4 unidad fenomenos
DESCRIPTION
asdfasTRANSCRIPT
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W= 4500 kg/hrCP= 0.6 Kcal/(kg °C)tb1= 40 °Ctb2= 95 °CD= 2.5 cm = 0.025espesor= 0.16 cm = 0.0016L= 90 m = 9000
To= 100.6 °C
Q= 2700 * 55 =
60.6
33.1 (To1-Tb1)-(To2-Tb2)60.6 5.6 =
23.0944138
vapor sat. A 1.02 atm
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H1= 346.674133 kcal/(hrm2°C)
Ha= 634.69645 kcal/(hrm2°C)
Hln= 909.676801 kcal/(hrm2°C)
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mmcm
148500 kcal/Hr
55
= 7.06858347 m2
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6.16
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P= 1 atm WB= 0Taire= A 60 °CT superfi=B 21 °CV= 215 cm/sdensidad = 1Pvapor a 21°C= 0.0245D= 0.05 cmR= 0.025 cmvol= 4/3 pi*R^3 6.5450E-005moles= m/pm*V*L*densidad
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Xa0= 0.0245 = 6.98Cpf 6.98 38.0445 10500Delta H 10500 =Scf 0.58 0.00056511Pr 0.74R 1.987Tinft 60 °CTo 21 °C 1.25Pr= cp/(Cp+5/4R) 0.73755118Xainft 0.00300
v
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0.8500885840.5
39T=60+21/260-21
10500
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x y x2xg
0 0 0 yg0.05 0.022 0.0025
0.1 0.052 0.01 1.037857140.15 0.087 0.0225
0.2 0.131 0.04 y=mx+b0.25 0.187 0.0625 m
0.3 0.265 0.09 xal,yal0.35 0.385 0.1225 b=yag-mxal
y=mx+by=b0+b1x+bx^2a+b+cx^2=mx+b
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10.1
0.38
y=b0+b1x+bx^2a+b+cx^2=mx+b