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  • 7/25/2019 Informe Ensayo de Compresin de Madera

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    UNIVERSIDAD POLITCNICA SALESIANA

    FACULTAD:INGENIERAS

    CARRERA:MECNICA

    LABORATORIO DE INGENIERA MECNICA

    TEMA:ENSAYO DE COMPRESIN EN MADERA

    (Fime, 2006)

    5TO A GRPO !

    BRAYAN MONTERO

    0"#!2#20!$

    QUITO-ECUADOR

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    ENSAYO DE COMPRESIN ENMADERA

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    ESFUER;O7)=(2,6

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    DEFORMACIONUNITARIA?8@L=L!

    M./1%! /eE%$&ti(i/$/5PSI6

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    !550 0,2 22!$,$" ;;,5 !2,00E0 !,05E06

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    950 0,!" 69;2,"; 29!,$2 29,00E0 !,$E06

    C0%(1%!&

    CALCULAR:EUCALIPTO

    A&:

    As=5x5cm2

    As=25cm2

    Ac=r2=(1 )2=2

    F=PA :

    F1=5102,2

    =728,28 kgf F5=4200

    2,2=5997,6Kgf

    F2=1500

    2,2=2141,99 kgf

    F6=5200

    2,2=7425,58 kgf

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    F3=2400

    2,2=3427,2 kgf

    F7=6200

    2.2=8853,58 kgf

    F4=3300

    2,2=4712,39 kgf F8=

    72002.2

    =10281,6 kgf

    F9=8000

    2,2

    =11424 kgf

    =F

    As

    1=728,28

    25=29,13(Kgf/cm2)

    5=5997,6

    25=239,90(Kgf/cm2)

    2=2141,99

    25=85,68(Kgf/cm2)

    6=7425,58

    25=297,02(Kgf/cm2)

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    3=3427,2

    25=137,09(Kgf/cm2)

    7=8853,6

    25=354,14(Kgf/cm2)

    4=4712,39

    25=188,5 (Kgf/cm2)

    8=10281,625 =411,26(Kgf/cm2)

    9=11424

    25=456,96(Kgf/cm2)

    =

    L :

    1=0,02

    200=1104 5=

    0,11

    200=5,510

    4

    2=0,03

    200

    =1.5104

    6=0,16

    200

    =8104

    3=0,04

    200=2104 7=

    0,22

    200=11104

    4=0,07

    200=3,5104 8=

    0,30

    200=15104

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    9=0,42

    200=21104

    =

    :

    1=

    29,13

    11041

    0.0703=4,14106psi 5=

    239,9

    5,51041

    0.0703=6,20106psi

    2=

    85,68

    1,51041

    0.0703=8,13106 psi 6=

    297,02

    81041

    0.0703=5,2810

    6psi

    3=

    137,09

    21041

    0.0703=9,75106psi 7=

    354,14

    111041

    0.0703=4,58106 psi

    4=

    188,5

    3,51041

    0.0703=7,66106 psi 8=

    411,26

    151041

    0.0703=3,9106psi

    9=

    456,96

    211041

    0.0703=3,1106 psi

    M./1%! /e e%$&ti(i/$/ t!t$% 5E6:

    E=

    =6565

    E= 297,02239,9

    81045,5104

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    E=228480psi

    CALCULAR: MALVA

    A&:

    As=5x5cm2

    As=25cm2

    Ac=r2=(1 )2=2

    F=PA :

    F1=5002,2

    =713,998kgf

    F5=4500

    2,2=6425,98Kgf

    F2=1500

    2,2=2141,99 kgf

    F6=5200

    2,2=7425,58 kgf

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    F3=2500

    2,2=3569,99 kgf

    F7=6000

    2.2=8567,98 kgf

    F4=3500

    2,2=4997,99 kgf

    =F

    As

    1=713,998

    25=28,56(Kgf/cm2)

    5=6425,98

    25=257,04 (Kgf/cm2)

    2=2141,99

    25=85,68(Kgf/cm2)

    6=7425,5825

    =297,02(Kgf/cm2)

    3=3569,99

    25=142,8(Kgf/cm2)

    7=8567,98

    25=342,72(Kgf/cm2)

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    4=4997,99

    25=199,92(Kgf/cm2)

    =

    L :

    1=0,10

    200=5104 5=

    0,69

    200=34,5104

    2=0,20

    200=10104 6=

    0,93

    200=46,510

    4

    3=0,35

    200=17,5104 7=

    1.17

    200=58,5104

    4=0,50

    200

    =25104

    =

    :

    1=28,565104

    1

    0.0703=0.813106 psi 5=

    257,0434,5104

    1

    0.0703=1,06106psi

    2=

    85,68

    101041

    0.0703=1,22106psi 6=

    297,02

    46,51041

    0.0703=0,909106 psi

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    3=

    142,8

    17,51041

    0.0703=1,16106psi 7=

    342,72

    58,51041

    0.0703=0,833106psi

    4=

    199,92

    251041

    0.0703=1,14106psi

    M./1%! /e e%$&ti(i/$/ t!t$% 5E6:

    E=

    =5454

    E= 257,04199,92

    34,510425104

    E=60126,3psi

    CALCULAR: PINO

    A&:

    As=5x5cm2

    As=25cm2

    Ac=r2=(1 )2=2

    F=PA :

    F1= 5502,2 =785,4 kgf F4=32502,2 =4640,99kgf

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    F2=1550

    2,2=2213,39 kgf

    F5=4000

    2,2=5711,99Kgf

    F3=2500

    2,2=3569,99 kgf

    F6=47502,2 =6782,98 kgf

    =F

    As

    1=785,4

    25=31,42(Kgf/cm2)

    4=4640,99

    25=185,64 (Kgf/cm2)

    2=2213,3925 =88,54 (Kgf/cm2)

    5=5711,99

    25=228,48(Kgf/cm2)

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    3=3569,99

    25=142,8(Kgf/cm2)

    6=6782,98

    25=271,32(Kgf/cm2)

    =

    L :

    1=0,12

    200=6104 4=

    0,44

    200=22104

    2=0,24

    200=12104 5=

    0,52

    200=26104

    3=0,35200 =17,5104 6=0,54200 =2710

    4

    =

    :

    1=

    31,42

    61041

    0.0703=0,7106psi 4=

    185,64

    221041

    0.0703=1,20106psi

    2=

    88,54

    121041

    0.0703 =1,05106

    psi 5=

    228,48

    261041

    0.0703 =1,25106

    psi

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    3=

    142,8

    17,51041

    0.0703=1,16106psi 6=

    271,32

    271041

    0.0703=1,43106psi

    M./1%! /e e%$&ti(i/$/ t!t$% 5E6:

    E=

    =4343

    E= 185,64142,82210417,5104

    E=95200psi

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    P/./ 7%/ me*-. '-m.e1i4% -+e%'i4% &e &/+-1 &ee +e%e. 7%/ =./%

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