ecuaciones un tanto complicadas
Post on 05-Jul-2015
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4√97− x+ 4
√x = 5 (1)
x
(6− x
x+ 1
)(6− x
x+ 1+ x
)= 8 (2)
y3 − 6x2 + 12x− 8 = 0z3 − 6y2 + 12y − 8 = 0x3 − 6z2 + 12z − 8 = 0
(3)
x2 − xy + y2 = 7x2y + xy2 = −2
}(4)
3x2−x−y + 3y
2−y−z + 3z2−z−x = 1 (5)
4√6561 · 12
√x = 6x (6)
√a−
√a+ x = x (7)
x2 + 2ax+1
16= −a+
√a2 + x− 1
16(8)
x4 − 6x2y2 + y4 = 14x3y − 4xy3 = 1
}(9)
x+ y + z = ax2 + y2 + z2 = b
xy = z2
(10)
x2 + y = 3x+ 42y3 + z = 6y + 62z3 + x = 9z + 8
(11)
Demuestra que:
3
√20 + 14
√2 +
3
√20− 14
√2 = 4 (12)
log5 x+ 3log3y = 7xy = 512
}(13)
xx+y = yx−y
x2y = 1
}(14)
√19− x+
√97 + x = 14 (15)
1
2x− 1+
1
2x+ 1+
1
4x2 − 1= 1 (16)
x(x+ y + z) = 26y(x+ y + z) = 27z(x+ y + z) = 28
(17)
2x(4− x) = 2x+ 4 (18)
x2 +√
y2 + 12 =√y2 + 60
y2 +√z2 + 12 =
√z2 + 60
z2 +√x2 + 12 =
√x2 + 60
(19)
y3 − 6x2 + 12x− 8 = 0z3 − 6y2 + 12y − 8 = 0x3 − 6z2 + 12z − 8 = 0
(20)
log(35− x3)
log(5− x)= lım
n→∞ln
(n+ 4
n+ 1
)n
(21)
√3x− 2y
2x+
√2x
3x− 2y= 2
4y2 − 1 = 3y(x− 1)
(22)
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