PRACTICA 2-3

SISTEMA 1

µ= mi –mf

0. µ=25-25 = 0

1. µ= 25 -24.99 = 0.01

2. µ=24.99 – 24.75 = 0.24

3. µ= 24.75 – 24.59 = 0.16

4. µ= 24.59 -24.48 = 0.11

5. µ= 24.48 – 24.28 = 0.20

6. µ= 24.28 – 24.07 = 0.21

7. µ= 24.07– 23.93 = 0.14

8. µ=23.93 – 23.78 = 0.15

9. µ= 23.78 – 23.48 = 0.3

SISTEMA 2

µ= mi –mf Maz=MsolBx

x100

0. µ=25-25 = 0 Maz=255x100=500

1. µ= 25 -24.93 = 0.07 Maz=24.935

x100=498.2

2. µ=24.93 – 24.89 = 0.04 Maz=24.895

x 100=497.8

3. µ= 24.89 – 24.56 = 0.33 Maz=24.564.9

x100=501.2

4. µ= 24.56 -24.33 = 0.11 Maz=24.334.8

x100=486

5. µ= 24.33 – 23.88 = 0.23 Maz=23.884.7

x100=508

6. µ= 23.88 – 23.62 = 0.45 Maz=23.624.6

x 100=513.5

7. µ= 23.62– 23.25 = 0.26 Maz=23.254.4

x100=528.4

8. µ= 23.25 – 22.94 = 0.31 Maz=22.944.4

x100=521.4

9. µ= 22.94 – 22.69 = 0.25 Maz=22.694.4

x 100=515.7

HALLAR Masaº AA, g

1. 100ml x ( 0,5mol1000ml )=0,05mol → 0.05mol ( 60 g1mol ) x100=3ga .a

2. 100ml x ( 0,25mol1000ml )=0,025mol →

0,025mol ( 60 g1mol ) x100=1.5ga .a

3. 100ml x ( 0,125mol1000ml )=0,0125mol →

0,0125mol ( 60 g1mol ) x100=0.75g a .a

4. 100ml x ( 0,0625mol1000ml )=0,00625mol →

0,00625mol ( 60 g1mol ) x100=0.375g a .a

5. 100ml x ( 0,03125mol1000ml )=0,003125mol →

0,003125mol ( 60 g1mol ) x100=0.1875g a .a

6. 100ml x ( 0,015625mol1000ml )=0,0015625mol →

0,0015625ol( 60g1mol )x 100=0.09375 ga .a

HALLANDO MASA AA

1. 0.0461 L (NaOH ) x ( 0,1mol1l )=0,00461 (NaOH )mol →

0,00461mol60 g1mol

=0.2766g

2. 0,0224 L (NaOH ) x ( 0,1mol1 l )=0,00224 (NaOH )mol →

0,00224mol60 g1mol

=0.1314 g

3. 0.0111 L (NaOH ) x ( 0,1mol1l )=0.00111 (NaOH )mol →

0.00111mol60 g1mol

=0.0666g

4. 0.0057 L (NaOH ) x ( 0,1mol1 l )=0.00057 (NaOH )mol →

0.00057mol60g1mol

=0.0342 g

5. 0.0023 L (NaOH ) x ( 0,1mol1 l )=0.00023 (NaOH )mol →

0.00023mol60g1mol

=0.0138 g

6. 0.0012 L (NaOH ) x ( 0,1mol1l )=0.00012 (NaOH )mol →

0.00012mol60 g1mol

=0.0072g

HALLANDO Cl ( g.AA/L)

1. 0.2766 g x1000ml100ml x1 L

=2,766 g/ l

2. 0.1344 g x1000ml100ml x 1L

=1.344 g /l

3. 0.0666 g x1000ml100ml x1 L

=0.666 g❑ l

4. 0.0342 gx1000ml100ml x1 L

=0.342 g❑ l

5. 0.0138 g x1000ml100ml x1 L

=0.138 g❑ l

6. 0.0072 gx1000ml100ml x1 L

=0.072g /l

HALLANDO

MASAº AA.g - MASA AA,g

1. 3 g – 0,2766 g = 2.7234 g Cs= 2.7234 g1 gde PAC

=2.7234 g de PAC

2. 1.5 g - 0.1344 g = 1.3656 g Cs= 1.3656g1 gde PAC

=1.3656 gde PAC

3. 0.75 g – 0.0666 g = 0.6834 g Cs= 0.6834 g1 gde PAC

=2.7234 g de PAC

4. 0.375 g - 0.0342 g = 0.3408 g Cs= 0.3408g1 gde PAC

=2.7234 g de PAC

5. 0.1875 g – 0.0138 g = 0.1737 g Cs= 0.1737g1 gde PAC

=2.7234 g de PAC

6. 0.09375 g – 0.0072 g = 0.08655 g Cs= 0.08655g1 gde PAC

=2.7234 g de PAC