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7/25/2019 RelacionY
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"Calcular la relacion y/D de un colector de 300 mm, que conduce 5o lt/seg a unapendiente de 3.5 o/00
SolucionDatosD = 300 mm = 0.3 mQ = 50 lt/ segS = 3.5 = 0.0035
Q0 = 0.3115 (1/n) (D)^8/3 (S)^1/2Q0 = 0.3115 (1/0.013) (0.3)^8/3 (0.0035)^1/2Q0 = 0.05717 m3/segQ0 = 57.17 lt / seg
Con la relacion
q/Q0 =q/Q0 = 50 / 57.17q/Q0 = 0.87
Hallamos con la tabla
v/v0 = 1,125y/D = 0.72
V0 = (0.397 (D)^2/3 (S)^1/2) / nV0 = (0.397 (0.3)^2/3 (0.0035)^1/2) / 0.013V0 = 0.72 m/s
Hallamos la Velocidad real
V = v/v0 * v0V = 1.125 * 0.72V = 0.82 m/s
Hallamos Rh
Rh = ((V * n) / (S^1/2))^3/2Rh = (0.82 * 0.013 / 0.0035 ^1/2) ^3/2Rh = 0.076"