funciones (1)
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7/18/2019 funciones (1)
http://slidepdf.com/reader/full/funciones-1-5696e6c0ef947 1/2
function [xr,iter,ea]=biseccion(f,xl,xu,es,imax)iter=0;f=inline(f);xr=(xl+xu)/2;
while iter<imax || es<ea xrold=xr; xr=(xl+xu)/2; iter=iter+1; if xr~=0 ea=abs(((xr-xrold)/xr)*100); end fr=f(xr); fprintf('\n%3.0f %3.5f %3.5f %3.5f %3.5f\n',iter,xl,xu,xr,fr) if f(xl)*fr<0; xu=xr; elseif f(xl)*fr>0 xl=xr;
else ea=0; end end
end
function [ xr ] = newton_rap( f,x0,imaxn,EPS,EPS1)sym('x');df=diff(f,'x');f=inline(f);df=inline(df);
i=0;fprintf('\n it x Ea \n')while i<imaxn; i=i+1; xr=x0-(f(x0)/df(x0));
Ea= abs(xr-x0); fprintf('\n %3.2f %3.6f %3.6f \n',i,xr,Ea)
if abs(xr-x0)<EPS break end if abs(f(xr))<EPS1
break end x0=xr;endif i>=imaxn fprintf('\n\n el metodo no converge \n\n')end end
7/18/2019 funciones (1)
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function [ xr] = secante(f,x0,x1,imaxs,EPS,EPS1 )sym x;f=inline(f);i=1;xrold=0;fprintf('\n it x0 x1 xr ea\n');while i<imaxs ; xr=x0-((x1-x0)*f(x0))/(f(x1)-f(x0)); ea=abs((xr-xrold)/xr); fprintf('\n %3.2f %3.5f %3.5f %3.8f %3.8f \n',i,x0,x1,xr,ea); if abs(xr-x1)<EPS ; fprintf (' La raiz xr= %3.8f \n',xr);
breakend
if abs(f(xr))<EPS1;
fprintf (' La raiz xr= %3.8f \n',xr); break end
x0=x1; x1=xr; xrold=xr; i=i+1; if i>=imaxs; fprintf('Numero excedido de iteraciones\n'); endend
end
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