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  • ESPECTROS ELECTRONICOS

  • -1 0 1

  • -1 0 1

    MICROESTADOS

  • 1) ORIENTACION DE ESPINES

    2) ORIENTACION DE MOMENTOS ANGULARES

  • LOS TERMINOS DE UNA CONFIGURACION d2 SON

    1G, 3F, 1D, 3P, 1S

  • MODELO DE ENLACE VALENCIA

    DE LA FORMULA, OBTENER:

    1) NUMERO DE COORDINACION

    2) ELECTRONES EN ORBITALES d

    (TODOS LOS e DE LA FAMILIA

    ESTAN EN d)

    [VCl3(NH3)3] NC = 6

    V0 = d5, V3+ = d2

  • MODELO DE ENLACE VALENCIA

    1) NC = 6

    2) Fe0 = d8, Fe2+ = d6

    Fe

    (3)d (4)s (4)p

    [FeII(L)6]2+

    Fe

    (3)d (4)s (4)p

    3) OCUPACION ORBITAL

    5) HIBRIDACION

    4) MAGNETISMO

  • sp lineal

    sp2 triangular

    sp3 tetraedro

    sdz lineal

    sd 90 grados

    sp2d cuadrada

    sp3d bipiramide triangular

    sp3d2 octaedro

    HIBRIDACION Y ESTRUCTURA

  • [FeII(H2O)6]2+

    NC = 6

    Fe2+3d 4s 4p

    Fe0 = d8, Fe2+ = d6

    4d

    sp3d2 OCTAEDRO PARAMAGNETICO, ALTO ESPIN (AS)

    Fe2+3d 4s 4p 4d

    sp3d2 OCTAEDRO DIAMAGNETICO

  • [FeII(CN)6]2+

    NC = 6

    Fe2+3d 4s 4p

    Fe0 = d8, Fe2+ = d6

    4d

    sp3d2 OCTAEDRO PARAMAGNETICO, ALTO ESPIN (AS)

    Fe2+3d 4s 4p 4d

    sp3d2 OCTAEDRO DIAMAGNETICO

  • [FeII(H2O)6]2+

    [FeII(CN)6]4-

    [FeIIIF6]3-

    [FeIII(CN)6]3-

    [Fe0(CO)5]0

    3d 4s 4p 4d

    AS

    BS

    AS

    BS

    BS

    sp3d2

    d2sp3

    sp3d2

    d2sp3

    dsp3

    OCT

    OCT

    OCT

    OCT

    BT

  • [FeII(CN)6]4-

    NC = 6

    Fe2+

    3d 4s 4p

    Fe0 = d8, Fe2+ = d6

    4d

    sp3d2 OCTAEDRO

    DIAMAGNETICO

    PREDICCION:

  • MODELO DE ENLACE VALENCIA

    1) NC = 6

    2) Fe0 = d8, Fe2+ = d6

    Fe

    (3)d (4)s (4)p

    Cl-NH3

    d4sp = OCTAEDRO, DIAMAGNETICO

    [FeII(L)6]2+

  • [FeII(H2O)6]2+

    NC = 6

    Fe2+

    3d 4s 4p

    Fe0 = d8, Fe2+ = d6

    4d

    sp3d2 OCTAEDRO

    DIAMAGNETICO

    PREDICCION:

  • [FeII(H2O)6]2+

    NC = 6

    Fe2+

    3d 4s 4p

    Fe0 = d8, Fe2+ = d6

    4d

    sp3d2 OCTAEDRO

    DIAMAGNETICO…

    PERO ES PARAMAGNETICO CON 4 ELECTRONES

    DESAPAREADOS…

  • [FeII(CN)6]4-

    NC = 6

    Fe2+

    3d 4s 4p

    Fe0 = d8, Fe2+ = d6

    4d

    sp3d2 OCTAEDRO

    DIAMAGNETICO

    PREDICCION:

  • [FeIIIF6]3-

    NC = 6

    Fe3+

    3d 4s 4p

    Fe0 = d8, Fe3+ = d5

    4d

    sp3d2 OCTAEDRO

    PARAMAGNETICO 1e DESAPAREADO

    PREDICCION:

  • [FeIIIF6]3-

    NC = 6

    Fe3+

    3d 4s 4p

    Fe0 = d8, Fe3+ = d5

    4d

    sp3d2 OCTAEDRO

    PARAMAGNETICO 1e DESAPAREADO…

    SI ES PARAMAGNETICO PERO CON 5e DESAPAREADOS…

  • [FeIIIF6]3-

    NC = 6

    Fe3+

    3d 4s 4p

    Fe0 = d8, Fe3+ = d5

    4d

    sp3d2 OCTAEDRO

    PARAMAGNETICO (AS), 5e DESAPAREADOS…

  • [FeIII(CN)6]3-

    NC = 6

    Fe3+

    3d 4s 4p

    Fe0 = d8, Fe3+ = d5

    4d

    sp3d2 OCTAEDRO

    PARAMAGNETICO 1e DESAPAREADO

    PREDICCION:

  • [FeIII(CN)6]3-

    NC = 6

    Fe3+

    3d 4s 4p

    Fe0 = d8, Fe3+ = d5

    4d

    sp3d2 OCTAEDRO

    PARAMAGNETICO 1e DESAPAREADO

    PREDICCION:

  • [CoII(H2O)6]2+

    [CoII(NO2)6]4-

    [CoIIIF6]3-

    [CoIII(CN)6]3-

    AS

    BS

    AS

    BS

    sp3d2

    d2sp3

    sp3d2

    d2sp3

    octa

    octa

    octa

    octa

    3d 4s 4p 4d

  • [NiII(CN)4]2-

    [Ni0(CO)4]0

    [NiIICl4]2-

    BS

    BS

    AS

    dsp2

    sp3

    tetra

    cuad

    tetra

    3d 4s 4p 4d

    sp3

  • [CuI(CN)4]3-

    [CuII(NH3)4]2+

    sp3

    dsp2

    tetra

    cuad

    3d 4s 4p 4d

  • HUGO TORRENS

    ELECTRONES EN d

    Ni

    (3)d (4)s (4)p

    Pd

    (4)d (5)s (5)p

    Pt

    (5)d (6)s (6)p