planta
DESCRIPTION
cyclopadTRANSCRIPT
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TALLER CICLO COMBINADO MODIFICADOUNIVERSIDAD NACIONAL DE COLOMBIA
Sede BogotPlantas Temicas
Ciclo Joue-Brayton
T1 25 C RPcom 8P1 120 kPa kaire 1.4
cpaire 1000 Jkg Kmgas 42
kgs
P2 =P1 RPcom 9.6 105 Pa P3 P2
T2 =T1 P2P1
kaire 1kaire
540.083 K
Qcal cpaire mgas (( T3 T2)) Qcal 43 MW
cpgas 1100 Jkg KT3 =+
Qcalcpaire mgas
T2 1.564 103 Kkgas 1.3
Wturb1 23 MW
T4 =+Wturb1
cpgas mgasT3 1.066 103 K
P4 =
T3T4
kgaskgas 1
P3
1
1.824 105 Pa
Wcomp1 =(( T2 T1)) cpaire mgas 1.016 107 W T5 540 C
P5 P4
Ciclo Rankin
T6 500 CP6 60 bar P7 40 barh6 3422
Jgm
P7s P7
s6 6.88 J
gm Ks7s s6 h7s 3290
Jgm
2
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sth %90 sth h6 h7h6 h7s
h7 =h6 sth h6 h7s 3.303 106
m2
s2
T7 438 C
T8 550 CP8 P7h8 3559
Jgms8 7.23
Jgm K
P9 8 bar stl %75
s9s s8 h9s 3054 J
gm
h9 =h8 h8 h9s stl 3.18 106
m2
s2T9 358 C s9 7.43
Jgm K
P10 1 bar
s10s s9 h10s 2688 J
gm
h10 =h9 h9 h10s stl 2.811 106
m2
s2T10 167 C s10 7.69
Jgm K
P11 0.08 bar
s11s s10 h11s 2407.13 J
gm
h11 =h10 h10 h11s stl 2.508 106
m2
s2T11 41.5 C s11 8.01
Jgm K
Tomando que a lasalida del intercambiadr cerrado (punto 22), liquido saturado
P22 P10T22 99.6 Ch22 417.5
Jgm
h14 h22P14 P11T14 41.5 Csq14 %10.14
Tomando 16 como liquido saturado
P16 P9 P17 P6h16 720.864
Jgm
T16 170.406 Cv16 0.00111
m3
kg
W h dv p vp
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W h dv p vp
h17 =+h16 v16 (( P17 P16)) 7.266 105 m2
s2T17 171.069 C
Tomando 19 como liquido saturado
P19 P7 P20 P6h19 1087.5
Jgm
T19 250.35 C Suponiendo que el intercambiador T18 T19
v19 0.00125 m3
kgP18 60 barh18 1087.45 J
gm
m (( 1 x1)) (( h19 h7)) m x1 (( h18 h17))
x1 =h7 h19
+h18 h17 h7 h190.86
W h dv p vp
h20 =+h19 v19 (( P20 P19)) 1.09 106 m2
s2T20 250.88 C
Suponiendo que el fluido en 12 sale saturado
P12 P11 P13 P9
h12 173.84 J
gm
v12 0.00101 m3
kg
T12 41.5 C
h13 =+h12 v12 (( P13 P12)) 1.746 105 m2
s2T13 41.52 C
Suponiendo que a la salidaa del intercambiador T22=T15
P15 8 barT15 T22
h15 418 J
gm
m x1 x2 (( 1 x3)) (( h22 h10)) m x1 x2 (( h15 h13))
x3 =1 (( h15 h13))
h10 h220.898
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m ((x1)) h16 +m x1 (( 1 x2)) h9 m x1 x2 h15
x2 =h16 h9h15 h9
0.89
m h21 +m x1 h18 m (( 1 x1)) h20
h21 =+x1 h18 (( 1 x1)) h20 1.088 106 m2
s2P21 P6
T21 250.46 C
Qrec hrsg cpgas mgas (( T5 T4)) m (( h6 h21)) hrsg %65
m =hrsg cpgas mgas (( T5 T4))
h6 h213.254
kgs
Q11_14_12 +m (( x1 x2)) h12 (( +m (( x1 x2 (( 1 x3)))) h14 m (( x1 x2 x3)) h11))
=Q11_14_12 5.286 106 W
Q78 =m ((x1)) (( h8 h7)) 7.157 105 W
Wth =m (( h7 h6)) 3.865 105 W
Wtl =m (( ++x1 (( h9 h8)) x1 x2 (( h10 h9)) x1 x2 x3 (( h11 h10)))) 2.658 106 W
Wc1 =m x1 x2 (( h13 h12)) 1.993 103 W
Wc2 =m x1 (( h17 h16)) 1.615 104 W
Wc3 =m (( 1 x1)) (( h20 h19)) 1.139 103 W
th =|||
++Wturb1 Wth Wtl+++++Qcal Q78 Wcomp1 Wc1 Wc2 Wc3
|||
0.483
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=T1 298.15 K =T11 314.65 K =T21 523.61 K=T2 540.083 K =T12 314.65 K =T22 372.75 K=T3 1.564 103 K =T13 314.67 K=T4 1.066 103 K =T14 314.65 K=T5 813.15 K =T15 372.75 K=T6 773.15 K =T16 443.556 K T17 171.069 C=T7 711.15 K =T17 444.219 K=T8 823.15 K =T18 523.5 K=T9 631.15 K =T19 523.5 K
=T10 440.15 K =T20 524.03 K T21 250.46 C
=h6 3.422 106 m2
s2=P1 1.2 105 Pa=P2 9.6 105 Pa
=h7 3.303 106 m2
s2=P3 9.6 105 Pa=P4 1.824 105 Pa
=h8 3.559 106 m2
s2=P5 1.824 105 Pa=P6 6 106 Pa
=h9 3.18 106 m2
s2=P7 4 106 Pa=P8 4 106 Pa
=h10 2.811 106 m2
s2=P9 8 105 Pa
=P10 1 105 Pa=h11 2.508 106 m
2
s2=P11 8 103 Pa=P12 8 103 Pa
=h12 1.738 105 m2
s2=P13 8 105 Pa=P14 8 103 Pa
=h13 1.746 105 m2
s2=P15 8 105 Pa=P16 8 105 Pa
=h14 4.175 105 m2
s2=P17 6 106 Pa=P18 6 106 Pa
=h15 4.18 105 m2
s2=P19 4 106 Pa=P20 6 106 Pa
=h16 7.209 105 m2
s2=P21 6 106 Pa=P22 1 105 Pa
=h17 7.266 105 m2
s2
=h18 1.087 106 m2
s2 =h20 1.09 106 m2
s2=h19 1.088 106 m2
s2 =h21 1.088 106 m2
s2
=h22 4.175 105 m2
s2