7/26/2019 Materia 15

1/2

(1z1 )2

z [( Ts+1)

( s+1)

T s2]

(1z1 )2

z

[ Ts+1

T s2 ( s+1 )]

Transformada z:

t=0.5

0.5 s+1

0.5s2 (s+1 )

= s+2

s2 ( s+1 )

=A

s+B

s2+ C

s+1

AS ( S+1 )+B ( S+1 )+C s2

=s+2

A s2+As+Bs+C s2=s+2

A+C=0

A+B=1

B=2

A=1

C=1

1s+ 2

s2+ 1

s+1

Escriba aqu la ecuacin.

(1z1 )2

[z

z1

z

(z1)2+

z

z0.61 ] (1z1 )

2[z (z1 )z(z1)2 + z

z0.61 ]

7/26/2019 Materia 15

2/2

(1z1 )2[z

2z(z1)2

+ z

z0.61]