10l - practica pdp (solucionario)
TRANSCRIPT
7/26/2019 10l - Practica Pdp (Solucionario)
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MANGOS
CASCAS PACASMAYO VIRU ASCOPE
Javas Veces Probabilidad Javas Veces Probabilidad Javas Veces Probabilidad Javas Veces Probabilidad
1 15 0.3 1 13 0.26 1 8 0.16 1 8 0.16
2 13 0.26 2 16 0.32 2 12 0.24 2 9 0.18
3 12 0.24 3 10 0.2 3 11 0.22 3 9 0.18
4 10 0.2 4 11 0.22 4 8 0.16 4 11 0.22
5 11 0.22 5 13 0.26
x:javas enviadas enviadas (no necesariaen!e e" c"ien!e "as !oar# !odas$x %AS%AS &A%ASMA'O )*+ AS%O&, &recio java 50 so"es-java
1 101.28 102.96 130.68 139.08 ,nvo nora" 5 so"es-java
2 99./8 102.06 131.28 139.68 ,nvo ren!e 8 so"es-java
3 94.38 96.36 128.28 13/.58 *e!orno / so"es-java
4 85.38 8/.66 121.98 132./8 ava adiciona" 35 so"es-java
5 113.28 124.68
AS%O&,
Solución óptima
1 2 3 4 5
1 139.08 61.28 59.18 54.38 46.28 139.08 1
2 139.08 139.68 88.58 83./8 /5.68 139.68 2
3 139.08 139.68 13/.58 106.88 98./8 139.68 2
4 139.08 139.68 13/.58 132./8 115.58 139.68 2
5 139.08 139.68 13/.58 132./8 124.68 139.68 2
6 139.08 139.68 13/.58 132./8 124.68 139.68 2
/ 139.08 139.68 13/.58 132./8 124.68 139.68 2
8 139.08 139.68 13/.58 132./8 124.68 139.68 2
9 139.08 139.68 13/.58 132./8 124.68 139.68 2
10 139.08 139.68 13/.58 132./8 124.68 139.68 2
11 139.08 139.68 13/.58 132./8 124.68 139.68 2
)*+
Solución óptima
1 2 3 4 5
6 130.68 131.28 128.28 121.98 113.28 131.28 2
/ 130.68 131.28 128.28 121.98 113.28 131.28 2
8 130.68 131.28 128.28 121.98 113.28 131.28 2
9 130.68 131.28 128.28 121.98 113.28 131.28 2
1 130.68 131.28 128.28 121.98 113.28 131.28 2
11 130.68 131.28 128.28 121.98 113.28 131.28 2
12 130.68 131.28 128.28 121.98 113.28 131.28 2
&A%ASMA'O
Solución óptima
1 2 3 4
10 102.96 102.06 96.36 8/.66 102.96 1
11 102.96 102.06 96.36 8/.66 102.96 112 102.96 102.06 96.36 8/.66 102.96 1
13 102.96 102.06 96.36 8/.66 102.96 1
%AS%AS
Solución óptima
1 2 3 4
14 101.28 99./8 94.38 85.38 101.28 1
Tabla de beneficios esperados i n(x)
s4
Max f(s4,x
4 ) = i(x
4 )
4
x4
s3
Max f(s3,x
3 ) = i(x
3 ) + f
4*(s
3-x
3 )
3
x3
s2
Max f(s2,x
2 ) = i(x
2 ) + f
3*(s
2-x
2 )
2
x2
s1
Max f(s1,x
1 ) = i(x
1 ) + f
2*(s
1-x
1 )
1
x1
Se reca"c"a e" inresoeserado considerando "as javas de S-.35 coo ar!ede" c#"c"o.