trabajo colaborativo 2 calculo diferencial

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lim x→ 2 x 2 x2 x 2 5 x + 6 = 2 2 22 2 2 5 ( 2)+6 = 0 0 lim x→ 2 x 2 x2 x 2 5 x + 6 = ( x2)(x+ 1) ( x3 )( x2) = x+1 x3 = 2+ 1 23 = 3 1 =−3

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Trabajo colaborativo 2 calculo diferencial

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