zapata exterior 2
DESCRIPTION
FdADadTRANSCRIPT
viga DISEO DE ZAPATA EXTERIOR CON EXCENTRICIDADA VARIABLE
ZAPATA INTERIORZAPATA EXTERIOR=2.00cmPD=54.43TnPD=30.12TnPD =0.00TonPL=19.0505TnPL=10.28Tn2 2PL =0.00TonPS =0.00Tonkg/cm2MD =0.00Ton-mML =0.00Ton-mMS =0.00Ton-m
COL:b=0.40mCOL:b=0.40mgS =0.00Ton/m3h=0.25mh=0.25mqa =1.8Kgr/cm2Longitud de viga entre ejes = 3.8mf'c =0Kgr/cm2gS=1600kg/m3fy =0Kgr/cm2qa=2kg/cm2r =0.00mfy=4200kg/cm2hs =0.00mf'c=210kg/cm2COL =b=0.00h=0.00r=0.1mhs=2mLong=3.8mDIMENSIONAMIENTO DE LA VIGA DE CONEXIN
40.4= 0.44mASUMIMOSVIGA DE24x 3.80b =50cm= 0.50CONEXIN3.80= 0.48mh =50cm8= 0.50Peso propio de Viga = gc x b x h =0.50mx 0.50x 2.40= 0.60Tn/m
40.40Tn
ZAPATA EXTERIOR
ASUMIMOS Re=1.25xP1 =Re =1.25x40.40=50.50Tn
ASUMIMOS PERALTE DELA ZAPATA EXTERIOR
ASUMIMOS t=40cmqe=qa - gs*hs - gc*hc=20.0- 1.60x 2.0- 2.40x 0.4= 15.8Tn/cm2
AREA DE LA ZAPATA50.50=3.19m215.84DIMENSIONAMIENTO DE LA ZAPATATANTEANDOZap. ExteriorAREAB =1.13mA=3.19ASUMIMOS B =1.50m4.50m2L =2.82mL =3.00m
PARA ESTAS DIMENSIONES CHEQUEAMOS Re QUE SATISFAGA EL EQUILIBRIO MO=0 Re *( Lvig + bcol/2 - B/2 ) - ( P1* Lvig ) - (P.Pviga * Lvig ^2/2) = 0Re *( 3.80+0.20 -0.75) -( 40.40x3.80)- (0.60x7.22) = 0
Re = 48.57Ton
PRESION TOTAL SOBRE LA ZAPATA
Peso propio de zapata = gc xB xL xt =2.40x 1.50x 3.00x 0.40= 4.32Ton
Se debe verificar48.57+ 4.32=11.75