diseño elementos

7/24/2019 Diseo Elementos

1/2

SOLUCIN A LOSPROBLEMAS PLANTEADOS

Solucin del problema: 14-1

d = = = 3.667 pulg Clculos:

d =12

= 1.333 pulg, Y = 0.296

= 244.3 pies/min

7/24/2019 Diseo Elementos

2/2

N 22

P 6

Y = 0.331

dn (3.667)V = = 1152 pies/min=

12 12

1200 + 1152Kv =

Wt

=

= 1.961200

T 63 025 63 025(15)= 429.7 lbf= =

d /2 nd /2 1200(3.667/2)

Esfue!o po fle"i#n:

Kv Wt 1.96(429.7)(6)

= = 7633 psi = 7.63 $psi=FY 2(0.331)

16

(1.333)V =

Kv =

12

1200 + 244.3

Clculos:

= 1.2041200

63 025H 63 025(1.5)W

t= = 202.6 lbf=

nd /2 700(1.333/2)

Esfue!o po fle"i#n:

Kv WtP 1.204(202.6)(12)

= 13 1%5 psi = 13.2 $psi = =FY 0.75(0.296

d = mN = 1.25(1%) = 22.5 mm, Y = 0.309

(22.

5)(103)V =

Kv =

Wt

=

= 2.121 m/s60

6.1 + 2.121

Clculos:

= 1.34%

60(0.5)(103)

6.1

60H=235.% &=

dn (22.5)(103)

Kv W 1.34%(235.%)

Esfue!o po fle"i#n:

FmY=

12(1.25)(0.309)= 6%.6 ' =

d = 5(15) = 75 mm, Y = 0.290

(75)(103)V = = 0.7%54 m/s

60

Clculos:

6.1 + 0.7%54Kv = = 1.129

6.1

60(5)(103)60W

t= = 6366 &=

dn (75)(103)(200)

Kv Wt 1.129(6366)

FmY=

60(5)(0.290)= %2.6 ' =

d = 1(16) = 16 mm, Y = 0.296

(16)(103)V = = 0.335 m/s

60

6.1 + 0.335Kv = = 1.055

6.1

60H 60(0.15)W

t= =447.6 &=

dn (16)(103)(400)

Kv W 1.

055(447.

6)F = =

150(1)(0.296)= 10.6 mm

mY

*e +bls usmos un nco -e c igul :11 mm

d = 1.5(17) = 25.5 mm, Y = 0.303

(25.5)(103)V = = 0.534 m/s

60

6.1 + 0.534Kv = = 1.0%%

6.1

60H 60(0.25)W

t= = 46% &=

dn (25.5)(103)

Kv W 1.0%%(46%)F =

mY=

75(1.5)(0.303)= 14.9 mm

24d = = 4.% pulg, Y = 0.337

5

(4.%)V = = 62.%3 pies/min

12

1200 + 62.%3Kv = = 1.052

1200

63 025H 63 025(6)W

t= = 3151 lbf=

nd /2

Kv WtP

50(4.%/2)

1.052(3151)(5)F = = 2.46 pulg=

20(103) Y

16d = = 3.2 pulg, Y = 0.296

5

(3.2)V = = 502.7 pies/min

12

1200 + 502.7Kv = = 1.419

1200

63 025(15)W

t= = 9%4.% lbf

600(3.2/2)

Kv WtP 1

.419(9%4

.%)(5)

F = = 2.3% pulg= Y 10(103)

Con:P = % lo .ue nos -: d = 1%/% = 2.25 pulg Y = 0.309.

(2.25)V = = 353.4 pies/min

12

1200 + 353.4E. (144b): Kv = = 1.295

1200

63 025(2.5)W

t= = 233.4 lbf

600(2.25/2)

Kv WtP 1.295(233.4)(%)

E. (147): F = = 0.7%3 pulg=10(103) Y

+s consi-eciones .ui!s -en l siguien+e selecci#n.Es+ssen:P = % (F = 7/% pulg) P = 10 (F = 1.25 pulg).

obn-o con: m = 2 mm lo .ue -: -= 2(1%) = 36 mm Y = 0.309.

(36)(10

3)V = = 1.696 m/s60

6.1 + 1.696

Clculos:

Kv =

Wt

=

= 1.27%6.1

60(1.5)(103)= %%4 &

(36)(103)

1.27%(%%4) o lo +n+o: F =

75(2)(0.309)= 24.4 mm

sn-o los m#-ulos efei-os en +bl con o+s consi-eciones -e -iseo

.ui!s -ign .ue el +mo -e selecci#n p el pesen -iseo es m = 2 mm (F = 25 mm) es+ es un buen selecci#n

22 60dP = = 3.667 pulg, dG = = 10 pulg

6

(3.667)

6

V = = 1152 pie/min12

1200 + 1152

Clculos:

Kv= =

1.961200

63 025(15)W

t= = 429.7 lbf

1200(3.667/2)

Cp = 2100

psi *e +bls:

3.667 sin 20 10 sin 20 uego: r1 = = 0.627 pulg, r2 = = 1.710 pulg

2 2

11/2

Kv WC = Cp +

rF cos r1 2

1/2

1C= 2100

0.627+

1.7102 cos 20

C= 65.6(103) psi = 65.6 $psi

16 4%d P =

12= 1.333 pulg, dG =

12= 4 pulg

(1.333)V = = 244.3 pies/min

121200 + 244.3

Kv =

Wt

=

= 1.2041200

63 025(1.5)= 202.6 lbf

700(1.333/2)

Cp = 2100

psi

1.333 sin 20 4 sin 20r1 = = 0.22% pulg, r2 = = 0.6%4 pulg

2 2

1/2

1 3C = 2100 = 100(10 )0.22%

+0.6%4F cos 20

21002

1.202(202.6) 1

1F = = 0.66% pulg

0.22%+

0.6%4100(103

)cos 20

24 4%dP = = 4.% pulg, dG = = 9.6 pulg

5

(4.%)

5

V = = 62.%3 pies/min12

600 + 62.%3Kv =

Wt

=

= 1.105600

63 025= 525.2H

50(4.%/2)

Cp = 1960

psi

4.% sinr1 = = 0.%21 pulg, r2 = 2r1 = 1.642 pulg

2 1/2

1100(10

3) = 1960 +

2.5 cos 0.%21

H = 577 p













Esfue!o po fle"i#n:

Clculos:

smos un nco -e c igul :15 mm

Clculos:

smos un nco -e c igul :25 pulg

Clculos:

smos un nco -e c igul :25 pulg

Clculos:

Clculos:

Clculos:

uego:

smos un nco -e c igul :0 75 pulg

diseño elementos

Documents