Act.3B Jaqueline J. Lugo.

AP47)D-

lnx+2 ln ( x−1 )−ln (x2−1 )−ln3=0

ln ( x ( x−1 )3 ( x+1 ) )=0

x (x−1 )=e0 (3 ( x+1 ) )

x (x−1 )=3 x+3

x2−4 x=3

x2−4 x−3=0

4±√(−4)2−4(1×−3)2×1

x=4±2√72

x=2±√7

AP29)D-

log2 (5 x+1 )−log22=0

log2( 5 x+12 )=020=5 x+1

2

5 x+1=20×2

5 x+1=2

5 x=−1+2

x=15

AP31)J-

2x−1=1

ln (2x−1)=ln 1

( x−1 ) ln 2=ln1

( x−1 ) ln 2=0

x=−1

AP46)C-

y−4−8 y−2−9=0

1y4

− 8y2

−9=0

1y4× y4− 8

y2× y4−9× y4=0× y4

1−8 y2−9 y4=0

(1+3 y ) (1−3 y ) (1+ y2 )=0→y=13

23 x+7=343❑