examen de ing, sanitaria

8/17/2019 Examen de Ing, Sanitaria

1/18

PROBLEMA 1

Captacion Estacion Reservorio Red de Distri

Bombeo

rio

Datos : Poblacion = 76000

Dotación = 250 l/hab/dia

K1 = 1.3

k2 1.8

Horas o!b"o #$% = 16

&ist"!a b% : 'na r"(r"s"a ali!"nta (or )ra*"dad a +na (lanta (otabili,adora. -a(lanta ali!"nta (or )ra*"dad al r"s"r*orio "l"*ado "l

planta Estacion Reservorio Red de Distri

Bombeo

represa

Datos : Poblacion = 76000Dotación = 250 l/hab/dia

K1 = 1.3

k2 1.8


&ist"!a c% : a(atación (or )ra*"dad d" +n rio +" ali!"nta (or )ra*"dad a +n r"s"r*orio "l"*ado "l c+al abast"c" tanbi"n (or )ra*"d


2/18

captacion reservorio red de distribucion

rio


Dotación = 250 l/hab/dia

K1 = 1.3

k2 1.8


&ist"!a d% : 'n (o,o ali!"nta a +n r"s"r*orio "l"*ado. l r"s"r*orio ali!anta (or )ra*"dad a la (oblacion.

estacion de bombeo reservorio red de distribucion

rio


Dotación = 250 l/hab/diaK1 = 1.3

k2 1.8



3/18

ondicion b !d

4"s+ltados :

o!(on"nt" a+dal"s d" dis"o "n l/s

a b c d

+"nt" &+("ricial &+("ricial &+("ricial &+bt"rran"a

a(tacion !d 285.88 !d 285.88 !d 285.88 b 28.82

ond+ccion !d 285.88 !d 285.88 !d 285.88 !d 0.00

9d+ccion !h 35.83 !h 35.83 !h 35.83 !h 35.83

;!(+lsion b 285.88 b 0.00 b 0.00 b 28.82

4"d d" Distrib !h 35.83 !h 35.83 !h 35.83 !h 35.83

PROBLEMA 3

-a c+r*a d" *ariacion"s horarias d" +na localidad s" han int")rado s")


4/18

18 3.!

24 40

a% &" +i"r" sab"r "l *ol+!"n d" r")+lacion. D"tallar c>lc+lo

?ol+!"n d" 4")+lacion s+!a d"l !a@i!o d"icit "l !a@i!o sobrant"

Aa@i!o d"icit = 27.20 B 23.10 = .1

Aa@i!o &obrant" = 13.0 B 10.50 = 3.

?ol+!"n d" r")+lacion = 7.5 @ 100 !3

Volumen de regulacion = 750 m3

0 2 4 8 10 12 14 1 18 20 22 24

1

3.90

23.1

0

27.20

10.50


5/18

b% +" cantidad d" a)+a ha "n "l r"s"r*orio a la hora 0

% C+stiicar r"s(+"sta a la (r")+nta b%

PROBLEMA 4

9bsisa 4asant" la*" -on)it+d #!%

0.00 8.86 8.6200.00 .00 3.0 200.06

00.00 2.00 1.0 200.01

600.00 87.00 86.20 200.06

750.00 86.00 85.0 150.00

00.00 80.00 7.00 150.12

1000.00 78.00 77.20 100.02

1200.00 6.00 68.20 200.20

1300.00 65.00 6.20 100.80

100.00 6.00 63.20 100.00

1600.00 62.00 61.0 200.01

1800.00 63.00 62.0 200.00

2000.00 63.50 62.0 200.00

2200.00 6.00 63.0 200.00

otal 2201.28

o!o "l cons+!o a la hora 0 a las :00 "s d" 320 !3

hasta las :00 (! +" co!i"n,a la hora d" bo!b"o.


6/18

!d = 30

o"ici"nt" d" Ha,"n B Eillia!s = 150

ota ondo a!ara d" ar)a d" P9P 8.67

ota d" D"scar)a d" 4"s"r*orio = 6

Distancia "ntr" P9P B 4"s"r*orio = 200.00

49AF 1 B 2

ar)a Dis(onibl" :

6.00 G h 9 B 4 8.67

h G 4 4I

9nali,a!os "l di>!"tro +" ("r!ita c+!(lir con lJ!it" d" *"locidad:

1.7 @ 30 2.5

D 4I P+l)adasL s"l"cciona!os D = 6 P+l)adas

9nali,a!os "l di>!"tro +" ("r!ita +tili,ar la car)a hidr>+lica dis(onibl".

171 @ 2201.28 30 3.5

150

D 5.8 P+l)adasL s"l"cciona!os D = 6 P+l)adas

ntonc"s "l Dia!"tro : D = 6 P+l)adas

PROBLEMA 5

D2

D.87

" #1741 $4.87 %$1.8!_ / (/

1.8!


7/18

? = M 1%. = 2

= M

= 2 l/s =

= 1.3Consumo

l ca+dal !a@i!o d" contrib+ción "s i)+al a :

= 1.8

=

P"riodo d" r"t"ncion !ini!o

P"riodo d" r"t"ncion !a@i!o

2.%D" la "c+acion :

Fbt"n"!os las raic"s :

?"riica!os +" la rai, d"b" s"r !aor a c"ro.

4""!(la,a!os *alor"s d" K = 1.8 a = 3

!c

!c

!in c

(

K1

K2

!a@c

K!inc

k1

2 #kBa% G k #aBk2% G k#

9@2 G @ G

&i b2 B ac

#a B k2% 2 B #kBa% N k N#kB1% #

&


8/18

10.5081

3%

4""!(la,ando

1.51

0.30

+or lo tanto ,

= 13.33

#3 B 1.82%2 B #1.8 B 3% #1.8% #1.8B1%#1G3%

#3 B 1.82%2

4"sol*i"ndo la "c+acion d" s")+ndo )rado #2% (ara hallar k1

!in c

&1#-−' ( $2) %%*( 4 2

&1$#-)-)0.24%/(-〖 -)0.24%〗$2)4-)1.23.2%%%*-2-)1.20%%

&1$#

&1$#

&1$#-)-)0.24%)(-〖 -)0.24%〗$2)4-)1.23.2%%%*-2-)1.20%%


9/18

= 2

=

Reemplaando el volumen de la camara de bombeo va acer iual a ,

eun la ecuacion

? = t K #K1B1%

#K1GKB1%

? =

? = 3.30

? = .00

!c

b

&1$ #


10/18

ucion

= 219.91

= 28!.88

= 39!.83

+al ali!"nta (or )ra*"dad a la (oblacion.

ucion

= 21.1

= 285.88

= 35.83

ad a la (oblacion


11/18

= 21.1

= 285.88

= 35.83

= 21.1

= 285.88

= 35.83

= 28.82


12/18


13/18

2


14/18


15/18


16/18

l/s

= 2 = 13.33 l/s

1.8

"ntonc"s K = = 2.00 = 1.80

13.33

K = 1.80

= t = 10 !in

a =

= 30 !in

!a@c

!inc

Pr !in

Pr !a@ t1 =

B1%#1Ba% =

0

1Ga% 0

1#(' ( $2) %%*( 4 2


17/18

#1.8 B 3% #1.8% #1.8B1%#1G3% =0

10.3702232

a = #1.8 B 3% = 1.80

B3.2

c = #0.8%#% = 0.80050113

l/s

b = #3B1.82% =


18/18

l/s

1.5 @ 13.33 = .00 l/s

10O @ 60O @ 13.33 @ 1.8 @ #1.5 B 1%

#1.5 G 1.80 B 1%

l/s

!3

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