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Universidad Fermín Toro
Ministerio de Educación Superior
Valera. Estado Trujillo
Asignación nro 3
Circuitos 2
Profesora
Matilde Garcia
Estudiante
Sofía Berrios
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DATOS
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Calculo de L
Calculo de C
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Calculo de f2
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BHZ=f2-f1=>f1=f2- BHZ
f1= – 120Hz=5771,308687Hz
f1=5771,308687Hz
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Datos
6Hz
Br=0.2MHz
QL=12,5=
L=831µHz
a)
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b)
c)
√ =>C=
=
C=
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Asumiendo que la bobina tiene elevado factor de
calidad (Qbob>>1)lo cual implica que XL>>1, o que
WL>>RL1 entonces
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Con R2=
XLXC=
R3=R5//R2=
R1=8Ω
Para que halla resonancia XL=XC=400 Ω
XLXC=
=(
R3=R2//R5=
R3=10KΩ
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Con B=1KHz=2π*1000rad/s
B=
C=
Wr=50000
=
Fp=25KHz
=25
Q=25
Para calcular Vc=Vab, es resonancia, dibulo el circuito con
solo R3
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Vab=Vc=IR3=0,1*10KΩ=1V
VC=1V
Vc=Vab=I/Yab=I/Zab
Yab=0,1* (
)
L=
L=
Vc=
(
) con wr=
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