complex numbers class work - content.njctl.org

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Pre-Calc Polar & Complex #s ~1~ NJCTL.org Complex Numbers – Class Work Simplify using i. 1. βˆšβˆ’16 2. βˆšβˆ’36 4 3. βˆšβˆ’8 2 4. βˆšβˆ’32 6 7 5. βˆšβˆ’16 βˆ™ βˆšβˆ’25 6. βˆšβˆ’8 βˆ™ βˆšβˆ’10 7. 3 βˆ™ 4 βˆ™ 5 8. βˆ’2 βˆ™ 4 βˆ™ βˆ’6 βˆ™ 8 9. 9 10. 22 11. 75 Complex Numbers – Homework Simplify using i. 12. βˆšβˆ’81 13. βˆšβˆ’121 8 14. βˆšβˆ’18 6 15. βˆšβˆ’48 5 6 16. βˆšβˆ’9 βˆ™ βˆšβˆ’4 17. βˆšβˆ’12 βˆ™ βˆšβˆ’75 18. 2 βˆ™ 5 βˆ™ 7 19. βˆ’ βˆ™ βˆ’3 βˆ™ βˆ’5 βˆ™ βˆ’7 20. 10 21. 23 22. 72 √ √ βˆ’ βˆ’βˆš βˆ’ βˆ’ βˆ’ √ √ βˆ’ βˆ’ βˆ’ βˆ’ βˆ’

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Page 1: Complex Numbers Class Work - content.njctl.org

Pre-Calc Polar & Complex #s ~1~ NJCTL.org

Complex Numbers – Class Work

Simplify using i.

1. βˆšβˆ’16 2. βˆšβˆ’36𝑏4 3. βˆšβˆ’8π‘Ž2

4. βˆšβˆ’32π‘₯6𝑦7 5. βˆšβˆ’16 βˆ™ βˆšβˆ’25 6. βˆšβˆ’8 βˆ™ βˆšβˆ’10

7. 3𝑖 βˆ™ 4𝑖 βˆ™ 5𝑖 8. βˆ’2𝑖 βˆ™ 4𝑖 βˆ™ βˆ’6𝑖 βˆ™ 8𝑖 9. 𝑖9

10. 𝑖22 11. 𝑖75

Complex Numbers – Homework

Simplify using i.

12. βˆšβˆ’81 13. βˆšβˆ’121𝑏8 14. βˆšβˆ’18π‘Ž6

15. βˆšβˆ’48π‘₯5𝑦6 16. βˆšβˆ’9 βˆ™ βˆšβˆ’4 17. βˆšβˆ’12 βˆ™ βˆšβˆ’75

18. 2𝑖 βˆ™ 5𝑖 βˆ™ 7𝑖 19. βˆ’π‘– βˆ™ βˆ’3𝑖 βˆ™ βˆ’5𝑖 βˆ™ βˆ’7𝑖 20. 𝑖10

21. 𝑖23 22. 𝑖72

πŸ’π’Š πŸ”π’ƒπŸπ’Š πŸπ’‚π’ŠβˆšπŸ

πŸ’π’™πŸ‘π’šπŸ‘π’ŠβˆšπŸπ’š βˆ’πŸπŸŽ βˆ’πŸ’βˆšπŸ“

βˆ’πŸ”πŸŽπ’Š πŸ‘πŸ–πŸ’ π’Š

βˆ’πŸ βˆ’π’Š

πŸ—π’Š πŸπŸπ’ƒπŸ’π’Š πŸ‘π’‚πŸ‘π’ŠβˆšπŸ

πŸ’π’™πŸπ’šπŸ‘π’ŠβˆšπŸ‘π’™ βˆ’πŸ” βˆ’πŸ‘πŸŽ

βˆ’πŸ•πŸŽπ’Š πŸπŸŽπŸ“ βˆ’πŸ

βˆ’π’Š 𝟏

Page 2: Complex Numbers Class Work - content.njctl.org

Pre-Calc Polar & Complex #s ~2~ NJCTL.org

Adding, Subtracting, and Multiplying Complex Numbers – Class Work

Simplify

23. (6 + 5𝑖) + (4 + 3𝑖) 24. (7 + 4𝑖) + (βˆ’2 βˆ’ 2𝑖)

25. (βˆ’3 βˆ’ 2𝑖) + (3 βˆ’ 𝑖) 26. (6 + 5𝑖) βˆ’ (4 + 3𝑖)

27. (7 + 4𝑖) βˆ’ (βˆ’2 βˆ’ 2𝑖) 28. (βˆ’3 βˆ’ 2𝑖) βˆ’ (3 βˆ’ 𝑖)

29. 5(4 βˆ’ 2𝑖) 30. 2𝑖(βˆ’6 + 𝑖)

31. (6 + 5𝑖)(4 + 3𝑖) 32. (7 + 4𝑖)(βˆ’2 βˆ’ 2𝑖)

33. (βˆ’3 βˆ’ 2𝑖)(3 βˆ’ 𝑖) 34. (8 βˆ’ 3𝑖)(1 βˆ’ 𝑖)

35. (4 βˆ’ 2𝑖)2 36. (βˆ’6 + 𝑖)2

𝟏𝟎 + πŸ–π’Š πŸ“ + πŸπ’Š

βˆ’πŸ‘π’Š 𝟐 + πŸπ’Š

πŸ— + πŸ”π’Š βˆ’πŸ” βˆ’ π’Š

𝟐𝟎 βˆ’ πŸπŸŽπ’Š βˆ’πŸ βˆ’ πŸπŸπ’Š

πŸ— + πŸ‘πŸ–π’Š βˆ’πŸ” βˆ’ πŸπŸπ’Š

βˆ’πŸπŸ βˆ’ πŸ‘π’Š πŸ“ βˆ’ πŸπŸπ’Š

𝟏𝟐 βˆ’ πŸπŸ”π’Š πŸ‘πŸ“ βˆ’ πŸπŸπ’Š

Page 3: Complex Numbers Class Work - content.njctl.org

Pre-Calc Polar & Complex #s ~3~ NJCTL.org

Adding, Subtracting, and Multiplying Complex Numbers – Homework

Simplify

37. (2 + 3𝑖) + (8 + 2𝑖) 38. (4 + 9𝑖) + (βˆ’4 βˆ’ 9𝑖)

39. (10 βˆ’ 7𝑖) + (5 βˆ’ 3𝑖) 40. (2 + 3𝑖) βˆ’ (8 + 2𝑖)

41. (4 + 9𝑖) βˆ’ (βˆ’4 βˆ’ 9𝑖) 42. (10 βˆ’ 7𝑖) βˆ’ (5 βˆ’ 3𝑖)

43. 6(5 βˆ’ 6𝑖) 44. 2𝑖(4 βˆ’ 3𝑖)

45. (2 + 3𝑖)(8 + 2𝑖) 46. (4 + 9𝑖)(βˆ’4 βˆ’ 9𝑖)

47. (10 βˆ’ 7𝑖)(5 βˆ’ 3𝑖) 48. (βˆ’6 βˆ’ 𝑖)(2 βˆ’ 7𝑖)

49. (6 βˆ’ 3𝑖)2 50. (βˆ’7 + 2𝑖)2

𝟏𝟎 + πŸ“π’Š 𝟎

πŸπŸ“ βˆ’ πŸπŸŽπ’Š βˆ’πŸ” + π’Š

πŸ– + πŸπŸ–π’Š πŸ“ βˆ’ πŸ’π’Š

πŸ‘πŸŽ βˆ’ πŸ‘πŸ”π’Š πŸ” + πŸ–π’Š

𝟏𝟎 + πŸπŸ–π’Š πŸ”πŸ“ βˆ’ πŸ•πŸπ’Š

πŸπŸ— βˆ’ πŸ”πŸ“π’Š βˆ’πŸπŸ— + πŸ’πŸŽπ’Š

πŸπŸ• βˆ’ πŸ‘πŸ”π’Š πŸ’πŸ“ βˆ’ πŸπŸ–π’Š

Page 4: Complex Numbers Class Work - content.njctl.org

Pre-Calc Polar & Complex #s ~4~ NJCTL.org

Dividing Complex Numbers – Class Work

Simplify

51. 2

𝑖 52.

3

4𝑖 53.

βˆ’2

3𝑖

54. 2+𝑖

𝑖 55.

2

1+𝑖 56.

3

2βˆ’π‘–

57. 2+𝑖

3+𝑖 58.

4βˆ’π‘–

3βˆ’2𝑖

Dividing Complex Numbers – Homework

Simplify

59. 3

𝑖 60.

2

5𝑖 61.

βˆ’4

7𝑖

62. 4βˆ’π‘–

𝑖 63.

8

3+𝑖 64.

2𝑖

4βˆ’π‘–

65. 2βˆ’π‘–

2+3𝑖 66.

5βˆ’π‘–

4βˆ’3𝑖

βˆ’πŸπ’Š βˆ’πŸ‘

πŸ’π’Š

𝟐

πŸ‘π’Š

𝟏 βˆ’ πŸπ’Š 𝟏 βˆ’ π’Š πŸ”+πŸ‘π’Š

πŸ“

πŸ•+π’Š

𝟏𝟎

πŸπŸ’+πŸ“π’Š

πŸπŸ‘

βˆ’πŸ‘π’Š βˆ’πŸ

πŸ“π’Š

πŸ’

πŸ•π’Š

βˆ’πŸ βˆ’ πŸ’π’Š πŸπŸβˆ’πŸ’π’Š

πŸ“

βˆ’πŸ+πŸ–π’Š

πŸπŸ•

πŸβˆ’πŸ–π’Š

πŸπŸ‘

πŸπŸ‘+πŸπŸπ’Š

πŸπŸ“

Page 5: Complex Numbers Class Work - content.njctl.org

Pre-Calc Polar & Complex #s ~5~ NJCTL.org

Graphing Complex Numbers – Class Work

Determine the quadrant of each of the following.

67. 9 – 3i 68. -2 + 4i

69. (5 + 4i) – (6 – 3i) 70. -3i(4 – 5i)

71. (2 + 3i)2 72. 3βˆ’i

i

73. 2

4+i 74.

5βˆ’3i

2+4i

Homework

Determine the quadrant of each of the following.

75. -7 – 3i 76. 5 - 4i

77. (3 + 2i) – (-5 + 4i) 78. (3 – i)(-4 + 5i)

79. (-1 + 5i)2 80. βˆ’2βˆ’i

3i

81. 4

3βˆ’i 82.

βˆ’6+2i

3βˆ’2i

IV II

II III

II III

IV III

III IV

IV II

III II

I III

Page 6: Complex Numbers Class Work - content.njctl.org

Pre-Calc Polar & Complex #s ~6~ NJCTL.org

Polar Properties – Class Work

Name the point three other ways using polar coordinates.

83. [5,Ο€

2] 84. [βˆ’4,

2Ο€

3]

85. [3,βˆ’4Ο€

7] 86. [βˆ’6,0]

Convert the point to rectangular form.

87. [5,Ο€

2] 88. [βˆ’4,

2Ο€

3]

89. [3,βˆ’4Ο€

7] 90. [βˆ’6,0]

Convert the point to polar form.

91. ( 3, 6) 92. (-4, 2)

93. (1, 0) 94. (7, 7)

(βˆ’πŸ“,πŸ‘π…

𝟐) , (πŸ“, βˆ’

πŸ‘π…

𝟐) , (βˆ’πŸ“, βˆ’

𝝅

𝟐) (πŸ’,

πŸ“π…

πŸ‘) , (πŸ’, βˆ’

𝝅

πŸ‘) , (βˆ’πŸ’, βˆ’

πŸ’π…

πŸ‘)

(βˆ’πŸ‘, βˆ’πŸπŸπ…

πŸ•) , (βˆ’πŸ‘,

πŸ‘π…

πŸ•) , (πŸ‘,

πŸπŸŽπ…

πŸ•) (πŸ”, 𝝅), (πŸ”, βˆ’π…), (βˆ’πŸ”, πŸπ…)

(𝟎, πŸ“) (𝟐, βˆ’πŸβˆšπŸ‘)

(βˆ’πŸŽ. πŸ”πŸ”πŸ•πŸ”, βˆ’πŸ. πŸ—πŸπŸ’πŸ–) (βˆ’πŸ”, 𝟎)

(πŸ‘βˆšπŸ“, πŸ”πŸ‘. πŸ’π’) (πŸβˆšπŸ“, πŸπŸ“πŸ‘. πŸ’π’)

(𝟏, πŸŽπ’) (πŸ•βˆšπŸ, πŸ’πŸ“π’)

Page 7: Complex Numbers Class Work - content.njctl.org

Pre-Calc Polar & Complex #s ~7~ NJCTL.org

Polar Properties – Homework

Name the point three other ways using polar coordinates.

95. [7,Ο€

3] 96. [βˆ’6,

2Ο€

5]

97. [2,βˆ’3Ο€

5] 98. [3, πœ‹]

Convert the point to rectangular form.

99. [7,Ο€

3] 100. [βˆ’6,

2Ο€

5]

101. [2,βˆ’3Ο€

5] 102. [3, Ο€]

Convert the point to polar form.

103. ( -3, 2) 104. (-7, -8)

105. (5, 10) 106. (-7, 0)

(πŸ•, βˆ’πŸ“π…

πŸ‘) , (βˆ’πŸ•,

πŸ’π…

πŸ‘) , (βˆ’πŸ•, βˆ’

πŸπ…

πŸ‘) (πŸ”,

πŸ•π…

πŸ“) , (βˆ’πŸ”, βˆ’

πŸ–π…

πŸ“) , (πŸ”, βˆ’

πŸ‘π…

πŸ“)

(𝟐,πŸ•π…

πŸ“) , (βˆ’πŸ,

πŸπ…

πŸ“) , (βˆ’πŸ, βˆ’

πŸ–π…

πŸ“) (βˆ’πŸ‘, 𝟎), (βˆ’πŸ‘, πŸπ…), (πŸ‘, βˆ’π…)

(πŸ‘. πŸ“, πŸ”. πŸŽπŸ”πŸ) (βˆ’πŸ. πŸ–πŸ“πŸ’, βˆ’πŸ“. πŸ•πŸŽπŸ”)

(βˆ’πŸŽ. πŸ”πŸπŸ–, βˆ’πŸ. πŸ—πŸŽπŸ) (βˆ’πŸ‘, 𝟎)

(βˆšπŸπŸ‘, πŸπŸ’πŸ”. πŸ‘π’)

(πŸ“βˆšπŸ“, πŸ”πŸ‘. πŸ’π’)

(βˆšπŸπŸπŸ‘, πŸπŸπŸ–. πŸ–π’)

(πŸ•, πŸπŸ–πŸŽπ’)

Page 8: Complex Numbers Class Work - content.njctl.org

Pre-Calc Polar & Complex #s ~8~ NJCTL.org

Geometry of Complex Numbers – Class Work

Let a =3 + 4i and b= -2 + 5i, perform the operation and write the answer in complex, rectangular,

polar, and trigonometric forms.

107. a + b 108. b – a

109. ab 110. a2

111. b2 112. 3a2b

113. π‘Ž = 4(π‘π‘œπ‘ πœ‹

4+ 𝑖𝑠𝑖𝑛

πœ‹

4) and 𝑏 = 3(π‘π‘œπ‘ 

7πœ‹

6+ 𝑖𝑠𝑖𝑛

7πœ‹

6), find ab.

114. 𝑐 = [5,2πœ‹

5] and 𝑑 = [3,

4πœ‹

6], find cd. 115. Find z if z[10, 80Β°]= [15, 140Β°]

𝟏 + πŸ—π’Š

(𝟏, πŸ—)

(βˆšπŸ–πŸ, πŸ–πŸ‘. πŸ•π’)

βˆšπŸ–πŸ(𝐜𝐨𝐬 πŸ–πŸ‘. πŸ• + π’Š 𝐬𝐒𝐧 πŸ–πŸ‘. πŸ•)

βˆ’πŸ“ + π’Š

(βˆ’πŸ“, 𝟏)

(βˆšπŸπŸ”, πŸπŸ”πŸ–. πŸ•π’)

βˆšπŸπŸ”(𝐜𝐨𝐬 πŸπŸ”πŸ–. πŸ• + π’Š 𝐬𝐒𝐧 πŸπŸ”πŸ–. πŸ•)

βˆ’πŸπŸ” + πŸ•π’Š

(βˆ’πŸπŸ”, πŸ•)

(πŸ“βˆšπŸπŸ—, πŸπŸ”πŸ’. πŸ—π’)

πŸ“βˆšπŸπŸ—(𝐜𝐨𝐬 πŸπŸ”πŸ’. πŸ— + π’Š 𝐬𝐒𝐧 πŸπŸ”πŸ’. πŸ—)

βˆ’πŸ• + πŸπŸ’π’Š

(βˆ’πŸ•, πŸπŸ’)

(πŸπŸ“, πŸπŸŽπŸ”. πŸ‘π’)

πŸπŸ“(𝐜𝐨𝐬 πŸπŸŽπŸ”. πŸ‘ + π’Š 𝐬𝐒𝐧 πŸπŸŽπŸ”. πŸ‘)

βˆ’πŸπŸ βˆ’ πŸπŸŽπ’Š

(βˆ’πŸπŸ, βˆ’πŸπŸŽ)

(πŸπŸ—, πŸπŸπŸ‘. πŸ”π’)

πŸπŸ—(𝐜𝐨𝐬 πŸπŸπŸ‘. πŸ” + π’Š 𝐬𝐒𝐧 πŸπŸπŸ‘. πŸ”)

βˆ’πŸ‘πŸπŸ– βˆ’ πŸπŸ’πŸ—π’Š

(βˆ’πŸ‘πŸπŸ–, βˆ’πŸπŸ’πŸ—)

(πŸ•πŸ“βˆšπŸπŸ—, πŸπŸπŸ–. πŸπ’)

πŸ•πŸ“βˆšπŸπŸ—(𝐜𝐨𝐬 πŸπŸπŸ–. 𝟏 + π’Š 𝐬𝐒𝐧 πŸπŸπŸ–. 𝟏)

𝟏𝟐(πœπ¨π¬πŸπŸ•π…

𝟏𝟐+ π’Š 𝐬𝐒𝐧

πŸπŸ•π…

𝟏𝟐)

(πŸπŸ“,πŸπŸ”π…

πŸπŸ“) 𝒛 = (

πŸ‘

𝟐, πŸ”πŸŽπ’)

Page 9: Complex Numbers Class Work - content.njctl.org

Pre-Calc Polar & Complex #s ~9~ NJCTL.org

Geometry of Complex Numbers – Homework

Let a =7 - 3i and b= -3 - 8i, perform the operation and write the answer in complex, rectangular,

polar, and trigonometric forms.

116. a + b 117. a – b

118. b – a 119. ab

120. a2 121. b2

122. 3a 123. 3a2b

124. π‘Ž = 7(π‘π‘œπ‘ πœ‹

3+ 𝑖𝑠𝑖𝑛

πœ‹

3) and 𝑏 = 2(π‘π‘œπ‘ 

5πœ‹

6+ 𝑖𝑠𝑖𝑛

5πœ‹

6), find ab.

125. 𝑐 = [12,7πœ‹

4] and 𝑑 = [. 5,

5πœ‹

3], find cd. 126. Find z if z[20, 100Β°]= [15, 140Β°]

πŸ’ βˆ’ πŸπŸπ’Š

(πŸ’, βˆ’πŸπŸ)

(βˆšπŸπŸ‘πŸ•, πŸπŸ—πŸŽπ’)

βˆšπŸπŸ‘πŸ•(𝐜𝐨𝐬 πŸπŸ—πŸŽ + π’Š 𝐬𝐒𝐧 πŸπŸ—πŸŽ)

𝟏𝟎 + πŸ“π’Š

(𝟏𝟎, πŸ“)

(πŸ“βˆšπŸ“, πŸπŸ”. πŸ”π’)

πŸ“βˆšπŸ“(𝐜𝐨𝐬 πŸπŸ”. πŸ” + π’Š 𝐬𝐒𝐧 πŸπŸ”. πŸ”)

βˆ’πŸπŸŽ βˆ’ πŸ“π’Š

(βˆ’πŸπŸŽ, βˆ’πŸ“)

(πŸ“βˆšπŸ“, πŸπŸŽπŸ”. πŸ”π’)

πŸ“βˆšπŸ“(𝐜𝐨𝐬 πŸπŸŽπŸ”. πŸ” + π’Š 𝐬𝐒𝐧 πŸπŸŽπŸ”. πŸ”)

βˆ’πŸ’πŸ“ βˆ’ πŸ’πŸ•π’Š

(βˆ’πŸ’πŸ“, βˆ’πŸ’πŸ•)

(πŸ”πŸ“. 𝟏, πŸπŸπŸ”. πŸπ’)

πŸ”πŸ“. 𝟏(𝐜𝐨𝐬 πŸπŸπŸ”. 𝟐 + π’Š 𝐬𝐒𝐧 πŸπŸπŸ”. 𝟐)

πŸ’πŸŽ βˆ’ πŸ’πŸπ’Š

(πŸ’πŸŽ, βˆ’πŸ’πŸ)

(πŸ“πŸ–, πŸ‘πŸπŸ‘. πŸ”π’)

πŸ“πŸ–(𝐜𝐨𝐬 πŸ‘πŸπŸ‘. πŸ” + π’Š 𝐬𝐒𝐧 πŸ‘πŸπŸ‘. πŸ”)

βˆ’πŸ“πŸ“ + πŸ’πŸ–π’Š

(βˆ’πŸ“πŸ“, πŸ’πŸ–)

(πŸ•πŸ‘, πŸπŸ‘πŸ–. πŸ—π’)

πŸ•πŸ‘(𝐜𝐨𝐬 πŸπŸ‘πŸ–. πŸ— + π’Š 𝐬𝐒𝐧 πŸπŸ‘πŸ–. πŸ—)

𝟐𝟏 βˆ’ πŸ—π’Š

(𝟐𝟏, βˆ’πŸ—)

(πŸ‘βˆšπŸ“πŸ–, πŸ‘πŸ‘πŸ”. πŸ–π’)

πŸ‘βˆšπŸ“πŸ–(𝐜𝐨𝐬 πŸ‘πŸ‘πŸ”. πŸ– + π’Š 𝐬𝐒𝐧 πŸ‘πŸ‘πŸ”. πŸ–)

βˆ’πŸπŸ‘πŸ”πŸ– βˆ’ πŸ“πŸ–πŸπ’Š

(βˆ’πŸπŸ‘πŸ”πŸ–, βˆ’πŸ“πŸ–πŸ)

(πŸπŸ•πŸ’βˆšπŸ•πŸ‘, πŸπŸŽπŸ‘π’)

πŸπŸ•πŸ’βˆšπŸ•πŸ‘(𝐜𝐨𝐬 πŸπŸŽπŸ‘ + π’Š 𝐬𝐒𝐧 πŸπŸŽπŸ‘)

πŸπŸ’(πœπ¨π¬πŸ•π…

πŸ”+ π’Š 𝐬𝐒𝐧

πŸ•π…

πŸ”)

(πŸ”,πŸ’πŸπ…

𝟏𝟐) (

πŸ‘

πŸ’, πŸ’πŸŽπ’)

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Polar Equations and Graphs – Class Work

127. Draw the graph of π‘Ÿ = sin πœƒ 128. Draw the graph of π‘Ÿ = 3 + π‘π‘œπ‘ πœƒ

129. Draw the graph of π‘Ÿ = 5 130. Draw the graph of πœƒ =2πœ‹

3

131. Draw the graph of π‘Ÿπ‘π‘œπ‘ πœƒ = 6

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Polar Equations and Graphs – Homework

132. Draw the graph of π‘Ÿ = π‘π‘œπ‘ πœƒ 133. Draw the graph of π‘Ÿ = 4 + π‘ π‘–π‘›πœƒ

134. Draw the graph of π‘Ÿ = βˆ’5 135. Draw the graph of πœƒ =3πœ‹

4

136. Draw the graph of π‘Ÿπ‘ π‘–π‘›πœƒ = βˆ’6

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Rose Curves and Spirals – Class Work

137. How many petals and what is a petals length for π‘Ÿ = 4π‘π‘œπ‘ 3πœƒ? Draw the graph.

138. How many petals and what is a petals length for π‘Ÿ = 5𝑠𝑖𝑛6πœƒ? Draw the graph.

139. How many petals and what is a petals length for π‘Ÿ = 2π‘π‘œπ‘ 4πœƒ? Draw the graph.

140. How many petals and what is a petals length for π‘Ÿ = 7π‘π‘œπ‘ 5πœƒ? Draw the graph.

141. What kind of spiral is π‘Ÿ = 3πœƒ? 142. What kind of spiral is π‘Ÿ = 2πœƒ + 2?

3 petals

length: 4

12 petals

length: 5

8 petals

length: 2

5 petals

length: 7

Logarithmic Archimedes

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Rose Curves and Spirals – Homework

143. How many petals and what is a petals length for π‘Ÿ = 6π‘π‘œπ‘ 2πœƒ? Draw the graph.

144. How many petals and what is a petals length for π‘Ÿ = 4𝑠𝑖𝑛7πœƒ? Draw the graph.

145. How many petals and what is a petals length for π‘Ÿ = 3π‘π‘œπ‘ 6πœƒ? Draw the graph.

146. How many petals and what is a petals length for π‘Ÿ = 5π‘π‘œπ‘ 3πœƒ? Draw the graph.

147. What kind of spiral is π‘Ÿ = 2πœƒ? 148. What kind of spiral is π‘Ÿ = 3πœƒ + 1?

4 petals

length: 6

7 petals

length: 4

12 petals

length: 3

3 petals

length: 5

Logarithmic Archimedes

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Powers of Complex Numbers – Class Work

Compute the given power and write your answer in the original form.

149. ([3,60Β°])5 150. (4 (π‘π‘œπ‘ πœ‹

5+ 𝑖𝑠𝑖𝑛

πœ‹

5))

7

151. (5 βˆ’ 6𝑖)6 152. (βˆ’5,9)8

153. If a tenth root of w is (3,8) what is w?

Homework

Compute the given power and write your answer in the original form.

154. ([9,80Β°])7 155. (5 (π‘π‘œπ‘ 4πœ‹

3+ 𝑖𝑠𝑖𝑛

4πœ‹

3))

9

156. (βˆ’4 + 7𝑖)8 157. (βˆ’7, βˆ’3)10

158. If a sixth root of w is 7(π‘π‘œπ‘ 0 + 𝑖𝑠𝑖𝑛0) what is w?

(πŸπŸ’πŸ‘, πŸ‘πŸŽπŸŽπ’) πŸπŸ”πŸ‘πŸ–πŸ’( πœπ¨π¬πŸ•π…

πŸ“+ π’Š 𝐬𝐒𝐧

πŸ•π…

πŸ“)

πŸπŸπŸ•πŸ’πŸ”πŸ— + πŸπŸ—πŸ’πŸπŸπŸŽπ’Š (βˆ’πŸ•πŸ”πŸ—πŸ”πŸ“πŸπŸŽπŸ’, βˆ’πŸπŸŽπŸŽπŸŽπŸ•πŸ’πŸπŸ’πŸŽ)

(πŸπŸ–πŸ•πŸŽπŸπŸ–πŸπŸπŸπŸ“, βˆ’πŸ–πŸ—πŸ’πŸ’πŸ“πŸ’πŸŽπŸ‘πŸ)

(πŸ’πŸ•πŸ–πŸπŸ—πŸ”πŸ—, πŸπŸŽπŸŽπ’) πŸπŸ—πŸ“πŸ‘πŸπŸπŸ“( 𝐜𝐨𝐬 πŸπ… + π’Š 𝐬𝐒𝐧 πŸπ…)

βˆ’πŸ—πŸ’πŸ•πŸŽπŸπŸŽπŸ• βˆ’ πŸπŸ“πŸπŸ‘πŸπŸ’πŸπŸ’π’Š (βˆ’πŸ’πŸŽπŸ’πŸπŸπŸŽπŸ–πŸŽπŸŽ, βˆ’πŸ“πŸπŸ•πŸπŸπŸ”πŸ•πŸ”πŸ–)

πŸπŸπŸ•πŸ”πŸ’πŸ—(𝐜𝐨𝐬 𝟎 + π’Š 𝐬𝐒𝐧 𝟎)

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Roots of Complex Numbers – Class Work

Find the given roots and write the answer in the same form as the original.

159. fifth root of [3,60Β°] 160. fourth root of 4 (π‘π‘œπ‘ πœ‹

5+ 𝑖𝑠𝑖𝑛

πœ‹

5)

161. sixth root of 5 βˆ’ 6𝑖 162. eighth root of (βˆ’5,9)

163. a to the fourth is √3(cos 20Β° + 𝑖𝑠𝑖𝑛 20Β°), find a

(𝟏. πŸπŸ’πŸ”, πŸπŸπ’)

(𝟏. πŸπŸ’πŸ”, πŸ–πŸ’π’)

(𝟏. πŸπŸ’πŸ”, πŸπŸ“πŸ”π’)

(𝟏. πŸπŸ’πŸ”, πŸπŸπŸ–π’)

(𝟏. πŸπŸ’πŸ”, πŸ‘πŸŽπŸŽπ’)

𝟏. πŸ’πŸπŸ’ (πœπ¨π¬π…

𝟐𝟎+ π’Š 𝐬𝐒𝐧

𝝅

𝟐𝟎)

𝟏. πŸ’πŸπŸ’ (πœπ¨π¬πŸπŸπ…

𝟐𝟎+ π’Š 𝐬𝐒𝐧

πŸπŸπ…

𝟐𝟎)

𝟏. πŸ’πŸπŸ’ (πœπ¨π¬πŸπŸπ…

𝟐𝟎+ π’Š 𝐬𝐒𝐧

πŸπŸπ…

𝟐𝟎)

𝟏. πŸ’πŸπŸ’ (πœπ¨π¬πŸ‘πŸπ…

𝟐𝟎+ π’Š 𝐬𝐒𝐧

πŸ‘πŸπ…

𝟐𝟎)

. πŸ–πŸ•πŸ“ + 𝟏. πŸπŸŽπŸ“π’Š

βˆ’. πŸ“πŸπŸ— + 𝟏. πŸ‘πŸπ’Š

βˆ’πŸ. πŸ‘πŸ—πŸ’+. πŸπŸŽπŸ“π’Š

βˆ’. πŸ–πŸ•πŸ“ βˆ’ 𝟏. πŸπŸŽπŸ“π’Š

. πŸ“πŸπŸ— βˆ’ 𝟏. πŸ‘πŸπ’Š

𝟏. πŸ‘πŸ—πŸ’βˆ’. πŸπŸŽπŸ“π’Š

(𝟏. πŸπŸ—πŸ‘, 𝟎. πŸ‘πŸ’πŸ’)

(. πŸ”πŸ•πŸ, 𝟏. πŸπŸ“πŸ•)

(βˆ’. πŸ‘πŸ’πŸ’, 𝟏. πŸπŸ—πŸ‘)

(βˆ’πŸ. πŸπŸ“πŸ•, 𝟎. πŸ”πŸ•πŸ)

(βˆ’πŸ. πŸπŸ—πŸ‘, βˆ’πŸŽ. πŸ‘πŸ’πŸ’)

(βˆ’. πŸ”πŸ•πŸ, βˆ’πŸ. πŸπŸ“πŸ•)

(. πŸ‘πŸ’πŸ’, βˆ’πŸ. πŸπŸ—πŸ‘)

(βˆ’. πŸ”πŸ•πŸ, 𝟏. πŸπŸ“πŸ•)

𝟏. πŸπŸ’πŸ•(𝐜𝐨𝐬 πŸ“Β° + π’Š 𝐬𝐒𝐧 πŸ“Β°)

𝟏. πŸπŸ’πŸ•(𝐜𝐨𝐬 πŸ—πŸ“Β° + π’Š 𝐬𝐒𝐧 πŸ—πŸ“Β°)

𝟏. πŸπŸ’πŸ•(𝐜𝐨𝐬 πŸπŸ–πŸ“Β° + π’Š 𝐬𝐒𝐧 πŸπŸ–πŸ“Β°)

𝟏. πŸπŸ’πŸ•(𝐜𝐨𝐬 πŸπŸ•πŸ“Β° + π’Š 𝐬𝐒𝐧 πŸπŸ•πŸ“Β°)

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Homework

Find the given roots and write the answer in the same form as the original.

164. fifth root of [9,80Β°] 165. fourth root of 5 (π‘π‘œπ‘ 4πœ‹

3+ 𝑖𝑠𝑖𝑛

4πœ‹

3)

166. sixth root of (βˆ’4 + 7𝑖) 167. eighth root of (βˆ’7, βˆ’3)

168. a to the sixth is √3(cos 30Β° + 𝑖𝑠𝑖𝑛 30Β°), find a

(𝟏. πŸ“πŸ“, πŸπŸ”π’)

(𝟏. πŸ“πŸ“, πŸ–πŸ–π’)

(𝟏. πŸ“πŸ“, πŸπŸ”πŸŽπ’)

(𝟏. πŸ“πŸ“, πŸπŸ‘πŸπ’)

(𝟏. πŸ“πŸ“, πŸ‘πŸŽπŸ’π’)

𝟏. πŸ’πŸ—πŸ“ (πœπ¨π¬π…

πŸ‘+ π’Š 𝐬𝐒𝐧

𝝅

πŸ‘)

𝟏. πŸ’πŸ—πŸ“ (πœπ¨π¬πŸ“π…

πŸ”+ π’Š 𝐬𝐒𝐧

πŸ“π…

πŸ”)

𝟏. πŸ’πŸ—πŸ“ (πœπ¨π¬πŸ’π…

πŸ‘+ π’Š 𝐬𝐒𝐧

πŸ’π…

πŸ‘)

𝟏. πŸ’πŸ—πŸ“ (πœπ¨π¬πŸπŸπ…

πŸ”+ π’Š 𝐬𝐒𝐧

πŸπŸπ…

πŸ”)

(𝟏. πŸ‘πŸ‘πŸ + 𝟎. πŸ’πŸ–πŸ‘π’Š)

(𝟎. πŸπŸ’πŸ• + 𝟏. πŸ‘πŸ—πŸ’π’Š)

(βˆ’πŸ. πŸŽπŸ–πŸ’ + 𝟎. πŸ—πŸπŸπ’Š)

(βˆ’πŸ. πŸ‘πŸ‘πŸ βˆ’ 𝟎. πŸ’πŸ–πŸ‘π’Š)

(βˆ’πŸŽ. πŸπŸ’πŸ• βˆ’ 𝟏. πŸ‘πŸ—πŸ’π’Š)

(𝟏. πŸŽπŸ–πŸ’ βˆ’ 𝟎. πŸ—πŸπŸπ’Š)

(𝟏. πŸπŸ–πŸ•, 𝟎. πŸŽπŸ”πŸ“)

(𝟎. πŸ–πŸ”πŸ’, 𝟎. πŸ—πŸ“πŸ”)

(βˆ’πŸŽ. πŸŽπŸ”πŸ“, 𝟏. πŸπŸ–πŸ•)

(βˆ’πŸŽ. πŸ—πŸ“πŸ”, 𝟎. πŸ–πŸ”πŸ’)

(βˆ’πŸ. πŸπŸ–πŸ•, βˆ’πŸŽ. πŸŽπŸ”πŸ“)

(βˆ’πŸŽ. πŸ–πŸ”πŸ’, βˆ’πŸŽ. πŸ—πŸ“πŸ”)

(𝟎. πŸŽπŸ”πŸ“, βˆ’πŸ. πŸπŸ–πŸ•)

(𝟎. πŸ—πŸ“πŸ”, βˆ’πŸŽ. πŸ–πŸ”πŸ’)

𝟏. πŸŽπŸ—πŸ”(𝐜𝐨𝐬 πŸ“Β° + π’Š 𝐬𝐒𝐧 πŸ“Β°)

𝟏. πŸŽπŸ—πŸ”(𝐜𝐨𝐬 πŸ”πŸ“Β° + 𝐒 𝐬𝐒𝐧 πŸ”πŸ“Β°)

𝟏. πŸŽπŸ—πŸ”(𝐜𝐨𝐬 πŸπŸπŸ“Β° + 𝐒 𝐬𝐒𝐧 πŸπŸπŸ“Β°)

𝟏. πŸŽπŸ—πŸ”(𝐜𝐨𝐬 πŸπŸ–πŸ“Β° + 𝐒 𝐬𝐒𝐧 πŸπŸ–πŸ“Β°)

𝟏. πŸŽπŸ—πŸ”(𝐜𝐨𝐬 πŸπŸ’πŸ“Β° + 𝐒 𝐬𝐒𝐧 πŸπŸ’πŸ“Β°)

𝟏. πŸŽπŸ—πŸ”(𝐜𝐨𝐬 πŸ‘πŸŽπŸ“Β° + 𝐒 𝐬𝐒𝐧 πŸ‘πŸŽπŸ“Β°)

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Polar and Complex Numbers Unit Review

Multiple Choice

1. Simplify: βˆ’4𝑖 βˆ™ 6𝑖 βˆ™ βˆ’2𝑖 βˆ™ βˆ’π‘–

a. -48i

b. 48i

c. -48

d. 48

2. Simplify: (6 βˆ’ 𝑖)2

a. 35 + 12i

b. 35 - 12i

c. 37 - 12i

d. 37 + 12i

3. Simplify: 3βˆ’π‘–

4βˆ’2𝑖

a. 7

10+

1

10i

b. 7

6+

1

6i

c. 7

10βˆ’

1

10i

d. 7

6βˆ’

1

6i

4. What quadrant is (6 + 2i) – (7 – 4i) in?

a. I

b. II

c. III

d. IV

5. What quadrant is (3 - 5i)2 in?

a. I

b. II

c. III

d. IV

6. What quadrant is 3βˆ’π‘–

4βˆ’2𝑖 in?

a. I

b. II

c. III

d. IV

7. Which of the point choices listed are not equal to: [5,Ο€

2]

a. (0,5)

b. 5(π‘π‘œπ‘ πœ‹

2+ 𝑖𝑠𝑖𝑛

πœ‹

2)

c. [βˆ’5,3Ο€

2]

d. they are all equivalent

C

C

A

B

C

A

D

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8. Convert the point to rectangular form: [4,Ο€

3]

a. (2,√3

2)

b. (√3

2, 2)

c. (2,√3)

d. (2,2√3)

9. Convert the point to polar form: ( 2.5 , 6)

a. (6.5, 0.395)

b. (6.5 , 1.176Β°)

c. (6.5 , 22.620Β°)

d. (6.5, 67.380Β°)

10. Let a =8 - 2i and b= -5 - 7i, which of the following is not a + b?

a. (3,-9)

b. [3√10, βˆ’71.565]

c. 10(cos 288.435Β° + i sin 288.435Β°)

d. –( -3 + 9i)

11. π‘Ž = 6(π‘π‘œπ‘ πœ‹

4+ 𝑖𝑠𝑖𝑛

πœ‹

4) and 𝑏 = βˆ’3(π‘π‘œπ‘ 

5πœ‹

3+ 𝑖𝑠𝑖𝑛

5πœ‹

3), find ab.

a. βˆ’18(π‘π‘œπ‘ 6πœ‹

7+ 𝑖𝑠𝑖𝑛

6πœ‹

7)

b. βˆ’18(π‘π‘œπ‘ 5πœ‹

12+ 𝑖𝑠𝑖𝑛

5πœ‹

12)

c. βˆ’18(π‘π‘œπ‘ 17πœ‹

12+ 𝑖𝑠𝑖𝑛

17πœ‹

12)

d. βˆ’18(π‘π‘œπ‘ 23πœ‹

12+ 𝑖𝑠𝑖𝑛

23πœ‹

12)

12. How many petals and what is a petals length for π‘Ÿ = 4π‘π‘œπ‘ 8πœƒ?

a. 4 petals, length 8

b. 8 petals, length 4

c. 8 petals, length 8

d. 16 petals, length 4

13. Compute: (7 βˆ’ 3𝑖)6

a. ( 195112, 220.809Β°)

b. ( 45.694, 220.809Β°)

c. ( 195112, 1.871πœ‹)

d. ( 45.694, 1.871πœ‹)

14. If a tenth root of w is [5,2πœ‹

3], what is w?

a. [50,20Ο€

3]

b. [9765625,20Ο€

3]

c. [50,4Ο€

3]

d. [9765625,4Ο€

3]

D

D

C

D

D

A

B

Page 19: Complex Numbers Class Work - content.njctl.org

Pre-Calc Polar & Complex #s ~19~ NJCTL.org

15. Find the third root of 27 (π‘π‘œπ‘ πœ‹

2βˆ’ 𝑖𝑠𝑖𝑛

πœ‹

2)

a. [3,Ο€

6]

b. [3,Ο€+4kΟ€

6] for k ∈ {1,2}

c. [3,4+kΟ€

6] for k ∈ {1,2,3}

d. [3,Ο€+4kΟ€

6] for k ∈ {0,1,2}

Extended Response

16. Let a =8 - 2i and b= -5 - 7i.

a. Find 3a2b.

b. How far from the origin is a + b?

c. What is the angle of rotation of a+b?

17. Write an equation

a. for a rose curve with 8 petals of length 5

b. for a rose curve with 5 petals of length 6

c. a Spiral of Archimedes with 6πœ‹ between the spirals

D

βˆ’πŸπŸ“πŸ•πŸ βˆ’ πŸ•πŸ–πŸŽπ’Š

πŸ‘βˆšπŸπŸŽ

πŸπŸ–πŸ–. πŸ’πŸ‘π’

𝒓 = πŸ“ 𝐜𝐨𝐬 πŸ’πœ½ 𝒐𝒓 𝒓 = πŸ“ 𝐬𝐒𝐧 πŸ’πœ½

𝒓 = πŸ” 𝐜𝐨𝐬 πŸ“πœ½ 𝒐𝒓 𝒓 = πŸ” 𝐬𝐒𝐧 πŸ“πœ½

𝒓 = πŸ‘πœ½ + π’Œ 𝒇𝒐𝒓 π’Œ β‰₯ 𝟏