problema nª 2 hardy cross
TRANSCRIPT
PROBLEMA Nª2Determinar por metodo de Hardy Cross los caudales que circulan por cada uno de los ramales de la red de tuberias mostradas.
SOLUCION:
10", 1200m
12", 1200m 14", 2000m
8", 1200m
10",
150
0m
10",
150
0m
10", 2000m
8", 2000m
10",
150
0m
12",
150
0m
16",
150
0m
C = 100
C = 120
C = 100
C = 120
C = 100C = 100
C =
100
C =
100
C =
100
C =
100
C =
100
45lt/s 55lt/s
30lt
/s
30lt
/s
20lt/s
25lt
/s
35lt
/s
70lt
/s
25lt/s
8lt/s15lt/s
2 1 3
6 5 4
789
PRIMERA ITERACIONCIRCUITO I
tramo D (pulg) L(Km) Qo
1--2 12 1.2 100 -45
2--6 10 1.5 100 -30
6--5 10 1.2 120 25
1--5 16 1.5 100 70Σ
CIRCUITO II
tramo D (pulg) L(Km) Qo
1--3 14 2 100 55
3--4 10 1.5 100 30
4--5 10 2 120 -20
1--5 16 1.5 100 -70Σ
CIRCUITO III
tramo D (pulg) L(Km) Qo
6--5 10 1.2 120 -25
6--9 12 1.5 100 -35
9--8 8 1.2 100 -15
8--7 8 2 100 8
7--4 10 1.5 100 25
4--5 10 2 120 20Σ
SEGUNDA ITERACION
CIRCUITO Itramo D (pulg) L(Km) Qo
1--2 12 1.2 100 -38.999
2--6 10 1.5 100 -23.999
6--5 10 1.2 120 30.658
1--5 16 1.5 100 82.011Σ
CIRCUITO II
CH
CH
CH
CH
45lt/s 55lt/s
30lt
/s
30lt
/s
20lt/s
25lt
/s
35lt
/s
70lt
/s
25lt/s
8lt/s15lt/s
2 1 3
6 5 4
789
tramo D (pulg) L(Km) Qo
1--3 14 2 100 48.990
3--4 10 1.5 100 23.990
4--5 10 2 120 -26.352
1--5 16 1.5 100 -82.011Σ
CIRCUITO III
tramo D (pulg) L(Km) Qo
6--5 10 1.2 120 -30.658
6--9 12 1.5 100 -34.657
9--8 8 1.2 100 -14.657
8--7 8 2 100 8.343
7--4 10 1.5 100 25.343
4--5 10 2 120 26.352Σ
TERCERA ITERACION
CIRCUITO Itramo D (pulg) L(Km) Qo
1--2 12 1.2 100 -39.419
2--6 10 1.5 100 -24.419
6--5 10 1.2 120 30.503
1--5 16 1.5 100 80.897Σ
CIRCUITO II
tramo D (pulg) L(Km) Qo
1--3 14 2 100 49.684
3--4 10 1.5 100 24.684
4--5 10 2 120 -25.393
1--5 16 1.5 100 -80.897Σ
CIRCUITO III
tramo D (pulg) L(Km) Qo
6--5 10 1.2 120 -30.503
6--9 12 1.5 100 -34.923
9--8 8 1.2 100 -14.923
8--7 8 2 100 8.077
7--4 10 1.5 100 25.077
4--5 10 2 120 25.393Σ
CH
CH
CH
CH
CH
Q
1 2
2 6
6 5
1 5
1 3
3 4
4 5
6 5
6 9
9 8
8 7
7 4
39.412
24.412
30.448
81.043
49.545
24.545
25.595
30.448
34.861
14.861
8.139
25.1391
lQ l slQ l slQ l slQ l slQ l slQ l slQ l slQ l slQ l slQ l slQ l slQ l s
Determinar por metodo de Hardy Cross los caudales que circulan por cada uno de los ramales de la red de tuberias mostradas.
10", 1200m
12", 1200m 14", 2000m
8", 1200m
10",
150
0m
10",
150
0m
10", 2000m
8", 2000m
10",
150
0m
12",
150
0m
16",
150
0m
C = 100
C = 120
C = 100
C = 120
C = 100C = 100
C =
100
C =
100
C =
100
C =
100
C =
100
45lt/s 55lt/s
30lt
/s
30lt
/s
20lt/s
25lt
/s
35lt
/s
70lt
/s
25lt/s
8lt/s15lt/s
2 1 3
6 5 4
789
hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ-2.789 0.062 6.001 -38.999-3.987 0.133 6.001 -23.9991.624 0.065 5.658 30.6581.956 0.028 12.011 82.011-3.195 0.288
hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ3.190 0.058 -6.010 48.9903.987 0.133 -6.010 23.990-1.792 0.090 -6.352 -26.352-1.956 0.028 -12.011 -82.0113.429 0.308
hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ-1.624 0.065 -5.658 -30.658-2.190 0.063 0.343 -34.657-2.611 0.174 0.343 -14.6571.360 0.170 0.343 8.3432.845 0.114 0.343 25.3431.792 0.090 6.352 26.352-0.428 0.675
hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ-2.140 0.055 -0.420 -39.419-2.638 0.110 -0.420 -24.4192.369 0.077 -0.155 30.5032.622 0.032 -1.114 80.8970.213 0.274
45lt/s 55lt/s
30lt
/s
30lt
/s
20lt/s
25lt
/s
35lt
/s
70lt
/s
25lt/s
8lt/s15lt/s
2 1 3
6 5 4
789
hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ2.575 0.053 0.694 49.6842.636 0.110 0.694 24.684-2.985 0.113 0.959 -25.393-2.622 0.032 1.114 -80.897-0.395 0.308
hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ-2.369 0.077 0.155 -30.503-2.150 0.062 -0.266 -34.923-2.502 0.171 -0.266 -14.9231.470 0.176 -0.266 8.0772.918 0.115 -0.266 25.0772.985 0.113 -0.959 25.3930.351 0.715
hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ-2.183 0.055 0.007 -39.412-2.724 0.112 0.007 -24.4122.347 0.077 -0.055 30.4482.556 0.032 0.146 81.043-0.003 0.275
hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ2.643 0.053 -0.139 49.5452.779 0.113 -0.139 24.545-2.787 0.110 -0.201 -25.595-2.556 0.032 -0.146 -81.0430.079 0.307
hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ-2.347 0.077 0.055 -30.448-2.181 0.062 0.062 -34.861-2.586 0.173 0.062 -14.8611.385 0.171 0.062 8.1392.862 0.114 0.062 25.1392.787 0.110 0.201 25.595-0.081 0.708