∫ 4

x3dx+∫ √ x

x3d x

=4∫ 1

x3+∫1 x−5 /2

x−2

−2+ x

−3/2

−32

−42x2

− 2

3 x3 /2+c

−12x32−4 x2

6(x2)(x32 )

−4 (3 x32−x2)

6 (x2)(x32)

−2(3 x32−x2)

3(x2)( x32 )

−2(3 x32−x2)

3(x2)( x32 )

−2x32 (3+x2)

3(x2)(x32 )

−2(3+x1/2)3 x2

−2(√ x+3)3 x2

+c