Tarea 3

Fermin Rodriguez

Calculo 3C_SU_2015, Codigo: IBI-101, Grupo:1

1-dydx

=2x (3 x3−2 )+9 x2 ( x2+2 )=x (15 x3+18 x−4 )

2-dydx

=(5 x2+2 ) (6 x−2 )+10 x (3 x2−2x+7 )=60 x3−30 x2+82x−4

3- dydx

=(x2−2 )2

2√x+1+4 x√ x+1 (x2−2 )= (x2−2 ) (9 x2+8x−2 )

2√ x+1

4-dydx

=2x3√ x2+3+ 2 x3

3 (x2+3 )23

= 8x3+18 x3 (x2+3)2 /3

5-dydx

=2x (x4−1 )+4 x3 (x2+1 )=6 x5+4 x3−2x

6-dydx

=3 (3 x−2 )(5−3 x )2

+ 35−3 x

= 9

(3 x−5 )2

7- dydx

= 23 x2+2

−6x (2 x+√3 )

(3 x2+2 )2=2(3 x2+3

32 x−2)

(3 x2+2 )2

8-dydx

= 9 x2

x2+3−2x (3 x3−2 )

( x2+3 )2=x (3 x3+27 x+4 )

(x2+3 )2

9-dydx

=3 (2 x2−3 x+3 )

(2−3x )2+ 4 x−32−3 x

=−6 x2−8 x−3(3 x−2 )2

10-dydx

= 2 x+3x2+2 x−3

−(2x+2 ) (x2+3 x−1 )

(x2+2x−3 )2=−x2+4 x+7

(x2+2 x−3 )2

11-dydx

=−4 sinx−2cosx=−2(2 sinx+cosx)

12-dydx

=−2cosxsinx

13-dydx

=2x ¿

14-dydx

=tcos ( t )−sen ( t )

t 2

15-dydx

=cos (2 x )