maximizar z
TRANSCRIPT
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8/18/2019 Maximizar Z
1/2
Maximizar Z= 4x1+3x2
Sujeto a 2x1+3x2≤ 60
-3x1+2x2≤ 30
2x1+ x2≤ 40
X1, X2 ≥ 0
Z= -4x1-3x2 = 0
2x1+3x2 +X1 = 60
-3x1+2x2 + X2 = 30
2x1+ x2 + X3 = 40
TABA S!M"#X
Z X1 X2 X1 X2 X3 $
1 -4 -3 0 0 0 0
0 2 3 1 0 0 60
0 -3 2 0 1 0 30
0 2 1 0 0 1 40
60%2 = 30
30% -3 = -10
40% 2 = 20
0 -3 2 0 1 0 30
% -3
=
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8/18/2019 Maximizar Z
2/2
0 1 -2%3 0 -1%3 0 -10
Z X1 X2 X1 X2 X3 $
0 1 -2%3 0 -1%3 0 -10
0 2 3 1 0 0 60
2 2 2 2 2 2 2
0 1 -2%3 0 -1%3 0 -10
0 0 -13%3 1 -2%3 0 -&0