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47

Induccioacuten Electromagneacutetica Problemas de Praacutectica

Slide 2 47

Preguntas de Multiopcioacuten

Slide 3 47

1 Una circuito cuadrado de alambre se coloca en un campo magneacutetico uniforme perpendicular a las liacuteneas magneacutetica La fuerza del campo magneacutetico es de 05 T y un lado del cuadrado es de 02 m iquestCuaacutel es el flujo magneacutetico en el circuito

A 002 Wb B 004 Wb C 006 Wb D 008 Wb E 010 Wb

02 m

05 T

Slide 4 47

2 Un circuito circular de alambre se coloca en un campo magneacutetico uniforme perpendicular a las liacuteneas magneacutetica La fuerza del campo magneacutetico es B y el radio del circulo es de R iquestCuaacutel es el flujo magneacutetico en el circuito

A π BR2

B π BR2 C π BR2 D π BR2 E BR2

Slide 5 47

3 Un circuito cuadrado de alambre con un lado de 04 m es colocado en un campo magneacutetico uniforme de B=2 T La vector normal del circuito hace un aacutengulo de 60ordm con las liacuteneas del campo magneacutetico iquestCuaacutel es el flujo magneacutetico en el circuito


Slide 6 47

4 Un circuito circular se pone inicialmente en un campo magneacutetico uniforme perpendicular a las liacuteneas de campo y luego se retira raacutepidamente del campo La FEM inducida crea un flujo de carga eleacutectrica en el circuito iquestCuaacutel de las siguientes explica la fuerza en la corriente inducida por el campo original A La fuerza hace que el circuito rote por su eje

B La fuerza hace que el circuito rote por su diaacutemetro

C La fuerza hace que el circuito se acelere en la direccioacuten del campo

D La fuerza hace que el circuito acelere perpendicular a la direccioacuten del campo

E La fuerza se opone a cualquier movimiento del circuito

Slide 7 47

5 Una barra de imaacuten con el polo norte hacia abajo se mantiene por encima de un anillo de aluminio horizontal iquestCuaacutel de las siguientes acerca de la corriente inducida en el anillo es cierta (visto desde arriba) A No hay corriente en el anillo

B Hay una corriente en sentido horario en el anillo

C Hay una corriente en sentido antihorario en el anillo

D Hay una corriente alterna en el anillo

E Se requiere maacutes informacioacuten

Slide 8 47

6 Una barra de imaacuten con el polo norte hacia abajo se mantiene por encima de un anillo de aluminio horizontal iquestCuaacutel de las siguientes acerca de la corriente inducida en el anillo es cierta (Visto desde arriba)

A No hay corriente en el anillo





Slide 9 47

7 Un circuito circular de alambre se coloca en un campo magneacutetico uniforme dirigido fuera de la paacutegina De repente el campo magneacutetico desaparece iquestCuaacutel es la direccioacuten de la corriente inducida en el circuito A sentido horarioB sentido antihorario

C No hay corriente en la bobina

D dentro de la paacutegina E fuera de la paacutegina

Slide 10 47

8 Un circuito cuadrado de alambre se coloca en un campo magneacutetico uniforme dirigido dentro de la paacutegina De repente el campo magneacutetico se hace maacutes fuerte iquestCuaacutel es la direccioacuten de la corriente inducida en el circuito A sentido horario

B sentido antihorario


D dentro de la paacutegina

E fuera de la paacutegina

Slide 11 47

9 Una barra de cobre ML se mueve a una velocidad constante en un campo magneacutetico uniforme perpendicular a la las liacuteneas magneacuteticas iquestCual afirmacioacuten es verdadera acerca de la potencial eleacutectrica en la barra

A El punto M se encuentra en una mayor potencial

B El punto L se encuentra en una mayor potencial

C La potencial es mayor en el superficie de la barra

D La potencial es mayor en el centro de la barra


Slide 12 47

10 Una barra de cobre ML se mueve a una velocidad constante en un campo magneacutetico uniforme perpendicular a la las liacuteneas magneacuteticas iquestCual afirmacioacuten es verdadera acerca de la potencial eleacutectrico en la barra






Slide 13 47

11 Un circuito cuadrado de alambre con un lado de a y resistencia R se jala fuera del campo con una velocidad constante de v La fuerza del campo es B iquestCual afirmacioacuten es cierta sobre la magnitud y la direccioacuten de la corriente inducida

A BavR sentido antihorario

B BavR sentido horario

C BavR sentido antihorario

D BavR sentido horario

E BavR sentido antihorario

Magnitud Direccioacuten

Slide 14 47

12 Un circuito cuadrado de alambre con un lado de a y resistencia R se jala fuera del campo con una velocidad constante de v La fuerza del campo es B iquestCual afirmacioacuten es verdadera acerca de la magnitud y la direccioacuten de la fuerza magneacutetica sobre el circuito

A BavR en la direccioacuten del movimiento del circuito

B BavR en la direccioacuten opuesta del movimiento del circuito

C B2a2vR en la direccioacuten del movimiento del circuito

D B2a2vR en la direccioacuten opuesta del movimiento del circuito

E B2a2vR en la direccioacuten del movimiento del circuito

Slide 15 47

13 Un circuito cuadrado de alambre de aluminio se pone inicialmente perpendicular a las liacuteneas de una campo magneacutetica constante de 05 T El aacuterea encerrada por el circuito es de 02 m2 El circuito despueacutes es girado a un aacutengulo de 90deg de modo que el plano del circuito es paralelo a las liacuteneas del campo El giro demora 01 s iquestCuaacutel es la fem inducida en el circuito

A 05 VB 10 VC 15 VD 12 VE 08 V

Slide 16 47

14 Un circuito cuadrado de alambre con un lado de a y resistencia R se coloca en un campo magneacutetico uniforme de B La fuerza del campo se desvanece y resulta en una corriente inducida en el circuito iquestCuaacutel es la rapidez de cambio del campo magneacutetico

A IRa

B IRa2

C IRa2

D IRa E IaR

Slide 17 47

15 Una barra metaacutelica con extremos acostados en dos carriles paralelos se mueve a una velocidad constante v en la direccioacuten del campo magneacutetico uniforme B La FEM inducida en la barra es

A Dirigida a la izquierda de la paacutegina B Dirigida a la derecha de la paacutegina C Dirigida a la parte superior de la paacutegina D Dirigida a la parte inferior de la paacutegina E Cero

Slide 18 47

16 Un circuito de alambre se jala con una velocidad constante v hacia la derecha a traveacutes de una regioacuten de espacio donde existe un campo magneacutetico uniforme B dirigido a la paacutegina como se muestra en la figura La fuerza magneacutetica sobre el circuito es

A Dirigida a la izquierda tanto cuando entra y sale de la regioacuten

B Dirigida hacia la derecha tanto cuando entra y sale de la regioacuten

C Dirigida a la izquierda al entrar en la regioacuten y hacia la derecha al salir

D Dirigida a la derecha al entrar en la regioacuten y hacia la izquierda al salir

E cero en todo momento

Slide 19 47

17 Una barra vertical de alambre de cobre se mueve a la derecha con una velocidad constante v en la direccioacuten perpendicular a un campo magneacutetico horizontal y constante de B iquestCuaacutel de las siguientes opciones describe las cargas inducidas en los extremos del alambre

A positiva negativa B negativa positiva C negativa Cero D Cero negativa E Cero Cero

El punto M El punto L

Slide 20 47

18 Cuando el interruptor se cierra la direccioacuten de la corriente eleacutectrica es

A sentido horario sentido antihorario

B antihorario horario

C horario horario

D antihorario antihorario

E Cero Cero

Lazo 1 Lazo 2

Lazo 2

lazo 1

Slide 21 47

19 iquestCuaacutel de los siguientes procedimientos no resultara en una corriente inducida en el lazo 2

A Cerrar el interruptor

B Abrir el interruptor

CRotacioacuten del lazo 2 con respecto a su eje cuando el interruptor estaacute cerrado por un largo tiempo

DRotacioacuten del lazo 2 con respecto a su diaacutemetro cuando el interruptor estaacute cerrado por un largo tiempo

E Sacando el lazo 2 del lazo 1 cuando el interruptor estaacute cerrado por un largo tiempo

Slide 22 47

20 Una barra de imaacuten con su polo norte hacia abajo se deja caer desde una cierta altura y en su caiacuteda pasa a traveacutes de una bobina de alambre cerrado iquestCual afirmacioacuten es verdadero acerca de la aceleracioacuten del imaacuten

A Mayor que g B Menos que g C gD Aceleracioacuten es cero E Se requiere maacutes informacioacuten

Slide 23 47

Preguntas Abiertas

Slide 24 47

1 Un circuito rectangular de alambre de 05 m2 de aacuterea y de 02 Ω se coloca en una regioacuten donde el campo magneacutetico cambia como se muestra en el diagrama a continuacioacuten

a iquestCuaacutel es el flujo magneacutetico en el circuito al 04s

b iquestCuaacutel es la fem inducida por los momentos siguiente

i ____ 01s ii ____03s iii ____ 05s

c iquestCuaacutel es la corriente inducida por los tiempos siguiente

i ____ 01s ii ____03s iii _____ 05s

d En el diagrama dibuja la corriente inducida en funcioacuten del tiempo

horario

antihorario

Slide 25 47

a iquestCuaacutel es el flujo magneacutetico en el circuito al 04 s

FB = B^A

FB = (04 T)(05 m2)

FB = 02 Wb


Slide 26 47

b iquestCuaacutel es la fem inducida en los momentos siguiente

i ____ 01 s ii ____03s iii ____ 05 s

i E = - AΔBΔt = -(05 m2)(04 T)(02 s) = -1V

ii E = 0

iii E = - AΔBΔt = -(05 m2)(-04 T)(01 s) = 2V


Slide 27 47

c iquestCuaacutel es la corriente inducida en las tiempos siguientes

i ____ 01 s ii ____03 S iii _____ 05 s

i I = VR = (1 V)(02 Ω) = 5 A

ii I = 0

iii I = VR = (2 V)(02 Ω) = 10 A


Slide 28 47

10 A

-10 A

5 A

-5 A

d En el siguiente diagrama dibuja la corriente inducida en funcioacuten del tiempo

antihorario

horario


Slide 29 47

15 m

05 m

2 Un circuito rectangular de alambre de 05 m de ancho y 15 m de largo se mueve fuera de un campo magneacutetico uniforme de B=2T a una velocidad constante de 2 ms El lado izquierdo del circuito se queda dentro del campo cuando el lado derecho estaacute fuera La resistencia del circuito es de 05 Ω

a iquestCuaacutel es la direccioacuten de la corriente inducida en el circuito

b Calcula la FEM inducida en el circuito

c Calcula la corriente inducida en el circuito

d Calcula la fuerza aplicada necesaria para mover el circuito a una velocidad constante

e Calcula la potencia desarrollada por la fuerza

Slide 30 47

15 m

05 m

sentido antihorario



Slide 31 47

15 m

05 m

E = Blv

E = (2 T) (05 m) (2 ms)

E = 2 V



Slide 32 47

15 m

05 m

I = V R

I = (2 V) (05 Ω)

I = 4 A



Slide 33 47

15 m

05 m

F = BIL

F = (2 T) (4 A) (05 m)

F = 4 N



Slide 34 47

15 m

05 m

P = Fv

P = (4 N) (2 m s)

P = 8 W



Slide 35 47

3 Una barra metaacutelica tiene una longitud L y se desliza a una velocidad constante v por encima de dos carriles paralelos Los carriles estaacuten conectado a una resistencia R El aparato se colocado en un campo magneacutetico uniforme B que es perpendicular al plano por donde la barra se mueve

a iquestCuaacutel es la direccioacuten de la corriente inducida

b Determina la FEM inducida

c Determina la corriente inducida en el circuito

d Determina el campo eleacutectrico E inducida en la barra

e Determina la fuerza necesaria para mover la barra a la velocidad constante

f Determina la potencia disipada en la resistencia cuando la barra atraviesa el campo magneacutetico

Slide 36 47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47

4 Una bobina de 30 cm de diaacutemetro consiste de 20 vueltas de alambre de cobre circular que es 2mm en diaacutemetro La bobina es conectada a un galvanoacutemetro de baja resistencia Inicialmente la bobina se coloca en un campo magneacutetico uniforme perpendicular a su plano Durante el experimento el campo magneacutetico cambia de 05T a 25T en 04s Ignore la resistencia de los cables de conexioacuten (resistividad del cobre 168x10-8Ω m)

a Calcula el flujo inicial de la bobina

b Calcula la FEM inducida en el galvanoacutemetro

c Calcula la corriente inducida en la bobina

d Calcula la potencia disipada en la bobina como el campo cambia

Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47

d Calcula la potencia disipada en la bobina como cambia el campo

P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47

Preguntas de Multiopcioacuten

Slide 3 47



02 m

05 T

Slide 4 47


A π BR2


Slide 5 47



Slide 6 47






Slide 7 47






Slide 8 47







Slide 9 47




Slide 10 47






Slide 11 47







Slide 12 47







Slide 13 47








Slide 14 47







Slide 15 47


A 05 VB 10 VC 15 VD 12 VE 08 V

Slide 16 47


A IRa

B IRa2

C IRa2

D IRa E IaR

Slide 17 47



Slide 18 47







Slide 19 47




Slide 20 47




C horario horario


E Cero Cero

Lazo 1 Lazo 2

Lazo 2

lazo 1

Slide 21 47







Slide 22 47



Slide 23 47

Preguntas Abiertas

Slide 24 47




i ____ 01s ii ____03s iii ____ 05s


i ____ 01s ii ____03s iii _____ 05s


horario

antihorario

Slide 25 47


FB = B^A

FB = (04 T)(05 m2)

FB = 02 Wb


Slide 26 47


i ____ 01 s ii ____03s iii ____ 05 s

i E = - AΔBΔt = -(05 m2)(04 T)(02 s) = -1V

ii E = 0

iii E = - AΔBΔt = -(05 m2)(-04 T)(01 s) = 2V


Slide 27 47


i ____ 01 s ii ____03 S iii _____ 05 s

i I = VR = (1 V)(02 Ω) = 5 A

ii I = 0

iii I = VR = (2 V)(02 Ω) = 10 A


Slide 28 47

10 A

-10 A

5 A

-5 A


antihorario

horario


Slide 29 47

15 m

05 m







Slide 30 47

15 m

05 m

sentido antihorario



Slide 31 47

15 m

05 m

E = Blv

E = (2 T) (05 m) (2 ms)

E = 2 V



Slide 32 47

15 m

05 m

I = V R

I = (2 V) (05 Ω)

I = 4 A



Slide 33 47

15 m

05 m

F = BIL

F = (2 T) (4 A) (05 m)

F = 4 N



Slide 34 47

15 m

05 m

P = Fv

P = (4 N) (2 m s)

P = 8 W



Slide 35 47








Slide 36 47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47



02 m

05 T

Slide 4 47


A π BR2


Slide 5 47



Slide 6 47






Slide 7 47






Slide 8 47







Slide 9 47




Slide 10 47






Slide 11 47







Slide 12 47







Slide 13 47








Slide 14 47







Slide 15 47


A 05 VB 10 VC 15 VD 12 VE 08 V

Slide 16 47


A IRa

B IRa2

C IRa2

D IRa E IaR

Slide 17 47



Slide 18 47







Slide 19 47




Slide 20 47




C horario horario


E Cero Cero

Lazo 1 Lazo 2

Lazo 2

lazo 1

Slide 21 47







Slide 22 47



Slide 23 47

Preguntas Abiertas

Slide 24 47




i ____ 01s ii ____03s iii ____ 05s


i ____ 01s ii ____03s iii _____ 05s


horario

antihorario

Slide 25 47


FB = B^A

FB = (04 T)(05 m2)

FB = 02 Wb


Slide 26 47


i ____ 01 s ii ____03s iii ____ 05 s

i E = - AΔBΔt = -(05 m2)(04 T)(02 s) = -1V

ii E = 0

iii E = - AΔBΔt = -(05 m2)(-04 T)(01 s) = 2V


Slide 27 47


i ____ 01 s ii ____03 S iii _____ 05 s

i I = VR = (1 V)(02 Ω) = 5 A

ii I = 0

iii I = VR = (2 V)(02 Ω) = 10 A


Slide 28 47

10 A

-10 A

5 A

-5 A


antihorario

horario


Slide 29 47

15 m

05 m







Slide 30 47

15 m

05 m

sentido antihorario



Slide 31 47

15 m

05 m

E = Blv

E = (2 T) (05 m) (2 ms)

E = 2 V



Slide 32 47

15 m

05 m

I = V R

I = (2 V) (05 Ω)

I = 4 A



Slide 33 47

15 m

05 m

F = BIL

F = (2 T) (4 A) (05 m)

F = 4 N



Slide 34 47

15 m

05 m

P = Fv

P = (4 N) (2 m s)

P = 8 W



Slide 35 47








Slide 36 47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47


A π BR2


Slide 5 47



Slide 6 47






Slide 7 47






Slide 8 47







Slide 9 47




Slide 10 47






Slide 11 47







Slide 12 47







Slide 13 47








Slide 14 47







Slide 15 47


A 05 VB 10 VC 15 VD 12 VE 08 V

Slide 16 47


A IRa

B IRa2

C IRa2

D IRa E IaR

Slide 17 47



Slide 18 47







Slide 19 47




Slide 20 47




C horario horario


E Cero Cero

Lazo 1 Lazo 2

Lazo 2

lazo 1

Slide 21 47







Slide 22 47



Slide 23 47

Preguntas Abiertas

Slide 24 47




i ____ 01s ii ____03s iii ____ 05s


i ____ 01s ii ____03s iii _____ 05s


horario

antihorario

Slide 25 47


FB = B^A

FB = (04 T)(05 m2)

FB = 02 Wb


Slide 26 47


i ____ 01 s ii ____03s iii ____ 05 s

i E = - AΔBΔt = -(05 m2)(04 T)(02 s) = -1V

ii E = 0

iii E = - AΔBΔt = -(05 m2)(-04 T)(01 s) = 2V


Slide 27 47


i ____ 01 s ii ____03 S iii _____ 05 s

i I = VR = (1 V)(02 Ω) = 5 A

ii I = 0

iii I = VR = (2 V)(02 Ω) = 10 A


Slide 28 47

10 A

-10 A

5 A

-5 A


antihorario

horario


Slide 29 47

15 m

05 m







Slide 30 47

15 m

05 m

sentido antihorario



Slide 31 47

15 m

05 m

E = Blv

E = (2 T) (05 m) (2 ms)

E = 2 V



Slide 32 47

15 m

05 m

I = V R

I = (2 V) (05 Ω)

I = 4 A



Slide 33 47

15 m

05 m

F = BIL

F = (2 T) (4 A) (05 m)

F = 4 N



Slide 34 47

15 m

05 m

P = Fv

P = (4 N) (2 m s)

P = 8 W



Slide 35 47








Slide 36 47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47



Slide 6 47






Slide 7 47






Slide 8 47







Slide 9 47




Slide 10 47






Slide 11 47







Slide 12 47







Slide 13 47








Slide 14 47







Slide 15 47


A 05 VB 10 VC 15 VD 12 VE 08 V

Slide 16 47


A IRa

B IRa2

C IRa2

D IRa E IaR

Slide 17 47



Slide 18 47







Slide 19 47




Slide 20 47




C horario horario


E Cero Cero

Lazo 1 Lazo 2

Lazo 2

lazo 1

Slide 21 47







Slide 22 47



Slide 23 47

Preguntas Abiertas

Slide 24 47




i ____ 01s ii ____03s iii ____ 05s


i ____ 01s ii ____03s iii _____ 05s


horario

antihorario

Slide 25 47


FB = B^A

FB = (04 T)(05 m2)

FB = 02 Wb


Slide 26 47


i ____ 01 s ii ____03s iii ____ 05 s

i E = - AΔBΔt = -(05 m2)(04 T)(02 s) = -1V

ii E = 0

iii E = - AΔBΔt = -(05 m2)(-04 T)(01 s) = 2V


Slide 27 47


i ____ 01 s ii ____03 S iii _____ 05 s

i I = VR = (1 V)(02 Ω) = 5 A

ii I = 0

iii I = VR = (2 V)(02 Ω) = 10 A


Slide 28 47

10 A

-10 A

5 A

-5 A


antihorario

horario


Slide 29 47

15 m

05 m







Slide 30 47

15 m

05 m

sentido antihorario



Slide 31 47

15 m

05 m

E = Blv

E = (2 T) (05 m) (2 ms)

E = 2 V



Slide 32 47

15 m

05 m

I = V R

I = (2 V) (05 Ω)

I = 4 A



Slide 33 47

15 m

05 m

F = BIL

F = (2 T) (4 A) (05 m)

F = 4 N



Slide 34 47

15 m

05 m

P = Fv

P = (4 N) (2 m s)

P = 8 W



Slide 35 47








Slide 36 47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47






Slide 7 47






Slide 8 47







Slide 9 47




Slide 10 47






Slide 11 47







Slide 12 47







Slide 13 47








Slide 14 47







Slide 15 47


A 05 VB 10 VC 15 VD 12 VE 08 V

Slide 16 47


A IRa

B IRa2

C IRa2

D IRa E IaR

Slide 17 47



Slide 18 47







Slide 19 47




Slide 20 47




C horario horario


E Cero Cero

Lazo 1 Lazo 2

Lazo 2

lazo 1

Slide 21 47







Slide 22 47



Slide 23 47

Preguntas Abiertas

Slide 24 47




i ____ 01s ii ____03s iii ____ 05s


i ____ 01s ii ____03s iii _____ 05s


horario

antihorario

Slide 25 47


FB = B^A

FB = (04 T)(05 m2)

FB = 02 Wb


Slide 26 47


i ____ 01 s ii ____03s iii ____ 05 s

i E = - AΔBΔt = -(05 m2)(04 T)(02 s) = -1V

ii E = 0

iii E = - AΔBΔt = -(05 m2)(-04 T)(01 s) = 2V


Slide 27 47


i ____ 01 s ii ____03 S iii _____ 05 s

i I = VR = (1 V)(02 Ω) = 5 A

ii I = 0

iii I = VR = (2 V)(02 Ω) = 10 A


Slide 28 47

10 A

-10 A

5 A

-5 A


antihorario

horario


Slide 29 47

15 m

05 m







Slide 30 47

15 m

05 m

sentido antihorario



Slide 31 47

15 m

05 m

E = Blv

E = (2 T) (05 m) (2 ms)

E = 2 V



Slide 32 47

15 m

05 m

I = V R

I = (2 V) (05 Ω)

I = 4 A



Slide 33 47

15 m

05 m

F = BIL

F = (2 T) (4 A) (05 m)

F = 4 N



Slide 34 47

15 m

05 m

P = Fv

P = (4 N) (2 m s)

P = 8 W



Slide 35 47








Slide 36 47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47






Slide 8 47







Slide 9 47




Slide 10 47






Slide 11 47







Slide 12 47







Slide 13 47








Slide 14 47







Slide 15 47


A 05 VB 10 VC 15 VD 12 VE 08 V

Slide 16 47


A IRa

B IRa2

C IRa2

D IRa E IaR

Slide 17 47



Slide 18 47







Slide 19 47




Slide 20 47




C horario horario


E Cero Cero

Lazo 1 Lazo 2

Lazo 2

lazo 1

Slide 21 47







Slide 22 47



Slide 23 47

Preguntas Abiertas

Slide 24 47




i ____ 01s ii ____03s iii ____ 05s


i ____ 01s ii ____03s iii _____ 05s


horario

antihorario

Slide 25 47


FB = B^A

FB = (04 T)(05 m2)

FB = 02 Wb


Slide 26 47


i ____ 01 s ii ____03s iii ____ 05 s

i E = - AΔBΔt = -(05 m2)(04 T)(02 s) = -1V

ii E = 0

iii E = - AΔBΔt = -(05 m2)(-04 T)(01 s) = 2V


Slide 27 47


i ____ 01 s ii ____03 S iii _____ 05 s

i I = VR = (1 V)(02 Ω) = 5 A

ii I = 0

iii I = VR = (2 V)(02 Ω) = 10 A


Slide 28 47

10 A

-10 A

5 A

-5 A


antihorario

horario


Slide 29 47

15 m

05 m







Slide 30 47

15 m

05 m

sentido antihorario



Slide 31 47

15 m

05 m

E = Blv

E = (2 T) (05 m) (2 ms)

E = 2 V



Slide 32 47

15 m

05 m

I = V R

I = (2 V) (05 Ω)

I = 4 A



Slide 33 47

15 m

05 m

F = BIL

F = (2 T) (4 A) (05 m)

F = 4 N



Slide 34 47

15 m

05 m

P = Fv

P = (4 N) (2 m s)

P = 8 W



Slide 35 47








Slide 36 47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47







Slide 9 47




Slide 10 47






Slide 11 47







Slide 12 47







Slide 13 47








Slide 14 47







Slide 15 47


A 05 VB 10 VC 15 VD 12 VE 08 V

Slide 16 47


A IRa

B IRa2

C IRa2

D IRa E IaR

Slide 17 47



Slide 18 47







Slide 19 47




Slide 20 47




C horario horario


E Cero Cero

Lazo 1 Lazo 2

Lazo 2

lazo 1

Slide 21 47







Slide 22 47



Slide 23 47

Preguntas Abiertas

Slide 24 47




i ____ 01s ii ____03s iii ____ 05s


i ____ 01s ii ____03s iii _____ 05s


horario

antihorario

Slide 25 47


FB = B^A

FB = (04 T)(05 m2)

FB = 02 Wb


Slide 26 47


i ____ 01 s ii ____03s iii ____ 05 s

i E = - AΔBΔt = -(05 m2)(04 T)(02 s) = -1V

ii E = 0

iii E = - AΔBΔt = -(05 m2)(-04 T)(01 s) = 2V


Slide 27 47


i ____ 01 s ii ____03 S iii _____ 05 s

i I = VR = (1 V)(02 Ω) = 5 A

ii I = 0

iii I = VR = (2 V)(02 Ω) = 10 A


Slide 28 47

10 A

-10 A

5 A

-5 A


antihorario

horario


Slide 29 47

15 m

05 m







Slide 30 47

15 m

05 m

sentido antihorario



Slide 31 47

15 m

05 m

E = Blv

E = (2 T) (05 m) (2 ms)

E = 2 V



Slide 32 47

15 m

05 m

I = V R

I = (2 V) (05 Ω)

I = 4 A



Slide 33 47

15 m

05 m

F = BIL

F = (2 T) (4 A) (05 m)

F = 4 N



Slide 34 47

15 m

05 m

P = Fv

P = (4 N) (2 m s)

P = 8 W



Slide 35 47








Slide 36 47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47




Slide 10 47






Slide 11 47







Slide 12 47







Slide 13 47








Slide 14 47







Slide 15 47


A 05 VB 10 VC 15 VD 12 VE 08 V

Slide 16 47


A IRa

B IRa2

C IRa2

D IRa E IaR

Slide 17 47



Slide 18 47







Slide 19 47




Slide 20 47




C horario horario


E Cero Cero

Lazo 1 Lazo 2

Lazo 2

lazo 1

Slide 21 47







Slide 22 47



Slide 23 47

Preguntas Abiertas

Slide 24 47




i ____ 01s ii ____03s iii ____ 05s


i ____ 01s ii ____03s iii _____ 05s


horario

antihorario

Slide 25 47


FB = B^A

FB = (04 T)(05 m2)

FB = 02 Wb


Slide 26 47


i ____ 01 s ii ____03s iii ____ 05 s

i E = - AΔBΔt = -(05 m2)(04 T)(02 s) = -1V

ii E = 0

iii E = - AΔBΔt = -(05 m2)(-04 T)(01 s) = 2V


Slide 27 47


i ____ 01 s ii ____03 S iii _____ 05 s

i I = VR = (1 V)(02 Ω) = 5 A

ii I = 0

iii I = VR = (2 V)(02 Ω) = 10 A


Slide 28 47

10 A

-10 A

5 A

-5 A


antihorario

horario


Slide 29 47

15 m

05 m







Slide 30 47

15 m

05 m

sentido antihorario



Slide 31 47

15 m

05 m

E = Blv

E = (2 T) (05 m) (2 ms)

E = 2 V



Slide 32 47

15 m

05 m

I = V R

I = (2 V) (05 Ω)

I = 4 A



Slide 33 47

15 m

05 m

F = BIL

F = (2 T) (4 A) (05 m)

F = 4 N



Slide 34 47

15 m

05 m

P = Fv

P = (4 N) (2 m s)

P = 8 W



Slide 35 47








Slide 36 47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47






Slide 11 47







Slide 12 47







Slide 13 47








Slide 14 47







Slide 15 47


A 05 VB 10 VC 15 VD 12 VE 08 V

Slide 16 47


A IRa

B IRa2

C IRa2

D IRa E IaR

Slide 17 47



Slide 18 47







Slide 19 47




Slide 20 47




C horario horario


E Cero Cero

Lazo 1 Lazo 2

Lazo 2

lazo 1

Slide 21 47







Slide 22 47



Slide 23 47

Preguntas Abiertas

Slide 24 47




i ____ 01s ii ____03s iii ____ 05s


i ____ 01s ii ____03s iii _____ 05s


horario

antihorario

Slide 25 47


FB = B^A

FB = (04 T)(05 m2)

FB = 02 Wb


Slide 26 47


i ____ 01 s ii ____03s iii ____ 05 s

i E = - AΔBΔt = -(05 m2)(04 T)(02 s) = -1V

ii E = 0

iii E = - AΔBΔt = -(05 m2)(-04 T)(01 s) = 2V


Slide 27 47


i ____ 01 s ii ____03 S iii _____ 05 s

i I = VR = (1 V)(02 Ω) = 5 A

ii I = 0

iii I = VR = (2 V)(02 Ω) = 10 A


Slide 28 47

10 A

-10 A

5 A

-5 A


antihorario

horario


Slide 29 47

15 m

05 m







Slide 30 47

15 m

05 m

sentido antihorario



Slide 31 47

15 m

05 m

E = Blv

E = (2 T) (05 m) (2 ms)

E = 2 V



Slide 32 47

15 m

05 m

I = V R

I = (2 V) (05 Ω)

I = 4 A



Slide 33 47

15 m

05 m

F = BIL

F = (2 T) (4 A) (05 m)

F = 4 N



Slide 34 47

15 m

05 m

P = Fv

P = (4 N) (2 m s)

P = 8 W



Slide 35 47








Slide 36 47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47







Slide 12 47







Slide 13 47








Slide 14 47







Slide 15 47


A 05 VB 10 VC 15 VD 12 VE 08 V

Slide 16 47


A IRa

B IRa2

C IRa2

D IRa E IaR

Slide 17 47



Slide 18 47







Slide 19 47




Slide 20 47




C horario horario


E Cero Cero

Lazo 1 Lazo 2

Lazo 2

lazo 1

Slide 21 47







Slide 22 47



Slide 23 47

Preguntas Abiertas

Slide 24 47




i ____ 01s ii ____03s iii ____ 05s


i ____ 01s ii ____03s iii _____ 05s


horario

antihorario

Slide 25 47


FB = B^A

FB = (04 T)(05 m2)

FB = 02 Wb


Slide 26 47


i ____ 01 s ii ____03s iii ____ 05 s

i E = - AΔBΔt = -(05 m2)(04 T)(02 s) = -1V

ii E = 0

iii E = - AΔBΔt = -(05 m2)(-04 T)(01 s) = 2V


Slide 27 47


i ____ 01 s ii ____03 S iii _____ 05 s

i I = VR = (1 V)(02 Ω) = 5 A

ii I = 0

iii I = VR = (2 V)(02 Ω) = 10 A


Slide 28 47

10 A

-10 A

5 A

-5 A


antihorario

horario


Slide 29 47

15 m

05 m







Slide 30 47

15 m

05 m

sentido antihorario



Slide 31 47

15 m

05 m

E = Blv

E = (2 T) (05 m) (2 ms)

E = 2 V



Slide 32 47

15 m

05 m

I = V R

I = (2 V) (05 Ω)

I = 4 A



Slide 33 47

15 m

05 m

F = BIL

F = (2 T) (4 A) (05 m)

F = 4 N



Slide 34 47

15 m

05 m

P = Fv

P = (4 N) (2 m s)

P = 8 W



Slide 35 47








Slide 36 47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47







Slide 13 47








Slide 14 47







Slide 15 47


A 05 VB 10 VC 15 VD 12 VE 08 V

Slide 16 47


A IRa

B IRa2

C IRa2

D IRa E IaR

Slide 17 47



Slide 18 47







Slide 19 47




Slide 20 47




C horario horario


E Cero Cero

Lazo 1 Lazo 2

Lazo 2

lazo 1

Slide 21 47







Slide 22 47



Slide 23 47

Preguntas Abiertas

Slide 24 47




i ____ 01s ii ____03s iii ____ 05s


i ____ 01s ii ____03s iii _____ 05s


horario

antihorario

Slide 25 47


FB = B^A

FB = (04 T)(05 m2)

FB = 02 Wb


Slide 26 47


i ____ 01 s ii ____03s iii ____ 05 s

i E = - AΔBΔt = -(05 m2)(04 T)(02 s) = -1V

ii E = 0

iii E = - AΔBΔt = -(05 m2)(-04 T)(01 s) = 2V


Slide 27 47


i ____ 01 s ii ____03 S iii _____ 05 s

i I = VR = (1 V)(02 Ω) = 5 A

ii I = 0

iii I = VR = (2 V)(02 Ω) = 10 A


Slide 28 47

10 A

-10 A

5 A

-5 A


antihorario

horario


Slide 29 47

15 m

05 m







Slide 30 47

15 m

05 m

sentido antihorario



Slide 31 47

15 m

05 m

E = Blv

E = (2 T) (05 m) (2 ms)

E = 2 V



Slide 32 47

15 m

05 m

I = V R

I = (2 V) (05 Ω)

I = 4 A



Slide 33 47

15 m

05 m

F = BIL

F = (2 T) (4 A) (05 m)

F = 4 N



Slide 34 47

15 m

05 m

P = Fv

P = (4 N) (2 m s)

P = 8 W



Slide 35 47








Slide 36 47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47








Slide 14 47







Slide 15 47


A 05 VB 10 VC 15 VD 12 VE 08 V

Slide 16 47


A IRa

B IRa2

C IRa2

D IRa E IaR

Slide 17 47



Slide 18 47







Slide 19 47




Slide 20 47




C horario horario


E Cero Cero

Lazo 1 Lazo 2

Lazo 2

lazo 1

Slide 21 47







Slide 22 47



Slide 23 47

Preguntas Abiertas

Slide 24 47




i ____ 01s ii ____03s iii ____ 05s


i ____ 01s ii ____03s iii _____ 05s


horario

antihorario

Slide 25 47


FB = B^A

FB = (04 T)(05 m2)

FB = 02 Wb


Slide 26 47


i ____ 01 s ii ____03s iii ____ 05 s

i E = - AΔBΔt = -(05 m2)(04 T)(02 s) = -1V

ii E = 0

iii E = - AΔBΔt = -(05 m2)(-04 T)(01 s) = 2V


Slide 27 47


i ____ 01 s ii ____03 S iii _____ 05 s

i I = VR = (1 V)(02 Ω) = 5 A

ii I = 0

iii I = VR = (2 V)(02 Ω) = 10 A


Slide 28 47

10 A

-10 A

5 A

-5 A


antihorario

horario


Slide 29 47

15 m

05 m







Slide 30 47

15 m

05 m

sentido antihorario



Slide 31 47

15 m

05 m

E = Blv

E = (2 T) (05 m) (2 ms)

E = 2 V



Slide 32 47

15 m

05 m

I = V R

I = (2 V) (05 Ω)

I = 4 A



Slide 33 47

15 m

05 m

F = BIL

F = (2 T) (4 A) (05 m)

F = 4 N



Slide 34 47

15 m

05 m

P = Fv

P = (4 N) (2 m s)

P = 8 W



Slide 35 47








Slide 36 47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47







Slide 15 47


A 05 VB 10 VC 15 VD 12 VE 08 V

Slide 16 47


A IRa

B IRa2

C IRa2

D IRa E IaR

Slide 17 47



Slide 18 47







Slide 19 47




Slide 20 47




C horario horario


E Cero Cero

Lazo 1 Lazo 2

Lazo 2

lazo 1

Slide 21 47







Slide 22 47



Slide 23 47

Preguntas Abiertas

Slide 24 47




i ____ 01s ii ____03s iii ____ 05s


i ____ 01s ii ____03s iii _____ 05s


horario

antihorario

Slide 25 47


FB = B^A

FB = (04 T)(05 m2)

FB = 02 Wb


Slide 26 47


i ____ 01 s ii ____03s iii ____ 05 s

i E = - AΔBΔt = -(05 m2)(04 T)(02 s) = -1V

ii E = 0

iii E = - AΔBΔt = -(05 m2)(-04 T)(01 s) = 2V


Slide 27 47


i ____ 01 s ii ____03 S iii _____ 05 s

i I = VR = (1 V)(02 Ω) = 5 A

ii I = 0

iii I = VR = (2 V)(02 Ω) = 10 A


Slide 28 47

10 A

-10 A

5 A

-5 A


antihorario

horario


Slide 29 47

15 m

05 m







Slide 30 47

15 m

05 m

sentido antihorario



Slide 31 47

15 m

05 m

E = Blv

E = (2 T) (05 m) (2 ms)

E = 2 V



Slide 32 47

15 m

05 m

I = V R

I = (2 V) (05 Ω)

I = 4 A



Slide 33 47

15 m

05 m

F = BIL

F = (2 T) (4 A) (05 m)

F = 4 N



Slide 34 47

15 m

05 m

P = Fv

P = (4 N) (2 m s)

P = 8 W



Slide 35 47








Slide 36 47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47


A 05 VB 10 VC 15 VD 12 VE 08 V

Slide 16 47


A IRa

B IRa2

C IRa2

D IRa E IaR

Slide 17 47



Slide 18 47







Slide 19 47




Slide 20 47




C horario horario


E Cero Cero

Lazo 1 Lazo 2

Lazo 2

lazo 1

Slide 21 47







Slide 22 47



Slide 23 47

Preguntas Abiertas

Slide 24 47




i ____ 01s ii ____03s iii ____ 05s


i ____ 01s ii ____03s iii _____ 05s


horario

antihorario

Slide 25 47


FB = B^A

FB = (04 T)(05 m2)

FB = 02 Wb


Slide 26 47


i ____ 01 s ii ____03s iii ____ 05 s

i E = - AΔBΔt = -(05 m2)(04 T)(02 s) = -1V

ii E = 0

iii E = - AΔBΔt = -(05 m2)(-04 T)(01 s) = 2V


Slide 27 47


i ____ 01 s ii ____03 S iii _____ 05 s

i I = VR = (1 V)(02 Ω) = 5 A

ii I = 0

iii I = VR = (2 V)(02 Ω) = 10 A


Slide 28 47

10 A

-10 A

5 A

-5 A


antihorario

horario


Slide 29 47

15 m

05 m







Slide 30 47

15 m

05 m

sentido antihorario



Slide 31 47

15 m

05 m

E = Blv

E = (2 T) (05 m) (2 ms)

E = 2 V



Slide 32 47

15 m

05 m

I = V R

I = (2 V) (05 Ω)

I = 4 A



Slide 33 47

15 m

05 m

F = BIL

F = (2 T) (4 A) (05 m)

F = 4 N



Slide 34 47

15 m

05 m

P = Fv

P = (4 N) (2 m s)

P = 8 W



Slide 35 47








Slide 36 47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47


A IRa

B IRa2

C IRa2

D IRa E IaR

Slide 17 47



Slide 18 47







Slide 19 47




Slide 20 47




C horario horario


E Cero Cero

Lazo 1 Lazo 2

Lazo 2

lazo 1

Slide 21 47







Slide 22 47



Slide 23 47

Preguntas Abiertas

Slide 24 47




i ____ 01s ii ____03s iii ____ 05s


i ____ 01s ii ____03s iii _____ 05s


horario

antihorario

Slide 25 47


FB = B^A

FB = (04 T)(05 m2)

FB = 02 Wb


Slide 26 47


i ____ 01 s ii ____03s iii ____ 05 s

i E = - AΔBΔt = -(05 m2)(04 T)(02 s) = -1V

ii E = 0

iii E = - AΔBΔt = -(05 m2)(-04 T)(01 s) = 2V


Slide 27 47


i ____ 01 s ii ____03 S iii _____ 05 s

i I = VR = (1 V)(02 Ω) = 5 A

ii I = 0

iii I = VR = (2 V)(02 Ω) = 10 A


Slide 28 47

10 A

-10 A

5 A

-5 A


antihorario

horario


Slide 29 47

15 m

05 m







Slide 30 47

15 m

05 m

sentido antihorario



Slide 31 47

15 m

05 m

E = Blv

E = (2 T) (05 m) (2 ms)

E = 2 V



Slide 32 47

15 m

05 m

I = V R

I = (2 V) (05 Ω)

I = 4 A



Slide 33 47

15 m

05 m

F = BIL

F = (2 T) (4 A) (05 m)

F = 4 N



Slide 34 47

15 m

05 m

P = Fv

P = (4 N) (2 m s)

P = 8 W



Slide 35 47








Slide 36 47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47



Slide 18 47







Slide 19 47




Slide 20 47




C horario horario


E Cero Cero

Lazo 1 Lazo 2

Lazo 2

lazo 1

Slide 21 47







Slide 22 47



Slide 23 47

Preguntas Abiertas

Slide 24 47




i ____ 01s ii ____03s iii ____ 05s


i ____ 01s ii ____03s iii _____ 05s


horario

antihorario

Slide 25 47


FB = B^A

FB = (04 T)(05 m2)

FB = 02 Wb


Slide 26 47


i ____ 01 s ii ____03s iii ____ 05 s

i E = - AΔBΔt = -(05 m2)(04 T)(02 s) = -1V

ii E = 0

iii E = - AΔBΔt = -(05 m2)(-04 T)(01 s) = 2V


Slide 27 47


i ____ 01 s ii ____03 S iii _____ 05 s

i I = VR = (1 V)(02 Ω) = 5 A

ii I = 0

iii I = VR = (2 V)(02 Ω) = 10 A


Slide 28 47

10 A

-10 A

5 A

-5 A


antihorario

horario


Slide 29 47

15 m

05 m







Slide 30 47

15 m

05 m

sentido antihorario



Slide 31 47

15 m

05 m

E = Blv

E = (2 T) (05 m) (2 ms)

E = 2 V



Slide 32 47

15 m

05 m

I = V R

I = (2 V) (05 Ω)

I = 4 A



Slide 33 47

15 m

05 m

F = BIL

F = (2 T) (4 A) (05 m)

F = 4 N



Slide 34 47

15 m

05 m

P = Fv

P = (4 N) (2 m s)

P = 8 W



Slide 35 47








Slide 36 47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47







Slide 19 47




Slide 20 47




C horario horario


E Cero Cero

Lazo 1 Lazo 2

Lazo 2

lazo 1

Slide 21 47







Slide 22 47



Slide 23 47

Preguntas Abiertas

Slide 24 47




i ____ 01s ii ____03s iii ____ 05s


i ____ 01s ii ____03s iii _____ 05s


horario

antihorario

Slide 25 47


FB = B^A

FB = (04 T)(05 m2)

FB = 02 Wb


Slide 26 47


i ____ 01 s ii ____03s iii ____ 05 s

i E = - AΔBΔt = -(05 m2)(04 T)(02 s) = -1V

ii E = 0

iii E = - AΔBΔt = -(05 m2)(-04 T)(01 s) = 2V


Slide 27 47


i ____ 01 s ii ____03 S iii _____ 05 s

i I = VR = (1 V)(02 Ω) = 5 A

ii I = 0

iii I = VR = (2 V)(02 Ω) = 10 A


Slide 28 47

10 A

-10 A

5 A

-5 A


antihorario

horario


Slide 29 47

15 m

05 m







Slide 30 47

15 m

05 m

sentido antihorario



Slide 31 47

15 m

05 m

E = Blv

E = (2 T) (05 m) (2 ms)

E = 2 V



Slide 32 47

15 m

05 m

I = V R

I = (2 V) (05 Ω)

I = 4 A



Slide 33 47

15 m

05 m

F = BIL

F = (2 T) (4 A) (05 m)

F = 4 N



Slide 34 47

15 m

05 m

P = Fv

P = (4 N) (2 m s)

P = 8 W



Slide 35 47








Slide 36 47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47




Slide 20 47




C horario horario


E Cero Cero

Lazo 1 Lazo 2

Lazo 2

lazo 1

Slide 21 47







Slide 22 47



Slide 23 47

Preguntas Abiertas

Slide 24 47




i ____ 01s ii ____03s iii ____ 05s


i ____ 01s ii ____03s iii _____ 05s


horario

antihorario

Slide 25 47


FB = B^A

FB = (04 T)(05 m2)

FB = 02 Wb


Slide 26 47


i ____ 01 s ii ____03s iii ____ 05 s

i E = - AΔBΔt = -(05 m2)(04 T)(02 s) = -1V

ii E = 0

iii E = - AΔBΔt = -(05 m2)(-04 T)(01 s) = 2V


Slide 27 47


i ____ 01 s ii ____03 S iii _____ 05 s

i I = VR = (1 V)(02 Ω) = 5 A

ii I = 0

iii I = VR = (2 V)(02 Ω) = 10 A


Slide 28 47

10 A

-10 A

5 A

-5 A


antihorario

horario


Slide 29 47

15 m

05 m







Slide 30 47

15 m

05 m

sentido antihorario



Slide 31 47

15 m

05 m

E = Blv

E = (2 T) (05 m) (2 ms)

E = 2 V



Slide 32 47

15 m

05 m

I = V R

I = (2 V) (05 Ω)

I = 4 A



Slide 33 47

15 m

05 m

F = BIL

F = (2 T) (4 A) (05 m)

F = 4 N



Slide 34 47

15 m

05 m

P = Fv

P = (4 N) (2 m s)

P = 8 W



Slide 35 47








Slide 36 47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47




C horario horario


E Cero Cero

Lazo 1 Lazo 2

Lazo 2

lazo 1

Slide 21 47







Slide 22 47



Slide 23 47

Preguntas Abiertas

Slide 24 47




i ____ 01s ii ____03s iii ____ 05s


i ____ 01s ii ____03s iii _____ 05s


horario

antihorario

Slide 25 47


FB = B^A

FB = (04 T)(05 m2)

FB = 02 Wb


Slide 26 47


i ____ 01 s ii ____03s iii ____ 05 s

i E = - AΔBΔt = -(05 m2)(04 T)(02 s) = -1V

ii E = 0

iii E = - AΔBΔt = -(05 m2)(-04 T)(01 s) = 2V


Slide 27 47


i ____ 01 s ii ____03 S iii _____ 05 s

i I = VR = (1 V)(02 Ω) = 5 A

ii I = 0

iii I = VR = (2 V)(02 Ω) = 10 A


Slide 28 47

10 A

-10 A

5 A

-5 A


antihorario

horario


Slide 29 47

15 m

05 m







Slide 30 47

15 m

05 m

sentido antihorario



Slide 31 47

15 m

05 m

E = Blv

E = (2 T) (05 m) (2 ms)

E = 2 V



Slide 32 47

15 m

05 m

I = V R

I = (2 V) (05 Ω)

I = 4 A



Slide 33 47

15 m

05 m

F = BIL

F = (2 T) (4 A) (05 m)

F = 4 N



Slide 34 47

15 m

05 m

P = Fv

P = (4 N) (2 m s)

P = 8 W



Slide 35 47








Slide 36 47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47







Slide 22 47



Slide 23 47

Preguntas Abiertas

Slide 24 47




i ____ 01s ii ____03s iii ____ 05s


i ____ 01s ii ____03s iii _____ 05s


horario

antihorario

Slide 25 47


FB = B^A

FB = (04 T)(05 m2)

FB = 02 Wb


Slide 26 47


i ____ 01 s ii ____03s iii ____ 05 s

i E = - AΔBΔt = -(05 m2)(04 T)(02 s) = -1V

ii E = 0

iii E = - AΔBΔt = -(05 m2)(-04 T)(01 s) = 2V


Slide 27 47


i ____ 01 s ii ____03 S iii _____ 05 s

i I = VR = (1 V)(02 Ω) = 5 A

ii I = 0

iii I = VR = (2 V)(02 Ω) = 10 A


Slide 28 47

10 A

-10 A

5 A

-5 A


antihorario

horario


Slide 29 47

15 m

05 m







Slide 30 47

15 m

05 m

sentido antihorario



Slide 31 47

15 m

05 m

E = Blv

E = (2 T) (05 m) (2 ms)

E = 2 V



Slide 32 47

15 m

05 m

I = V R

I = (2 V) (05 Ω)

I = 4 A



Slide 33 47

15 m

05 m

F = BIL

F = (2 T) (4 A) (05 m)

F = 4 N



Slide 34 47

15 m

05 m

P = Fv

P = (4 N) (2 m s)

P = 8 W



Slide 35 47








Slide 36 47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47



Slide 23 47

Preguntas Abiertas

Slide 24 47




i ____ 01s ii ____03s iii ____ 05s


i ____ 01s ii ____03s iii _____ 05s


horario

antihorario

Slide 25 47


FB = B^A

FB = (04 T)(05 m2)

FB = 02 Wb


Slide 26 47


i ____ 01 s ii ____03s iii ____ 05 s

i E = - AΔBΔt = -(05 m2)(04 T)(02 s) = -1V

ii E = 0

iii E = - AΔBΔt = -(05 m2)(-04 T)(01 s) = 2V


Slide 27 47


i ____ 01 s ii ____03 S iii _____ 05 s

i I = VR = (1 V)(02 Ω) = 5 A

ii I = 0

iii I = VR = (2 V)(02 Ω) = 10 A


Slide 28 47

10 A

-10 A

5 A

-5 A


antihorario

horario


Slide 29 47

15 m

05 m







Slide 30 47

15 m

05 m

sentido antihorario



Slide 31 47

15 m

05 m

E = Blv

E = (2 T) (05 m) (2 ms)

E = 2 V



Slide 32 47

15 m

05 m

I = V R

I = (2 V) (05 Ω)

I = 4 A



Slide 33 47

15 m

05 m

F = BIL

F = (2 T) (4 A) (05 m)

F = 4 N



Slide 34 47

15 m

05 m

P = Fv

P = (4 N) (2 m s)

P = 8 W



Slide 35 47








Slide 36 47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47

Preguntas Abiertas

Slide 24 47




i ____ 01s ii ____03s iii ____ 05s


i ____ 01s ii ____03s iii _____ 05s


horario

antihorario

Slide 25 47


FB = B^A

FB = (04 T)(05 m2)

FB = 02 Wb


Slide 26 47


i ____ 01 s ii ____03s iii ____ 05 s

i E = - AΔBΔt = -(05 m2)(04 T)(02 s) = -1V

ii E = 0

iii E = - AΔBΔt = -(05 m2)(-04 T)(01 s) = 2V


Slide 27 47


i ____ 01 s ii ____03 S iii _____ 05 s

i I = VR = (1 V)(02 Ω) = 5 A

ii I = 0

iii I = VR = (2 V)(02 Ω) = 10 A


Slide 28 47

10 A

-10 A

5 A

-5 A


antihorario

horario


Slide 29 47

15 m

05 m







Slide 30 47

15 m

05 m

sentido antihorario



Slide 31 47

15 m

05 m

E = Blv

E = (2 T) (05 m) (2 ms)

E = 2 V



Slide 32 47

15 m

05 m

I = V R

I = (2 V) (05 Ω)

I = 4 A



Slide 33 47

15 m

05 m

F = BIL

F = (2 T) (4 A) (05 m)

F = 4 N



Slide 34 47

15 m

05 m

P = Fv

P = (4 N) (2 m s)

P = 8 W



Slide 35 47








Slide 36 47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47




i ____ 01s ii ____03s iii ____ 05s


i ____ 01s ii ____03s iii _____ 05s


horario

antihorario

Slide 25 47


FB = B^A

FB = (04 T)(05 m2)

FB = 02 Wb


Slide 26 47


i ____ 01 s ii ____03s iii ____ 05 s

i E = - AΔBΔt = -(05 m2)(04 T)(02 s) = -1V

ii E = 0

iii E = - AΔBΔt = -(05 m2)(-04 T)(01 s) = 2V


Slide 27 47


i ____ 01 s ii ____03 S iii _____ 05 s

i I = VR = (1 V)(02 Ω) = 5 A

ii I = 0

iii I = VR = (2 V)(02 Ω) = 10 A


Slide 28 47

10 A

-10 A

5 A

-5 A


antihorario

horario


Slide 29 47

15 m

05 m







Slide 30 47

15 m

05 m

sentido antihorario



Slide 31 47

15 m

05 m

E = Blv

E = (2 T) (05 m) (2 ms)

E = 2 V



Slide 32 47

15 m

05 m

I = V R

I = (2 V) (05 Ω)

I = 4 A



Slide 33 47

15 m

05 m

F = BIL

F = (2 T) (4 A) (05 m)

F = 4 N



Slide 34 47

15 m

05 m

P = Fv

P = (4 N) (2 m s)

P = 8 W



Slide 35 47








Slide 36 47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47


FB = B^A

FB = (04 T)(05 m2)

FB = 02 Wb


Slide 26 47


i ____ 01 s ii ____03s iii ____ 05 s

i E = - AΔBΔt = -(05 m2)(04 T)(02 s) = -1V

ii E = 0

iii E = - AΔBΔt = -(05 m2)(-04 T)(01 s) = 2V


Slide 27 47


i ____ 01 s ii ____03 S iii _____ 05 s

i I = VR = (1 V)(02 Ω) = 5 A

ii I = 0

iii I = VR = (2 V)(02 Ω) = 10 A


Slide 28 47

10 A

-10 A

5 A

-5 A


antihorario

horario


Slide 29 47

15 m

05 m







Slide 30 47

15 m

05 m

sentido antihorario



Slide 31 47

15 m

05 m

E = Blv

E = (2 T) (05 m) (2 ms)

E = 2 V



Slide 32 47

15 m

05 m

I = V R

I = (2 V) (05 Ω)

I = 4 A



Slide 33 47

15 m

05 m

F = BIL

F = (2 T) (4 A) (05 m)

F = 4 N



Slide 34 47

15 m

05 m

P = Fv

P = (4 N) (2 m s)

P = 8 W



Slide 35 47








Slide 36 47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47


i ____ 01 s ii ____03s iii ____ 05 s

i E = - AΔBΔt = -(05 m2)(04 T)(02 s) = -1V

ii E = 0

iii E = - AΔBΔt = -(05 m2)(-04 T)(01 s) = 2V


Slide 27 47


i ____ 01 s ii ____03 S iii _____ 05 s

i I = VR = (1 V)(02 Ω) = 5 A

ii I = 0

iii I = VR = (2 V)(02 Ω) = 10 A


Slide 28 47

10 A

-10 A

5 A

-5 A


antihorario

horario


Slide 29 47

15 m

05 m







Slide 30 47

15 m

05 m

sentido antihorario



Slide 31 47

15 m

05 m

E = Blv

E = (2 T) (05 m) (2 ms)

E = 2 V



Slide 32 47

15 m

05 m

I = V R

I = (2 V) (05 Ω)

I = 4 A



Slide 33 47

15 m

05 m

F = BIL

F = (2 T) (4 A) (05 m)

F = 4 N



Slide 34 47

15 m

05 m

P = Fv

P = (4 N) (2 m s)

P = 8 W



Slide 35 47








Slide 36 47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47


i ____ 01 s ii ____03 S iii _____ 05 s

i I = VR = (1 V)(02 Ω) = 5 A

ii I = 0

iii I = VR = (2 V)(02 Ω) = 10 A


Slide 28 47

10 A

-10 A

5 A

-5 A


antihorario

horario


Slide 29 47

15 m

05 m







Slide 30 47

15 m

05 m

sentido antihorario



Slide 31 47

15 m

05 m

E = Blv

E = (2 T) (05 m) (2 ms)

E = 2 V



Slide 32 47

15 m

05 m

I = V R

I = (2 V) (05 Ω)

I = 4 A



Slide 33 47

15 m

05 m

F = BIL

F = (2 T) (4 A) (05 m)

F = 4 N



Slide 34 47

15 m

05 m

P = Fv

P = (4 N) (2 m s)

P = 8 W



Slide 35 47








Slide 36 47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47

10 A

-10 A

5 A

-5 A


antihorario

horario


Slide 29 47

15 m

05 m







Slide 30 47

15 m

05 m

sentido antihorario



Slide 31 47

15 m

05 m

E = Blv

E = (2 T) (05 m) (2 ms)

E = 2 V



Slide 32 47

15 m

05 m

I = V R

I = (2 V) (05 Ω)

I = 4 A



Slide 33 47

15 m

05 m

F = BIL

F = (2 T) (4 A) (05 m)

F = 4 N



Slide 34 47

15 m

05 m

P = Fv

P = (4 N) (2 m s)

P = 8 W



Slide 35 47








Slide 36 47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47

15 m

05 m







Slide 30 47

15 m

05 m

sentido antihorario



Slide 31 47

15 m

05 m

E = Blv

E = (2 T) (05 m) (2 ms)

E = 2 V



Slide 32 47

15 m

05 m

I = V R

I = (2 V) (05 Ω)

I = 4 A



Slide 33 47

15 m

05 m

F = BIL

F = (2 T) (4 A) (05 m)

F = 4 N



Slide 34 47

15 m

05 m

P = Fv

P = (4 N) (2 m s)

P = 8 W



Slide 35 47








Slide 36 47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47

15 m

05 m

sentido antihorario



Slide 31 47

15 m

05 m

E = Blv

E = (2 T) (05 m) (2 ms)

E = 2 V



Slide 32 47

15 m

05 m

I = V R

I = (2 V) (05 Ω)

I = 4 A



Slide 33 47

15 m

05 m

F = BIL

F = (2 T) (4 A) (05 m)

F = 4 N



Slide 34 47

15 m

05 m

P = Fv

P = (4 N) (2 m s)

P = 8 W



Slide 35 47








Slide 36 47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47

15 m

05 m

E = Blv

E = (2 T) (05 m) (2 ms)

E = 2 V



Slide 32 47

15 m

05 m

I = V R

I = (2 V) (05 Ω)

I = 4 A



Slide 33 47

15 m

05 m

F = BIL

F = (2 T) (4 A) (05 m)

F = 4 N



Slide 34 47

15 m

05 m

P = Fv

P = (4 N) (2 m s)

P = 8 W



Slide 35 47








Slide 36 47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47

15 m

05 m

I = V R

I = (2 V) (05 Ω)

I = 4 A



Slide 33 47

15 m

05 m

F = BIL

F = (2 T) (4 A) (05 m)

F = 4 N



Slide 34 47

15 m

05 m

P = Fv

P = (4 N) (2 m s)

P = 8 W



Slide 35 47








Slide 36 47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47

15 m

05 m

F = BIL

F = (2 T) (4 A) (05 m)

F = 4 N



Slide 34 47

15 m

05 m

P = Fv

P = (4 N) (2 m s)

P = 8 W



Slide 35 47








Slide 36 47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47

15 m

05 m

P = Fv

P = (4 N) (2 m s)

P = 8 W



Slide 35 47








Slide 36 47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47








Slide 36 47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47

En sentido horario



Slide 37 47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47

E = Blv = BLv



Slide 38 47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47

I = E R = Blv R



Slide 39 47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47

E = V d

E = Blv L

E = Bv



Slide 40 47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47

F = BIL

F = B (BLv R) (L)

F = B2L2vR



Slide 41 47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47

P = Fv

P = (B 2L2v R) v

P = B 2L2v2 R



Slide 42 47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47






Slide 43 47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47


F = nB^A

F = (20) (05 T) (π) (015 m) 2

F = 071 Wb


Slide 44 47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47


E= -NΔFΔt

E= -NAΔB (04 s)

E= -NA(25T-05T)(04s)

E = -(20)(π)(015m)2(25T-05T)(04s) = -707V


Slide 45 47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47


I = V R

I = (707 V) (01008 Ω)

I = 0713 A

R = pLA

R = p (2 r)(20) ( r2)

R = (168x10 -8 m ) (1885m) (π) (0001 m) 2

R = 01008


Slide 46 47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

47


P = IV

P = (0713 A) (707 V)

P = 504 W


Slide 47 47

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