filtros segundo orden
DESCRIPTION
filtros segundo ordenTRANSCRIPT
Juan Sebastian González Rondón
1016063483
Circuitos Eléctricos 3
FILTROS DE SEGUNDO ORDEN
PASA BAJOS PASIVOS
ᶔ=0.7
C=29μf
w0=√ 1LC
L= 1w0∗c
=2.8mH
R=2∗ᶔ∗L∗w0=13.65Ω
H (s )=(w0)
2
S2+RLS+(w0)
2
H (s )= (3483)2
S2+4876 S+(3483)2
XFG1
R1
13.65Ω
L12.8mH
C3
29µF
XBP1
IN OUT
ᶔ=1
C=29μf
w0=√ 1LC
L= 1w0∗c
=2.8mH
R=2∗ᶔ∗L∗w0=19.5Ω
H (s )=(w0)
2
S2+RLS+(w0)
2
H (s )= (3483)2
S2+7686S+(3483)2
H (s )=(w0)
2
S2+RLS+(w0)
2
H (s )= (3483)2
S2+11529 S+(3483)2
XFG1
R1
29.25Ω
L12.8mH
C3
29µF
XBP1
IN OUT
ᶔ=2
C=29μf
w0=√ 1LC
L= 1w0∗c
=2.8mH
R=2∗ᶔ∗L∗w0=39Ω
H (s )=(w0)
2
S2+RLS+(w0)
2
H (s )= (3483)2
S2+15372S+(3483)2
XFG1
R1
39Ω
L12.8mH
C3
29µF
XBP1
IN OUT
w0=√ 1LC
L= 1w0∗c
=2.8mH
R=2∗ᶔ∗L∗w0=19.5Ω
H (s )= (S )2
S2+RLS+(w0)
2
H (s )= (S)2
S2+7686S+(3483)2
XFG1
R1
19.5Ω
L12.8mH
C3
29µF
XBP1
IN OUT
ᶔ=1.5
C=29μf
w0=√ 1LC
L= 1w0∗c
=2.8mH
R=2∗ᶔ∗L∗w0=29.25Ω
H (s )= (S )2
S2+RLS+(w0)
2
H (s )= (S )2
S2+11529 S+(3483 )2
L= 1w0∗c
=2.8mH
R=2∗ᶔ∗L∗w0=39Ω
H (s )= (S )2
S2+RLS+(w0)
2
H (s )= (S)2
S2+15372S+(3483)2
XFG1
R1
39Ω
L12.8mH
C3
29µF
XBP1
IN OUT
PASA BANDA PASIVOS
ᶔ=0.7
C=29μf
w0=√ 1LC
L= 1w0∗c
=2.8mH
R=2∗ᶔ∗L∗w0=13.65Ω
H (s )=
RL∗S
S2+RLS+(w0)
2
H (s )= 4876 S
S2+4876 S+(3483)2
XFG1
R1
39Ω
L12.8mH
C3
29µF
XBP1
IN OUT
ᶔ=1
C=29μf
w0=√ 1LC
L= 1w0∗c
=2.8mH
R=2∗ᶔ∗L∗w0=19.5Ω
H (s )=
RL∗S
S2+RLS+(w0)
2
L= 1w0∗c
=2.8mH
R=2∗ᶔ∗L∗w0=29.25Ω
H (s )=
RL∗S
S2+RLS+(w0)
2
H (s )= 11529 S
S2+11529 S+(3483)2
XFG1
R1
29.25Ω
L12.8mH
C3
29µF
XBP1
IN OUT
ᶔ=0.7
C=29μf
w0=√ 1LC
L= 1w0∗c
=2.8mH
R=2∗ᶔ∗L∗w0=13.65Ω
H (s )=S2+ (w¿¿0)2
S2+RLS+(w0)
2¿
H (s )= S2+(3483)2
S2+4876 S+(3483)2
XFG1
R1
13.65Ω
L12.8mH
C3
29µF
XBP1
IN OUT
H (s )=S2+ (w¿¿0)2
S2+RLS+(w0)
2¿
H (s )= S2+(3483)2
S2+7686S+(3483)2
XFG1
R1
19.5Ω
L12.8mH
C3
29µF
XBP1
IN OUT
ᶔ=1.5
C=29μf
w0=√ 1LC
L= 1w0∗c
=2.8mH
R=2∗ᶔ∗L∗w0=29.25Ω
H (s )=S2+ (w¿¿0)2
S2+RLS+(w0)
2¿
H (s )= S2+(3483)2
S2+11529 S+(3483)2
XFG1
R1
29.25Ω
L12.8mH
C3
29µF
XBP1
IN OUT
H (s )=S2+ (w¿¿0)2
S2+RLS+(w0)
2¿
H (s )= S2+(3483)2
S2+15372S+(3483)2
XFG1
R1
39Ω
L12.8mH
C3
29µF
XBP1
IN OUT
PASA BAJOS ACTIVOS
ᶔ=0.7
R=10Ω
C= 1R∗w0
C= 110∗3483
=29 μf
A=3−2 ᶔ
A=1.6
H (s )=(w0)
2
S2+2 ᶔ w0S+(w0)2
H (s )= (3483)2
S2+4876 S+(3483)2
R5= (A−1 ) R=6
R2
10Ω
R3
10Ω
R410Ω
R5
6Ω
C1
290µF
C2290µF
XFG2
U1
OPAMP_5T_VIRTUAL
VCC5V
ᶔ=1
R=10Ω
C= 1R∗w0
C= 110∗3483
=29 μf
A=3−2 ᶔ
A=1
H (s )=(w0)
2
S2+2 ᶔ w0S+(w0)2
H (s )= (3483)2
S2+7686S+(3483)2
R5= (A−1 ) R=0
C= 1R∗w0
C= 110∗3483
=29 μf
A=3−2 ᶔ
A=0
H (s )=(w0)
2
S2+2 ᶔ w0S+(w0)2
H (s )= (3483)2
S2+11529 S+(3483)2
R5= (A−1 ) R=−10
R2
10Ω
R3
10Ω
R410Ω
R5
-10Ω
C1
290µF
C2290µF
XFG2
U1
OPAMP_5T_VIRTUAL
VCC5V
ᶔ=2
R=10Ω
C= 1R∗w0
C= 110∗3483
=29 μf
A=3−2 ᶔ
A=−1
H (s )=(w0)
2
S2+2 ᶔ w0S+(w0)2
H (s )= (3483)2
S2+15372S+(3483)2
PASA ALTAS ACTIVOS
ᶔ=0.7
R=10Ω
C= 1R∗w0
C= 110∗3483
=29 μf
A=3−2 ᶔ
A=1.6
H (s )= S2
S2+2 ᶔ w0S+(w0)2
H (s )= S2
S2+4876 S+(3483)2
R5= (A−1 ) R=6
ᶔ=1
R=10Ω
C= 1R∗w0
C= 110∗3483
=29 μf
A=3−2 ᶔ
A=1
H (s )= S2
S2+2 ᶔ w0S+(w0)2
H (s )= S2
S2+7686S+(3483)2
R5= (A−1 ) R=10
R210Ω
R410Ω
R5
10Ω
C1
290µF
C2
290µF
XFG2
U1
OPAMP_5T_VIRTUAL
VCC5V
R3
10Ω
A=0
H (s )= S2
S2+2 ᶔ w0S+(w0)2
H (s )= S2
S2+11529 S+(3483)2
R5= (A−1 ) R=−10
R210Ω
R410Ω
R5
-10Ω
C1
290µF
C2
290µF
XFG2
U1
OPAMP_5T_VIRTUAL
VCC5V
R3
10Ω
H (s )= S2
S2+2 ᶔ w0S+(w0)2
H (s )= S2
S2+15372S+(3483)2
R5= (A−1 ) R=−20
R210Ω
R410Ω
R5
-20Ω
C1
290µF
C2
290µF
XFG2
U1
OPAMP_5T_VIRTUAL
VCC5V
R3
10Ω
H (s )=2 ᶔ w0∗S
2
S2+2 ᶔ w0S+(w0)2
H (s )= 4876∗S2
S2+4876 S+(3483)2
R5= (A−1 ) R=6
ᶔ=1
R=10Ω
C= 1R∗w0
C= 110∗3483
=29 μf
A=3−2 ᶔ
A=1
H (s )=2 ᶔ w0∗S
2
S2+2 ᶔ w0S+(w0)2
H (s )= 7686∗S2
S2+7686S+(3483)2
R5= (A−1 ) R=0
ᶔ=1.5
R=10Ω
C= 1R∗w0
C= 110∗3483
=29 μf
A=3−2 ᶔ
A=−1
H (s )=2 ᶔ w0∗S
2
S2+2 ᶔ w0S+(w0)2
H (s )= 11529∗S2
S2+11529 S+(3483)2
R5= (A−1 ) R=−10
ᶔ=2
R=10Ω
C= 1R∗w0
C= 110∗3483
=29 μf
A=3−2 ᶔ
A=−2
H (s )=2 ᶔ w0∗S
2
S2+2 ᶔ w0S+(w0)2
H (s )= 11529∗S2
S2+11529 S+(3483)2
R5= (A−1 ) R=−20
RECHAZABANDA
ᶔ=0.7
R=10Ω
C= 1R∗w0
C= 110∗3483
=29 μf
A=3−2 ᶔ
A=1.6
H (s )=S2+w0
2
S2+2 ᶔ w0S+(w0)2
H (s )= S2+34832
S2+4876 S+(3483)2
R5= (A−1 ) R=6
H (s )= S2+34832
S2+7686S+(3483)2
R5= (A−1 ) R=0
ᶔ=1.5
R=10Ω
C= 1R∗w0
C= 110∗3483
=29 μf
A=3−2 ᶔ
A=0
H (s )=S2+w0
2
S2+2 ᶔ w0S+(w0)2
H (s )= S2+34832
S2+11529 S+(3483)2
R5= (A−1 ) R=−10
ᶔ=2
R=10Ω
C= 1R∗w0
C= 110∗3483
=29 μf