intrusion de agua 2

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    Periodo Pseudo

    Permanente

    Pd(td)= 1j2(lnreD+0 ,80907) Pd(td)=(2jreD" 2)*tD+In reD-3j4

    Pd(tD)=lj2tD Pd(tD)=2jreD"2

    tDa=O,l

    5.- Determinar el influjo de agua con la siguiente ec:

    _ U~(tD)-We(tDj_l)P~(tDj) ( )We(t Dj) - We(t Dj -1) + . If Dj -t Dj-l

    P D(t Dj) - t Dj-l P D (t Dj )

    Modelo Pseudo Permanente de Lang. (PSS) ~We = c / Wi (Pan - P an+\)

    =_ W cfP a(t)

    q c / i dt

    J A ka=--=----

    c/Wi c,Wi j.16oo

    Calculo de la presion medio esquema UBP.

    - = (p _ )e-atli + Pn+\ - P" ( -af),/-1)Pan+\ Pn+\ an Pn aM e

    Calculo de la presion medio esquema SIBP.

    - _ - - af),/+ Pn + Pn+l (1- -af),/)Pan+\ - Pane 2 e

    1:- Primeramente determinamos la c1ase de variacion si es lineal 0 diferencial

    Si reD< 0.5 Utilizamos la variacion Lineal metoda LIBP

    >0.5 Utilizamos la variacion Gradual metodo SIBP

    En nuestro caso Utilizamos el radio de drenaje adimensional determinado en la tabla 8

    para acufferos radiales Leung para un radio de drene reD = 2.8 tenemos un valor de 0.

    de SIBP que es mayor aiD,S

    2.-Calculamosa a= (ry/ro2) * ; _ 0.4381~ =0.1175

    (6/ro) x reD -1 0,54* 2.8 -1

    Fecha detiempo

    Presion

    inicio Prom. tD ~t (tpSS)D

    alios Psia

    Sep-89 0,00 3952 0,00 0,00 1,979

    Jul-91 1,83 3854 0,97 1,78 1,979

    Ago-94 4,92 3839 2,61 12,83 1,979Nov 95 6 17 3713 3 27 20 19 1 979

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    e-Qdt e-QM-l

    e-Qdt_l-e-QM

    l/aAt(Pn+Pn+1 )/2 Pmpd a P

    l,OOE+OO O,OOE+OO #iDIVjO! 3952 O,OOE+OO 3952

    -8,27E-35 1,00E+00 -1,27E-02 3903 1,00E+00 3903

    -2,60E-92 1,00E+00 -4,74E-03 3847 1,00E+00 3847

    -l,26E-115 l,OOE+OO -3,78E-03 3776 l,OOE+OO 3776

    -1,87E-154 l,OOE+OO -2,83E-03 3653 l,OOE+OO 3653

    -l,51E-171 1,00E+00 -2,54E-03 3573 1,00E+00 3573

    -l,78E-185 l,OOE+OO -2,35E-03 3481 1,00E+00 3481

    -2,24E-210 l,OOE+OO -2,07E-03 3344 l,OOE+OO 3344

    ti*Wi We n+l L'lWe(Mbls)

    15203 0 0

    15203 745 745

    15203 1604 859

    15203 2676 1817

    15203 4553 2737

    15203 5762 3025

    15203 7161 4135

    15203 9244 5108

    4.- Calculamos el tiempo adimensional to Can la siguiente formula para cada etapa d

    presion

    2.309kttD = B * 2 L'lt= to * tp tpss = 0.25*Re02

    uWc(rwacuj

    Can este metoda tenemos un volumen de entrada de agua de 9.244 MMBbls

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    1.- Primeramente ealeulamos de la tabla 8.5 de 105 parametros del modelo

    MPSS modifieado por LANG

    5", / rg = In reD -0.75 = LN(2.8)-0.75 = 0.284

    Si reo >20 se toma un valor eonstante de 0.9855 si es menor se utiliza la ec:

    /3/ = in re D *0.0465 + 0.845 = In(2.8) *0.0465 + 0.845 = 0.893

    EI at podemos leer de la tabla 8.4 de 105 parametros del modele modifieado 0 podemos

    ealeular con la siguiente relacion

    at = 5.4156* reD-1.6506= 5.4156*2.8-1.6506= 0.98

    Wi = Jrx(r} -r:)xhx =2.851e+9

    a= C ''7 /ro2)* 2 = 0.43816 =0.2255

    (5/ro)xreD2 -1 0,284*2.82-1

    Fecha detiempo

    Presion

    inicio Prom. to L'.t (tpss)o

    Aiios Psia

    Sep-89 0,00 3952 0,00 0,00 1,97~

    Jul-91 1,83 3854 0,97 1,78 1,979

    Ago-94 4,92 3839 2,61 12,83 1,979

    Nov-95 6,17 3713 3,27 20,19 1,979

    Die-97 8,25 3592 4,38 36,15 1,979

    Nov-98 9,17 3554 4,87 44,63 1,979

    Ago-99 9,92 3408 5,26 52,21 1,979

    Die-OO 11,26 3280 5,97 67,23 1,979

    e-Q4t e-Q4t_le-Q4t_

    Pmpss al_e-Q4t r

    l/aAton+1 ti*Wi

    0 0 0 3952 OOE+OO 15203-

    2.5ge-65 1,00E+00 -1.00 3898 1,00E+00 15203-

    2.81e-174 1,00E+00 -1.00 3846 1,00E+00 15203-

    1.83e-218 1,00E+00 -1.00 3769 1,00E+00 15203

    -4.8e-292 1,00E+00 -1.00 3646 1,00E+00 15203

    -0 1,00E+00 -1.00 3571 1,00E+00 15203

    -0 1,00E+00 -1.00 3473 1,00E+00 15203

    -0 l OOE+OO -1 00 3337 1 00E+00 15203

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    We n+l ~We(Mbls)

    a a824 824

    1616 791

    2778 19864651 2665

    5792 3127

    7279 4151

    9347 5196

    En las secciones anteriores fueron presentados varios model os para el calculo de la

    entrada de agua acumulada proveniente de 105 acufferos. Cada uno de 105 modelos fue

    utilizado para estimar el influjo acumulado del acuffero circular limitado. Para cada unode 105 modelos, se calculo en base al tiempo, el influjo acumulado del acuffero sujeto a

    un historial de presion variable en el contacto. Los resultados estan presentados en la

    tabla 8.11.

    15,06

    9,24

    9,35

    8,65

    7,28

    Tabla 8.11 - Comparaci6n entre /05 varios mode/os de influjo de aqua

    Como se pude observar el metodo de Fetkovich es el mas optimista para nuestros

    alculos y 105 metod os mas recomendable son: Van Everdinger, PSS y MPSS de Leung

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    IIdJus I

    Conned

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    1Q..!Y'

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    - 1 G.\(9: / O c .Q ,C\{+GIe \ YI we. +ev)'ftA. - V,;sweeden is not contaminated by acid rain

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    co. tCI1 -~ 0+10 /Z{~:rI

    l;)ei t; !A -V f - ~ Jl fV1 C CL

    b./\r;t e;7 ----~ U-1': Gi5

    ~ alSD --:J ~ a )~ b '~ u \Sa .- l\ . .: : : : = y \lG..-Llck\i'

    bor 1 "" 1 ---, : . V'\"t cCr

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    -hop\ca\

    A NIM A L .S IN D A NG E R

    ,,{' \?o..\'{q l"'OII

    Many g!JimoJ$are in danger of

    ex:tiQ.cticJDbecause we are

    destroying the rainforests,~---

    The -Lavclnrhinoceros one lived

    in the rainforests of many

    countries: in the north of India,

    through ~0do-China and ~u.:tb

    tbrougb Malaysia and the [slands

    of Indonesia. But today there are

    only about one thousand of these

    animals in the world, some living

    in Vietnam and some living in the

    Ujung Kulon NationaLforest Parkon the island of Java , where forest

    workers protect them.

    Today, there are many forest

    park in the rainforests of the

    world. Animals need(~e parks"

    because some ~p-e~l~$.have to travel

    many B i J ( ) . !11~ lr _ ? S _ to find food. The

    Par'~ Nationaldes ~I}~ in

    Rwanda, for e > 5 .q j'n p - J ~ , protects the

    mountain gorilla and saves it from~---extinction.

    Some animals are in dangerJl.l 'Y \\C''_ 1c:iu f)

    be~2H.~e P i ~ ~ p L ~ " w 9 [ ; 1 lt~(% ~f'scR~~'V,.i~{'C:ia.there are only 2,500 hyacinth -

    m(lcaw~ now living in the forest of

    LmLn A~~:_But in 1989, people

    caught 500 hyacinth maca~s and

    sold them in pe!:~~9Fs~,

    (~) When you vjsit a pet shop, ask

    about the animals there. D,id

    somebody catch any of them in the

    rainforests, put them into boxes,

    and fly them to the pet shop)

    Zoos in many countries of the----

    VJorldare helping to p-rotect ..

    animals in danger. The golden lion

    tamarin comes from f?r:'.aziJ's.fol'est

    near the sea.

    ( G The forest there is'-'

    disappearing fast and people

    caught hundreds of these tamar ins

    and sold them in pet shops. There

    were only a few left in the

    rainforest. But many golden lion

    tamarins were born in zoos, and

    scientists have taken some of them

    back to the Poco das Antas forest

    Park near Rio..9s.janeiro.

    /~ f ) Animals born in zoos know'-' nothing a_~out)life in the

    rainforest. Someone must tea~h

    thetn how to find food Q n d keep

    away from danger. Janis Cartel'

    teaches chjmpanzees about life in

    the rainforest of the Gambia

    because they were born in zoos:aIJ'away from forest. In Borneo,

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    va CA8ULARY

    grea-:- : grcn -, hurt : donar

    bu rn : qu emar - coal : carbon

    fog neblina - snow : nieve

    dead : muerto - stone p ledr o

    smoke : humo - lake logo'

    aw ley - but pero

    - dangerous : peligroso

    - because o T , : debido 0

    - oil : petroleo, oceite

    - fuel : combustible

    - Do!lution : contaminacionI

    ENGLISH

    - [)i- ,

    4 Acid rain'liuv iG . Ac i'-- :-

    \ .I ..

    0t.:lc.l rJln IS:l ~re:1[ Qroblc:m in m: lnl'

    counrrie s i n rh e \.'lorrh', ,vbnr foods

    :.!n~cirinks - ,=-:ln~_s, for c::'(~mpic: _ I

    coni :ciln :Jc ic :> hur che:~do ao r hurr

    ~lnybod~'. Qrdinaq/.r;J.in is J ij,,!e

    J~ici, roo)Bt.:r srr on g a cid is

    (J;:lngerous. elf bacj:eries

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    ~-. . .

    1. Why are animals in danger? ')

    " 'J'

    3. What do animals need t olive bf~Her? ;:,l . .,.L .:, I. !. _,;:,

    4. Which are the palces that prntf.:cttfw "nirn;;\l'>,'

    5. Where do golden lion tam;:1rins live novi? -

    6. Where can you buy macaws?-V Y nJ J z..{ ,1.'1).0-,-, I ' .,_. ,,] .C I (.!

    1- i J

    pet shops/-- -------- ~

    destroying

    - - _ . _ - _ ...._- - ---------

    M . I . d r . ~ . . b I ;- J - 1 '\ h . fany anima s are III -----.- ---------------- 01extlllctlOn ecause peop e are -- -.~-....------.-----. t e ram orest ..l

    \ .today there are about one thousand of J;:lVan Hhinoceros in the . 1 ). ./ :: - : : . . - - - - - - some are protected by

    forests workers. There are many _~sJ( - inthe rainforests of the world .. Then; many animals --~~~22J

    r nf ..'. t'I' .. .large park.sto find food. Today there ar~ 2500 --- -----------.:. -~------..:-------- liVing In the forests.

    I -

    Zoos help to _n ~-dlC the animals in danger; in the forest people catch them and selll them in --,--:~-::

    _________J _

    But there are animals that don't know about ------------- ...----------- in the forests and somebody teach thei

    Animals need plenty of space to grow in

    In Latin America p~ople can sell animals in pet shops

    The people that visit the zoos can feed the animals

    In Rio de Janeiro there are many forest parks

    Some people teach animal ~how to live in the forests

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