Nombre: Helmut Albrecht Villarroel.

Sección: 79.

Guía de ejercicios: cálculos de concentración.

2. Calcule los valores q faltan en el siguiente cuadro:

masa inicial (mg) masa final (mg) tiempo flujo concentración (mg/m3)13,561 13,894 1,8 hrs 1702 cc/min 1,81210,589 12,478 234,077min 1962 cc/min 4,11511,265 11,369 78 min 0,001591m3 /min 0,83812,845 14,214 385 min 1720 cc/min 2,05417,951 18,258 167,76min 1008 cc/min 1,81314,632 15,478 250 min 0.00169m3/min 1,99315,915 18,364 4,8 hrs 2,092 l/min 4,06113,211 14,024 1,5 hrs 1629 cc/min 5,545

1.- mi=13,561mg , mf=x , t ∆=1,8h , Q x=1702cc /min , C=1,812mg /m3

C= ∆m

Qx x∆ t(Qx x ∆ t xC)+mi=mf

(0,001702m3/min x108min x1,812mg /m3)+13,561mg=mf

(0,184m3 x1,812mg /m3)+13,561mg=mf

0,333408mg+13,561mg=

13,894m g

2.-mi=10,589mg , mf=12,478mg , t ∆=x , Q x=1962cc /min , C=4,115mg /m3.

C= m∆

Qx x t ∆=t ∆= m∆

Q x xC=¿

m∆=12,478mg−10,589mg=1,889mg

Q x=1962cc /min= 1m3

1000000cc=0,001962m3 /mi n

t ∆= 1,889mg

0,001962m3/minx 4,115mg /m3=¿

t ∆= 1,889mg0,00807mg /min

t ∆=234,077min

3.- mi=11,265mg , mf=11,369mg , t ∆=78min , Q x=x , C=0 ,838mg /m3.

C= m∆

Qx x t ∆=Q x= m∆

t ∆ xC

m∆=11,369mg−11,265mg=1,889mg

m∆=0,104mg

Q x= 0,104mg78min x 0,838mg/m3

=¿

Q x= 0,10465,364m3/min

=¿

Q x=0,001591m3/min

4.-mi=11,265mg , mf=11,369mg , t ∆=78min , Q x=x , C=0,838mg /m3.

C= m∆

Qx x t ∆=( t ∆ xC xQ x)−mf=−mi

Q x=1720cc /min= 1m3

1000000cc=0,00172m3/min

(0,00172m3/min x385min x2,054mg /m3)−14,214mg=−m i

(0,1622m3 x 2,054mg /m3)−14,214mg=−mi

1,360mg−14,214mg=−mi

−12,845mg=−mi/ x−1

12,845mg=mi

5.- mi=17,951mg , mf=18,258mg , t ∆=x , Q x=1008cc /min , C=1,813mg /m3.

C= m∆

Qx x t ∆=t ∆= m∆

Q x xC=¿

m∆=18,258mg−17,951mg=0,307mg

Q x=1008cc /min= 1m3

1000000cc=0,001008m3/min

t ∆= 0,307mg

0,001008mg /min x1,813mg /m3=¿

t ∆= 0,3070.00183min

=167,76min

6.- mi=14,632mg , mf=15,478mg , t ∆=250min , Q x=x , C=1,993mg /m3.

C= m∆

Qx x t ∆=Q x= m∆

t ∆ xC

m∆=15,478mg−14,632mg=0,846mg

Q x= 0,846mg250minx 1,993mg /m3

=¿

Q x= 0,846498,25m3/min

=¿

Q x=0.00169m3/min

7.- mi=15,915mg ,mf=18,364mg, t ∆=4,8min , Q x=2,092L /min, C=x

C= m∆

Qx x t ∆=¿

m∆=18,364mg−15,915mg=2,449mg

t ∆=4,8h=60min1h

=288min

Q x=2,092L /min= 1m3

1000L=0.00209m3/min

C= 2,449

0,00209m3 /minx 288min=¿

C=2,449mg0,603m3

=¿

C=4,061mg /m3

8.- mi=13,211mg , mf=x , t ∆=1,5h , Q x=1629cc /min , C=5,545mg /m3

C= ∆m

Qx x∆ t(Qx x ∆ t xC)+mi=mf

t ∆=1,5h=60min1h

=90min

Q x=2,092cc /min= 1m3

1000000cc=0.00163m3/min

(0,00163m3/min x90min x 5,545mg /m3)+13,211mg=mf

(0,147m3 x5,545mg /m3)+13,211mg=mf

0,813mg+13,211mg=mf

14,024mg=mf