela 5iela Corredera.1as aceleraciones de los centros de masas de los eslabones est%n dadas por0

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