105 prob sols - c

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PROGRAMS

1. Write a program to find factorial of a number

Br:

1) If number is negative store -1 into the output1 variable

2) If number is greater than 7 store -2 into the output1 variable

#include

#includevoid main()

{

int n,i,fact=1,op;

clrscr();

printf("\nEnter Number:");

scanf("%d",&n);

if(n7)

{

op=-2;

}

else

{

for(i=1;i

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op=-2;

else

{

if(count==1)

op=1;

if(count==2)

op=0;

if(count==3){

while(n!=0)

{

a=n%10;

sum=sum+(a*a*a);

n=n/10;

}

op=1;

}

}

}

printf("%d",op);

getch();

}

3. Write a program to find number of digits in a given number(ex: for 345 no of digits is 3)

1) if number is negative store -1 into the output1 variable

#include

#include

void main()

{

int n,a=0,op;

clrscr();

printf("\nEnter n:");

scanf("%d",&n);

if(n

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scanf("%d",&n);

if(n

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output1=-2;

printf("The Ans is:%d",output1);

}

else if(a[i]

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}

6. Given two arrays, compare two arrays and store the greater element of the arrays into output array.

Br:

1) If any of the element in an array is negative store -1 into first element of the output array

2) If the size of an array is negative then store -2 into the first element of the output array

#include

#include

void main()

{

int c[80],n ,a[30],b[30],i,j,k,temp,output1;

clrscr();

printf("ENTER THE ARRAY SIZE");

scanf("%d",&n);

printf("ENTER THE ARRAY ELEMENTS A:");

for(i=1;i

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{

output1=-1;

printf("The number is -ve=%d",output1);

}

else if(n>32767)

{

output1=-2;printf("The number great than =%d",output1);

}

else if(n>0&&n0)

{

a=n%10;

n=n/10;

if(a%2==0)

sum=sum+a;

}

printf("the sum is %d",sum);

}

getch();

}

9. Write a program to search an element in an array and if it is found store the location into

Output variable

Br:

1) if it is not found store 1 into the output variable

2) if any element in an input array is negative store -1 into output variable

3) if the size of an array is negative store -2 into the output variable

#include

#include

void main()

{

int a[20],search,n,flag,i,op;clrscr();


scanf("%d",&n);

if(n

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for(i=0;i

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{

if(i!=0)

k++;

max=count;

op[k]=a[i];

//k++;

}

else{}

}

}

}

for(i=0;i

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}

printf("\n\nOutput: %d",op);

getch();

}

12. Find the product of the digits of the given no and if product is divisible by 3 or 5 store 1 to the

output variable

Input1=56Output=1

Input2 is the array size.

BR

1.If the given input is negative store -1 to the output

2.If the given no itself is divided by 3 or 5 store -2 to the output

#include

#include

void main()

{

int num,n,op,a,i,sum=1;

clrscr();


scanf("%d",&n);

if(n

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scanf("%d",&n);

if(n

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3.Store -3 to the first position of the output array if the given array size is even

#include

#include

int main()

{

int input1[40],output[40],input;

int i,j,k,count=0,temp;clrscr();

printf("Enter the size::\n");

scanf("%d",&input);

if(input

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Input3=4;

OUTPUT[]={26,24,45,7}

BR

1.Store -1 to the first position of the output array if any input array elements contains negative

value

2.Store -2 to the first position of the output array if array size is negative

#include#include

int main()

{

int input1[40],input2[40],output[40],input;

int i,j,k,count=0;

clrscr();

printf("Enter the size::\n");

scanf("%d",&input);

if(input

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value

2.Store -2 to the first position of the output array if array size is negative

#include

#include

int main()

{

int input1[25],input2,output[25],i,j,k,count=0;

clrscr();printf("enter limit::\n");

scanf("%d",&input2);

if(input2

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void main()

{

int fahren;

clrscr();

printf("enter the temperature in fahrenheit:");

scanf("%d",&fahren);

temp(fahren);

printf("output=%d",out);getch();

}

void temp(int fahren)

{

if(fahren

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1) if the limit(n) is negative, store -1 to output

2) if the n value is greater than 7, store -1 to output

#include

#include

void primesum(int inut);

int out;

void main()

{int input;

clrscr();

printf("enter the range");

scanf("%d",&input);

primesum(input);

printf("output=%d",out);

getch();

}

void primesum(int input)

{

int sum=8,i,flag,j;

if(input7)

out=-1;

else

{

for(i=3;i

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for(i=0;i

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if(input1[i]

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{

printf("%d\t",output[i]);

}

getch();

}

void delnegandsort(int input1[],int input)

{

int j,temp;

if(input

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void main()

{

int input;

clrscr();

printf("Enter an number:");

k=(int)if(scanf("%d",&input));

sumofcubes(input,k);

printf("Sum of cubes of prime numbers:\n\tout=%ld",out);getch();

}

void sumofcubes(int input,int k)

{

int i,j,flag,count=0;

long int sum=1;

if(k!=1)

{

out=-2;

}

else if(input

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scanf("%d",&input1[i]);

sumofmul5(input1,input);

printf("\noutput:");

printf("%.1f\t",out);

getch();

}

void sumofmul5(int input1[],int input)

{int count=0,sum=0,temp;

if(input

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Business Rule:1.if the element is found, store 1 into the output variable,

2.if the array contanis -ve elements store 1- into the output variable,

3.if the array size is -ve, store -2 into the array,

4.if the element not found, store -3 into the array,

#include

#include

void main()

{int a[20],n,i,s,output;

clrscr();

printf("enter the limit:");

scanf("%d",&n);

if(n

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int j,i,output;

long int n,sum=0;

clrscr();

printf("enter the numbers:");

scanf("%ld",&n);

if(n32767)

{

output=-2;

printf("output=%d",output);

}

else

{

for(j=1;j

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count++;

}

}

avg=s/count;

printf("output=%f",avg);

}

getch();}

32. sum of squres of odd digits in a number.

Business Rule:if input1< 0, store -1 into the output variable

#include

#include

void main()

{

long int n,t,r=0,q,s=0,count=1,output;

clrscr();

printf("enter the value:");

scanf("%ld",&n);

if(n

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#include

void main()

{

int input1[25],input2,output1[25],i,j,temp;

clrscr();

printf("enter the range");


if(input2

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printf("enter limit");


if(input1500){

output1=-2;

printf("%d",output1);

}

else

{

for(i=1;i

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for(i=0;i

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Business Rules:

i) If the given input is not a binary value store -1 to the output variable.

ii) If the given input is greater than 11111 store -2 to the output variable.

#include

#include

void main()

{

long int input1,output1=0,base=1,rem,count=0,n,d,k=0;clrscr();

printf("enter number");

scanf("%ld",&input1);

if(input1>11111)

{

output1=-2;

printf("%ld",output1);

}

else

{

n=input1;

while(n!=0)

{

d=n%10;

k++;

if((d==0)||(d==1))

count++;

n=n/10;

}

if(k==count)

{

while(input1>0)

{

rem=input1%10;

output1=output1+rem*base;

input1=input1/10;

base=base*2;

}

printf("output1=%ld",output1);}

else

{

output1=-1;

printf("output1=%ld",output1);

}

}

getch();

}

37. Calculate the sum of squares of prime numbers up to N natural number. Consider input1 is the N

value. (Consider 1 is not a prime.)

Eg:

Input1=10

Output1=87

Business Rules:

i) If the given input is negative store -1 to the output variable.

ii) If the given input is greater than 500 store -2 to the output variable.

#include

#include

void main()

{

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int c,f;

clrscr();

printf("temperature=");

scanf("%d",&c);

if(c

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{

sum=sum+i*i;

}

}

printf("sum is %d",sum);

}

getch();

}

39. Convert celcius to farenheit

Business rule: if the input temperature is negative then store -1 to output1

#include

#include

void main()

{

int input1[10],input2,i,sum=0,output;

clrscr();

printf("\n input2=");


if(input2

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Input1[]={1.2.3.4}

Input2[]={4,3,2,1}

Output1={2,4,6,8}

Business Rule1: If the size of input array is negative ,then store -2 to output array

Business Rule2: If any of element in input array is negative then store -1 to output array

#include

#include

void main(){

int input1[10],input2[10],c[10],i,j,n,sum=0,output;

clrscr();

printf("\n size");

scanf("%d",&n);

if(n

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input1[]={2,-3,4,5,-9}

output1=11

Business Rule1: If the size of input array is negative ,then store -2 to output array

Business Rule2: If any element in input array is negative ,then store -1 to output array

#include

#include

void main(){

int a[10],n,i,j,sum=0,op;

clrscr();

printf("\n enter the limit of the arrays");

scanf("%d",&n);

if(n0)

{

printf("\n enter the array elements");

for(i=0;i

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else if(n>0)

{

printf("\n enter the array elements");

for(i=0;i=11111)

{

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op=-2;

printf("\n %ld",op);

}

else if(b

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k++;

}

}

if(k==2)

sum=sum+(i*i*i);

}}

printf("the sum of cube is %ld",sum);

getch();}

46. Program to calculate sum of squares of multiples of 5 and find out the average up to n number.

if

Input1

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for(i=0;i=0)

k++;

if(a[i]%3==0)

b++;

}if(k==n)

{

out=b;

}

else

out=-1;

}

printf("the out is %d",out);

getch();

}

48. Program to find out the sum of odds from a digit.

Input1 < 0 output1=-1

Input1 >32767 output1=-2

#include

#include

void main()

{

long int count=0, b, n,rev=0,d;

clrscr();

printf("enter the number");

scanf("%ld",&n);

if(n32767)

count=-2;

else

while(n!=0){d=n%10;

if(d%2!=0)

count=count+d;

n=n/10;

}

printf("the odd count in digit is %ld",count );

getch();

}

49. Program to find the repetitions of the particular element in an array for a given element.

Input1[]

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printf("\nBR2 : Output is %d",output); // Array size is negative

}

else if(n>0)

{

printf("\nEnter the elements of array : ");

for(i=0;i

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#include

#include

void main()

{

float salary,output1,days,savings,foodexp,travelexp,daysal,earnsal;

int flag=0,dayflag=0;

clrscr();printf("\nEnter the Monthly salary : ");

scanf("%f",&salary);

if(salary=0 && salary

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{

printf("\nOutput is Rs. %0.2f",output1);

}

getch();

}

51. wap to calculate the square of sum of even digits in a given number.(Ex:1234 output=20)

br:store -1 to output variable if input value is negative.#include

#include

void main()

{

int num,output,rev=0,rem,sum=0,count=0;

clrscr();

printf("\nEnter the Number : ");

scanf("%d",&num);

if(num0)

{

while(num!=0) // Reversing the number

{

rev=(rev*10)+(num%10);

num=num/10;

}

while(rev!=0) // Calculating sum of Squares

{

rem=rev%10;

count++;

rev=rev/10;

if(count%2==0) // Even digits

{

sum=sum+(rem*rem);output=sum;

}

}

}

printf("\nOutput is %d",output);

getch();

}

52. wap to find if input number is perfect number or not.

br:store 1 to output1 if it is perfect number

store -1 to output1 if it is not a perfect number

store -2 to output1 if entered number is negative number

#include

#include

void main()

{

int i,num,output1,n,sum=0;

clrscr();

printf("\nEnter the number : ");

scanf("%d",&n);

num=n;

if(num

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output1=-2; // BR3

}

else if(num>0)

{

for(i=1;ib)

output1=a;

else

output1=b;

if(c>output1)

output1=c;

}

printf("Output is %ld",output1);

getch();

}

54. wap to calculate the sum of multiples upto given number.

Ex: 3 upto 15(3+6+9+12+15=45)

#include

#include

void main()

{

int n ,sum=0,i;

clrscr();

printf("enter the limit:");

scanf("%d",&n);

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for(i=0;i

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}

if(flag==1)

op[0]=-1;

else

{

for(i=0;i

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{

output=0;

}

}

printf("\n%d",output);

getch();

}

58. find the product of prime numbers in a given array

B.R1: if input

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}

59. find the second largest number in a given array

B.R1:if any element is negative in the array store -1 in the output

B.R2:if the size of the array is less than 0 store -2 in the output

#include

#include

void main()

{int n,a[100],temp,i,j,output;

clrscr();

printf("Enter the size of the array:");

scanf("%d",&n);

if(n0)

{

printf("\nEnter the elements of the array:");

for(i=0;i

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if(n0)

{

printf("\nEnter the elements in the array:");for(i=0;i

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for(i=0;i

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//if((input1>0) && (input2>0))

{

switch(n)

{

case 1: input3=input1+input2;

printf("\n %d",input3);

break;

case 2: input3=input1-input2;

// input3=2;

printf("\n %d",input3);

break;

case 3: input3=input1*input2;

// input3=3;

printf("%d\n",input3);

break;

case 4: input3=input1/input2;

//nput3=4;

printf("%d\n",input3);

break;

}

}

getch();

}

63. List the prime numbers in the given array and store in the output array

Business Rule(Store -1 to output array if array contains any negative elements, Store -2 in the output

array if the input size is negative and Store -3 in the output array if there are no prime numbers in the

given input array)

#include#include

void main()

{

int n,i,j,a[100],f,c;

clrscr();

printf("\nenter the limit:");

scanf("%d",&n);

if(n

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if(f==0)

{

for(i=0;i

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else if(amt>0)

{

printf("\n Notes of 500 required:%d",amt/500);

printf("\n Notes of 100 required:%d",(amt%500)/100);

printf("\n Notes of 50 required:%d",((amt%500)%100)/50);

printf("\n Notes of 10 required:%d",(((amt%500)%100)%50)/10);

printf("\n Coins of 1 required:%d",((((amt%500)%100)%50)%10)/1);

}getch();

}

66. Calculate the gross salary of the employee given da and hra is 75% and 50% of basic salary

(Business rule: Store -1 in the output variable if basic pay10000 and -3 in the output variable if number of working days>31)

// 67. Find the sum of factors from a given number upto N like input1:3,input2:15

output1=3+6+9+12+15=45)

(Business rule:Store -1 in output variable if input1 is negative and -2 in output variable if input2 is

>32627) 68. Generate perfect numbers upto N natural numbers (Business rule: store -1 in output variable if N 23627)

#include

#include

void main()

{

int n,i,sum=0;

clrscr();

printf("\n Enter the number:");

scanf("\n %d",&n);

for(i=0;i

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{

for(i=min;i

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{

if(output[i]

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Input2:6

Input3:4

Output1:3

If any one of the element in input array is negative ,store-1,

If input2 is negative,store -2.


#include#include

void main()

{

int input[10],output=0,temp=0,i,j,n,ele;

printf("enter the size of array\n");

scanf("%d",&n);

if(n

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If he works for 31 days add 500 to the salary of the employee.

Example1:

Input1=5000

Input2=30

Output1=11250

Example2:Input1=5000

Input2=31

Output1=11750

If input1>10000,store -1.

If input2>31,store -2.



74. decimal to binary.

Hint: Output is an array

If input1 is negative,store -1

75. Find the largest of three numbers.

If any number is negative store -1 to output

If the number is greater than 32767 store -2 to output

76. a person owns some plots plot numbers are even and odd numbers, he want to keep average of

sum of odd numbers and sum of even numbers as his password,,.. What is his password Input is an array and output is an integer

Business rule if any number in array is negative store -1 in output1 Business rule if array size is negative store -2 in output1 77. a

ship story.. inputs are two arrays output is an array We have to add the FIRST ELEMENT OF ONE ARRAY WITH LAST ELEMENT OF

ANOTHER ARRAY SECOND ELEMENT OF ONE ARRAY WITH SECOND LAST ELEMENT OF ANOTHER ARRAY

Business rule if any number in array i s negative store -1 in output1...

78. salary story

Inputs are salary and number of working days

and output is an integer

Calculate the amount saved by a person if his

Salary of person is 7000 for 30 days500 extra if he works for 31 daysFood expenditure is 50% of salary

Travel expenditure is 20% of salary

Business rule:

If input1 >9000 then store -1if input1 is negative then store -3If input2 is negative then store -4

79. leap year

Store -1 in output 1 if input number is negative

80. product of prime

Store -1 in output 1 if input number is negative

81. second highst element in an array

Business rule if any number in array is negative store -1 in output1

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Business rule if array size is negative store -2 in output1

#include

#include

void main()

{

int a[100],i,j,n,count=0,temp;

printf("Enter the number");

scanf("%d",&n);

if(n

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for(j=i+1;j3 output=-2,if no. is not Armstrong

output=-3,if Armstrong output=1)

83. second highest no. in an array

(if array has any negative no. output=-1,if size of array isve output=-2)

84. print largest repeated element in array(if array has any negative no. output=-1,if size of array isve

output=-2)

85. count no. of digits in number(if no. isve output=-1)

#include

#include

void main()

{

int a,count=0;

clrscr();


scanf("%d",&a);

if(a99 output=-1,if 70

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int out,n,a[10],i,sum=0;

float avg;

clrscr();


scanf("%d",&n);

printf("enter the marks");

for(i=0;i

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}

}

}

printf(" 0 = %d",sum);

getch();

}

88. write a Program to calculate temperature from celcius to Fahrenheitc/5=f/9-32

Business Rules:

a)If given input is negative store -1 to the output variable

#include

void main()

{

float f,c;

clrscr();

printf("enter celsius");

scanf("%f",&c);

if(c

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output=-2;

printf("%d",output);

}

}

getch();

}

90. write a program to find products of digits which are divisible by 3 or 5

If it divisible then store 1 to the output variablea)if given input is divisible by 3 or 5 then store -1 to output variable

b)if given input is negative store -2 to output variable

Input=56Output=1

#include

#include

void main()

{

int input,output,pdt=1,d;

clrscr();

printf("enter number");

scanf("%d",&input);

if(input

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printf("enter range");


if(input2

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{

printf("enter elements");

for(i=0;i

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for(i=0;i

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94. Second largest in a given array.[if array has -ev elements store -1 , if array size is -ve store -2]#include

#include

void main()

{

int n,i,j,t,a[10];

clrscr();

printf("Enter the number");

scanf("%d",&n);

if(n

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printf("%d",output);

goto l;

}

printf("Enter the values");

for(i=0;i

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}

else if(bs31)

{

c=-2;

printf("\n %d",c);

}

else if(d99 store -3]

#include

#include

void main()

{

int av,a[10],n,i,sum=0,j,bs,c,d;

float avg;

clrscr();

printf("enter the no of subjects");

scanf("%d",&n);

if(n

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av=-3;

printf("%d",av);

}

else

printf("the average is %f",avg);

}l:

getch();

}

98. Sort the array (half ascending and descending based on odd or even no elements) [if input arrayhas -ve elements store -1, size of array -ve store -2]

#include

#include

void main()

{

int s[20], a[20],i,j,n,b[20],c[20],t,d[20],e[20],k;

clrscr();

printf("enter the limit");scanf("%d",&n);

printf("enter the element");

for(i=1;i

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}

for(i=(n/2)+1;i

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99. Sum of digits of a given number. Input1=given number, if the

given no is negative store output1=-1,if given no is >32767

#include

#include

void main()

{

long int a,count=0;clrscr();

printf("enter any no");

scanf("%ld",&a);

if((a32767))

{

count=-1;

printf("%d",count);

goto l;

}

while(a!=0)

{

a=a/10;

count=count+1;

}

printf("no of digit in a no %d",count);

l:

getch();

}

99. Sum of digits of a given number. Input1=given number, if thegiven no is negative store output1=-1,if given no is >32767

#include

#includevoid main()

{long int a,count=0;clrscr();

printf("enter any no");scanf("%ld",&a);

if((a32767)){count=-1;

printf("%d",count);

goto l;}while(a!=0)

{

a=a/10;count=count+1;

}printf("no of digit in a no %d",count);l:

getch();

}

100. Sum of digits of a given number. Input1=given number, if the given no is negative storeoutput1=-1,if given no is >32767101. Sum of even numbers up to n numbers if the given no is negative store output1=-1,if given no is

>32767

#include

#include

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void main()

{

int n,i,out=0;

clrscr();

printf("\n enter the no");

scanf("%d",&n);

if(n3276)

{

out=-1;

}

else

{

for(i=1;i

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{

int n,i,j,out=0;

printf("\n enter the range");

scanf("%d",&n);

if(n

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if(n

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if(n

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}

else

j++;

}

}

for(i=0;i10000,store output1=-1.

105 prob sols - c

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