Universidad Tcnica De ManabFacultad De Ciencias bsicasMtodo numericoTema: deber matriz inversaIntegrantes:Andrs Ormaza alacios!ivel: "to ##$##>> A=[1 2 3; 2 2 3; 1 4 4];>> B=[6;7;9];>> AB=[A B]AB = 1 2 3 6 2 2 3 7 1 4 4 9>> rank(A)ans = 3>> rank(AB)ans = 3>> inv(A)*Bans =1.00001.00001.0000>> A\Bans = 1 1 1>> det(A)ans = 4>> A=[1 1 1; 2 1 3; 3 1 6];>> B=[4;7;2];>> AB=[A B]AB = 1 1 1 4 2 1 3 7 3 1 6 2>> rank(A)ans = 3>> rank(AB)ans = 3>> inv(A)*Bans = 19.0000 7.0000 !.0000>> A\Bans = 19.0000 7.0000 !.0000>> det(A)ans =1