Determine los valores de las intensidades de corriente que circulan por cada lazo, para cada uno de los siguientes

circuitos:

Solución:

V= I*R

10v = I1 * 5 ohm + I1 * 3 ohm – I2 * 5 ohm

6v = I2 * 3 ohm + I2 * 5 ohm – I2 * 6 ohm - I1 * 3 ohm

10v = I1 * (5 ohm + 3 ohm) – I2 * 3 ohm

6v = I2 * (5 ohm + 3 ohm + 6ohm) – I1 3 ohm

10v = I1 8 ohm – I2 3 ohm (3) 10v = I1 8 – I2 3

6v = I2 14ohm – I1 3 ohm (8) 6v = I1 3 – I2 14

30v = I1 24 – I2 9

48v = I1 24 – I2 112

78v = I2 103ohm

78 = I2 I2= 0.75 A

103 I2= 750 mA

10v = I1 8 ohm – I2 0,75 ohm(3)

6v = I1 8ohm – 2.25v

12.25 = I1 8ohm

12.25 = I1 I1 = 0.28

8 I1= 280 mA

V= I*R

12v = -I1 * 6 ohm + I1 * 2 ohm – I1 * 3 ohm + 10v + I1 * 5 ohm – I2 - 3 ohm

10v = -I2 * 3 ohm +6v + I2 * 6 ohm + I2 * 5 ohm – I1 - 3 ohm

12v = -I1(6 ohm + 2 ohm + 3 ohm + 5 ohm) + 10 v - I2 - 3 ohm

10v = -I2(3 ohm + 6 ohm + 5 ohm )+ 6v – I1 - 3 ohm

12v = -I1( 16 ohm) + 10 v - I2 - 3 ohm

10v = -I2(14ohm)+ 6v – I1 - 3 ohm

12v-10v = -I1 ( 16 ohm) - I2 - 3 ohm (3)2v= I1( 16 ohm) - I2 – (3 ohm )

10v -6v = -I2 (14ohm) – I1 - 3 ohm (16)4v= - I1( 3 ohm) +I2 – (14 ohm)

6v= I1( 48ohm) - I2 – (9 ohm )

64v= -I1( 48ohm) + I2 –(124 ohm )

70v= -I2(115ohm)

70v = -I2 = 0.60 A

115v

2v= I1( 16 ohm) -0.60 – (3 ohm )

2v= I1( 16ohm) - 1.8 ohm

2v + 1.8v= I1 (16 ohm)

3.8V= I1 (16 ohm)

3.8v = I1 = 0.23 A

16ohm