hardy cross
DESCRIPTION
hcTRANSCRIPT
ESTUDIO DE REDES DE TUBERIA
ESTUDIO DE REDES DE TUBERIA
(METODO DE HARDY CROSS)
SOLUCIONPROBLEMA N 01
Determinar por el mtodo de Hardy Cross, los caudales que circulan por cada tubera
SOLUCION:
1ra ITERACION
CIRCUITO I
TuboD(pulg)L(km)CHQohfo (m)hfo/QoQQ1 = Qo + Q
1-22-3
1-386
60.50.5
0.6100100
100+35+10
-15+5.109+2.037-5.1750.1460.2040.345-1.533-1.533-1.6546-1.53333.467+6.81-16.533
= +1.970 = 0.695CIRCUITO II
TuboD(pulg)L(km)CHQohfo (m)hfo/QoQQ1 = Qo + Q
2-42-33-48
6
80.7
0.5
0.6100
100
100+25
-10
-25+3.838-2.037-3.290.1540.2040.132+1.6546
+1.6546+1.533+1.654626.646-6.81-23.354
= -1.489 = 0.4892da ITERACION
CIRCUITO I
TuboD(pulg)L(km)CHQ1hf1 (m)hf1/Q1QQ2 = Q1 + Q
1-2
2-3
1-38
6
60.5
0.5
0.6100
100
100+33.65+7.00-16.35+4.702+2.08-6.1960.1410.2060.375+0.17+0.17+0.35+0.1733.827.52-16.18
= -0.586 = 0.721CIRCUITO II
TuboD(pulg)L(km)CHQ1hf1 (m)hf1/Q1QQ2 = Q1 + Q
2-42-33-48
6
80.7
0.5
0.6100
100
100+26.65
-7.0
-23.35+4.2
-1.05
-2.870.160.150.12-0.35-0.35-0.17-0.3526.30-7.52-23.70
= +0.28 = 0.433ra ITERACION
CIRCUITO I
TuboD(pulg)L(km)CHQ2hf2 (m)hf2/Q2QQ3 = Q2 + Q
1-2
2-3
1-38
6
60.5
0.5
0.6100
100
100+33.2+7.52-16.18+4.54+1.20-5.750.13
0.160.35+0.008+0.008-0.046 +0.00833.217.48-16.18
= -0.01 = 0.64CIRCUITO II
TuboD(pulg)L(km)CHQ2hf2 (m)hf2/Q2QQ3 = Q2 + Q
2-42-33-48
6
80.7
0.5
0.6100
100
100+26.30-7.52-23.7+4.1-1.20-2.920.15
0.160.12+0.046+0.046-0.008+0.04626.35-7.48-23.65
= -0.02 = 0.43Error = Q*100/Q = 0.008*100/16.17= 0.00005% < 1% ( OKEYError = Q*100/Q = 0.046*100/23.65 = 0.002% < 1% ( OKEY
( Q1-2 = 33.21 lt/s
Q2-3 = 7.48 lt/s Q1-3 = 16.17 lt/s Q2-4 = 26.35lt/s Q3-4 = 23.65 lt/s
PROBLEMA N 02Determinar por el mtodo de Hardy Cross los caudales que circulan por cada uno de los ramales de la red de tuberas mostradas.
SOLUCION:
1ra ITERACION
CIRCUITO I
TuboD(pulg)L(km)CHQohfo (m)hfo/QoQQ1 = Qo + Q
1-2
2-66-5
1-512
10
10
161.2
1.5
1.2
1.5100
100
120
100-45
-30
+25
+70- 2.64
-3.45
+1.56
+1.270.0586
0.1150
0.0623
0.0182+ 6.95+ 6.95
+6.95-0.525
+6.95+5.64-38.05
-23.05
+31.425
+82.59
= -3.26 = 0.2541CIRCUITO II
TuboD(pulg)L(km)CHQohfo (m)hfo/QoQQ1 = Qo + Q
1-33-4
4-51-514
10
10162.01.52.01.5100
100
120
100+55+30
-20
-70+3.00+3.45
-1.66-1.880.0545
0.1150
0.08300.0268-5.64-5.64
-5.64-0.525-5.64-6.95+49.366+24.36
- 26.165
- 82.59
= +2.91 = 0.2973CIRCUITO III
TuboD(pulg)L(km)CHQohfo (m)hfo/QoQQ1 = Qo + Q
6-56-9
9-8
8-7
7-4
4-510
12
8
8
10
101.2
1.5
1.2
2.0
1.5
2.0120
100
100
100
100
120-25-35-15+8+25
+20-1.56-2.1
-2.51
+1.3
+2.55
+1.70.06230.06
0.1676
0.1624
0.1020
0.08500.525-6.95
0.525
0.525
0.525
0.525
0.525+5.64-31.425-34.475
-14.475
8.525
+25.525
+26.165
= +0.62 = 0.63932da ITERACION
CIRCUITO I
TuboD(pulg)L(km)CHQ1hf1 (m)hf1/Q1QQ2 = Q1 + Q
1-2
2-66-5
1-512
10
10
161.2
1.5
1.2
1.5100
100
120
100-38.05
-23.05
+31.42
+82.59-1.92
-2.25
+2.28
+2.400.0505
0.0978
0.0735
0.0291-1.1
-1.1
-1.1+0.156
-1.1-0.76-39.15
-24.15
+30.48
+80.73
= +0.51 = 0.2509CIRCUITO II
TuboD(pulg)L(km)CHQ1hf1 (m)hf1/Q1QQ2 = Q1 + Q
1-33-4
4-5
1-514
10
10
162.0
1.5
2.0
1.5100
100
120
100+49.36
+24.36
-26.16
-82.59+2.4
+2.4
-2.8
-2.40.0545
0.1150
0.0830
0.0268+0.76
+0.76+0.76+0.156
+0.76+1.1+50.12+25.12
-25.249
-80.76
= -0.4 = 0.2835CIRCUITO III
TuboD(pulg)L(km)CHQ1hf1 (m)Hf1/Q1QQ2 = Q1 + Q
6-56-9
9-8
8-7
7-4
4-510
12
8
8
10
101.2
1.5
1.2
2.0
1.5
2.0120
100
100
100
100
120-31.42-34.47
-14.47
+8.52+25.52+26.16-2.28-2.025
-2.4
+1.4
+2.7
+2.80.07250.0589
0.1656
0.1640
0.1060
0.1073+1.156+1.1-0.156
-0.156
-0.156
-0.156
-0.156-0.76-30.481-34.631
-14.631
+8.369
+25.369
+25.249
= +0.195 = 0.67433ra ITERACION
CIRCUITO I
TuboD(pulg)L(km)CHQ2hf2 (m)hf2/Q2QQ3 = Q2 + Q
1-2
2-66-5
1-512
10
10
161.2
1.5
1.2
1.5100
100
120
100-39.15
-24.15
+31.48
+80.73-2.1-2.40
+2.10
+2.330.05380.0997
0.0690
0.0290+0.15+0.15
+0.15+0.025
+0.15+0.425-39.00-24.00
+30.656
+81.305
= -0.07 = 0.2515CIRCUITO II
TuboD(pulg)L(km)CHQ2hf2 (m)hf2/Q2QQ3 = Q2 + Q
1-33-4
4-5
1-514
10
10
162.0
1.5
2.0
1.5100
100
120
100+50.12+25.12
-25.249
-80.73+2.5+2.55
-2.5
-2.330.0500.1010
0.0990
0.0290-0.425-0.425
-0.425+0.025
-0.425-0.15+49.695+24.695
-25.649
-81.305
= -0.22 = 0.2790CIRCUITO III
TuboD(pulg)L(km)CHQ2hf2 (m)hf2/Q2QQ3 = Q2 + Q
6-56-9
9-8
8-7
7-4
4-510
12
8
8
10
101.2
1.5
1.2
2.0
1.5
2.0120
100
100
100
100
120-30.481-34.631
-14.631
+8.369
+25.369
+25.249-2.10-2.10
-2.22
+1.4
+2.55
+2.50.07250.0589
0.1656
0.1640
0.1060
0.1073-0.025-0.15-0.025
-0.025
-0.025
-0.025
-0.025+0.42-30.656-34.656
-14.656
+8.344
+25.344
+25.649
= +0.03 = 0.6482Como: Q < 1% Q3 ( los caudales Q3 en cada tramo son:Q1-2 = 39l/s
Q2-6 = 24l/s
Q6-5 = 30.656l/s
Q1-5 = 81.305l/s
Q1-3 = 49.695l/s
Q3-4 = 24.695l/sQ4-5 = 25.649l/s
Q6-9 = 34.656l/s
Q9-8 = 14.655l/s
Q8-7 = 8.344l/sQ7-4 = 25.344l/s
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