problema 11
DESCRIPTION
ejerccio de estucturaTRANSCRIPT
∑ fy=0↔Ray+Rby=12T +2T
Ray+Rby=14 T….¿0
∑MA=0↔Rby (6 )−12T (3 )−2T (3 )=0
Rby (6 )−36T−6T=0
Rby (6)−42T=0
Rby=7T….¿1
Reemplazando(¿¿¿1)en (¿¿¿0)¿¿
Ray+7T=14T
Ray=7T
Calculamos diagramsde fuerzacortante V ( x ) y momento flector M (x ) .
∑ fy=0↔7−2 x−V ( x )=0
V ( x )=7−2x
∑M=0↔M ( x )+2 x . x2−7 x=0
M (x )=7 x−x2
∑ fy=0↔7−2x−2−V ( x )=0
5−2x−V ( x )=0
V ( x )=5−2 x
∑M=0↔M ( x )+2 ( x−3 )+2 x . x2−7 x=0
M (x )=−x2+5 x+6