d) Determinar la deflexión en el centro del tramo 4-5

Empleando el método de Castigliano:

M 4a=(28.357+Q2 )X−40.81−2.5 X 2→∂M∂Q

=X /2

Mab=(28.357+Q2 )X−40.81−2.5 X 2−5(x−3)→∂M∂Q

=X /2

M 5 c=(26.643+Q2 )X−33.100−2.5 X2→ ∂M∂Q

=X /2

M cb=(26.643+Q2 )X−33.100−2.5 X2−5(x−3)→∂M∂Q

=X /2

δb=δcl (45 )= 13.24 EI

∫0

3 (28.357 X−40.81−2.5 X2 ) Xdx2

+ 13.24 EI

∫3

4.5 (28.357 X−40.81−2.5 X2−5 ( x−3 )) Xdx2dx

+¿ 13.24 EI

∫0

3 (26.643 X−33.100−2.5 X2 ) Xdx2

+ 13.24 EI

∫3

4.5 (26.643 X−33.100−2.5 X2−5 ( x−3 ) ) Xdx2

+¿¿¿

δb=δcl (45 )=56.28212/EI ↓