placas 1
Post on 23-Dec-2015
2 Views
Preview:
DESCRIPTION
TRANSCRIPT
Parques Alta
Diseño de placas en la dirección XCálculo de cortante sísmico:
Parámetros sísmicos;
Z = 0.4
U = 1.5
C = 2.5
S = 1.2
R = 6
P = 817.49 T
Vu = 245.25 T
L = Vu = 10.22 m
0.53*f'c^0.5*t
0.80*L = 8.17 m
Consideramos por medidas arquitectónicas:
Placa 1 = 4.75 m (incluidas las columnas)
Placa 2 = 3.50 m (incluidas las columnas)
Total = 8.25 m
Pu = 227.64
Mu = 216.95
Vu = 38.42
hm = 10.8
Lm = 4.15
F = 52.28 T
As = F/fy = 12.45 cm2
8 φ 5/8" = 15.84 cm2
Acero en la placa
ph min = 0.0025
As / 100t = 6.25 cm2/m
espaciamiento s = L/5 = 83 cm
3*t = 75 cm
As hor: 2 capas de 3/8" @25cm
acero vertical:
0.0025
6.25 cm2/m
As ver: 2 capas de 3/8" @25cm
Vu = Vua*(Mur/Mua) = 142.04 T
Vu < 2.6 t d f'c^0.5 = 312.72 T
ok
Vc = 0.53*t*d*f'c^0.5 = 63.75 T
Vu > φVc 245.25 T
Vs =Vu/φ - Vc = 103.35 T
s = Avfyd/Vs = 19.16 cm
3/8 @20cm en ambos sentidos
top related